Give an example of a real-world situation that could be represented by an algebraic expression

Answer:x=4

Isolate the variable by dividing each side by factors that don't contain the variable.

Answer:

83/100

Step-by-step explanation:

step 1- Address input parameters & values.

Input parameters & values: The decimal number = 0.83

step 2- Write it as a fraction

0.83/1

step 3- Multiply 100 to both numerator & denominator

(0.83 x 100)/(1 x 100) = 83/100

It can be written as 83% = 83/100 or 83/100

step 4- To simplify 83/100 to its lowest terms, find LCM (Least Common Multiple) for 83 & 100.

1 is the LCM for 83 & 100

step 5- As LCM is 1, the fraction can't be factorized further

83/100 is a simplest fraction for the decimal point number 0.83

*hope this helped <3*

Answer:

It is 83/100.

Step-by-step explanation:

1. Notice the decimal numbers. They end in the hundredths place.

2. After acknowledging this you know by this that it will be the decimal over 100, like ??/100.

3. Since the decimal is 0.83, we know that it will be 83 over 100. Solved for 83/100.

Answer:

A = 62.5

Step-by-step explanation:

I would break this up into two easier cases. the square at the top where three vertices are A,B, and C. and then the triangle for the rest of the area. we can use the distance formula to find the side length of the square.

sqrt((y2-y1)^2 + (x2-x1)^2)

sqrt((5-2)^2 + (-1-3)^2)

sqrt(3^2 + (-4)^2)

sqrt(9 + 16)

sqrt ( 25)

5

so the area of the square is 5^2 =25

now for the triangle. the formula for the area of a triangle is (1/2)bh.

so we can plug in our b=5, but we need to find h.

we use the distance formula between point A and D to find the distance to be 20, but we have to subtract the 5 we already counted in the area of the square. so the height is 15.

so The triangle has area (1/2)×5×15

37.5.

add the two areas together and we get our answer

25+37.5 = 62.5