PLEASEEE HELP. Solve x^3-7x^2+6x-42=0

Answers

Answer 1

Answer: factor by grouping

x^2(x-7) + 6(x-7) = 0 [took x^2 out of the first two and a 6 out of the last two]
(x-7)(x^2+6) = 0 [moved (x-7) out to the front]
x = -i sqrt(6) , i sqrt(6) , 7

only one real solution of x = 7

Answer 2

Answer: $x^(3) -7 x^(2) +6x-42=0$

$(x-7)$ is a factor since it is a factor of -42 and 7 is a solution for f(x) to equal 0.

$(x-7)(a x^(2) +bx+c)=0$

$(x-7)( x^(2) +bx+6)=0$

$-7 x^(2) +b x^(2) =-7 x^(2)$

$-7+b=-7$

$b=0$

$(x-7)( x^(2) +6)=0$

$x-7=0$

$x^(2) +6=0$

$x=7$ (only solution because you can't square root (-6))

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Answers

Answer:

Step-by-step explanation:

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Answers

Answer:

54 m^3

Step-by-step explanation:

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Answers

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Answers

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Answers

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