CHEMISTRY HIGH SCHOOL

Calculate the molarity (M) of 1.5 L solution of todium nitrate (NaNO3) containing 61.2 g of NaNO3

Answers

Answer 1
Answer:

Answer:

\huge\boxed{\sf Molarity = 0.48\ M}

Explanation:

Given data:

Volume of solution = 1.5 L

Mass of solute = 61.2 g

Molar mass of solute:

= 23 + 14 + (16 × 3)

= 23 + 14 + 48

= 85 g/mol

Required:

Molarity = ?

Formula:

Molarity = no. of moles of solute / volume

Solution:

First, we have to find moles of solute.

We know that,

Moles = mass / molar mass

Moles = 61.2 / 85

Moles = 0.72 moles

Now, finding molarity:

Molarity = 0.72 / 1.5

Molarity = 0.48 M

\rule[225]{225}{2}
Answer 2
Answer:

The molarity of the 1.5 L solution of sodium nitrate containing 61.2 g of NaNO3 is approximately **0.480 M**

To calculate the molarity (M) of a solution, you can use the formula:

\[ \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{volume of solution (L)}} \]

- Volume of solution (\( V \)) = 1.5 L

- Mass of sodium nitrate = 61.2 g

- Molar mass of sodium nitrate = 85 g/mol (Na: 23 g/mol, N: 14 g/mol, O: 16 g/mol)

First, calculate the moles of sodium nitrate using its molar mass:

\[ \text{Moles of } \text{NaNO}_3 = \frac{\text{Mass}}{\text{Molar mass}} = \frac{61.2 \, \text{g}}{85 \, \text{g/mol}} \approx 0.720 \, \text{mol} \]

Now, substitute the values into the molarity formula:

\[ \text{Molarity (M)} = \frac{0.720 \, \text{mol}}{1.5 \, \text{L}} \]Calculate:\[ \text{Molarity (M)} \approx 0.480 \, \text{M} \]

So, the molarity of the 1.5 L solution of sodium nitrate containing 61.2 g of NaNO3 is approximately **0.480 M**.

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The universe is mostly made up of what?

Answers

the universe is made mostly of empty space nothing else even close.

What does it mean that valence electrons in a metal are delocalized?

Answers

Delocalized means that electrons in the metal are not linked only to a single atom or in a bond. Electrons are free to move and around the crystal structure and carry currents. This is why, in metals, there is a term "electron sea".

Answer:

A

Explanation:

The density of aluminum is 2.70 g/cm3. What is the mass of 235 cm3 of aluminum? 634.5 g
635 g
635 g/cm3
634.5 ml

Answers

Answer:

JUST B

Explanation:

Final answer:

The mass of 235 cm³ of aluminum, which has a density of 2.70 g/cm³, is calculated to be 634.5 g using the formula Mass = Density × Volume.

Explanation:

To find the mass of a given volume of a substance, you can use the formula: Mass = Density × Volume. In this case, the density of aluminum is given as 2.70 g/cm³ and you need to find the mass of 235 cm³ of aluminum.

Substitute the given values into the formula:

Mass = 2.70 g/cm³ × 235 cm³ = 634.5 g

Therefore, the mass of 235 cm³ of aluminum is 634.5 g.

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Answers

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Answer:

D. An ancient Stone Temple

Explanation:

Edg 2021

Under which conditions of temperature and pressure does a sample of neon behave most like an ideal gas?(1) 100 K and 0.25 atm
(2) 100 K and 25 atm
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(4) 400 K and 25 atm

Answers

Answer : The correct option is, (3) 400 K and 0.25 atm

Explanation :

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Ideal gas are those gas that have negligible volume.

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PV=nRT

The conditions for real gas are :

Real gas are those gas that have intermolecular attractions.

Real gas are those gas that have volume.

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From the given options, option (3) have high temperature and low pressure is the correct option.

Hence, the 400 K and 0.25 atm conditions of temperature and pressure does a sample of neon behave most like an ideal gas.
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 Therefore, (3) 400K and 0.25 atm is the correct answer.
Hope this would help~

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Answers

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The correct answer is A.syrup

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