What is the common angle of triangle PQT and triangle RSQ? Can someone explain this for me ?

Answers

Answer 1

Answer: The angle on the lines sq and tq

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Quadrilateral with 2 pairs of equal sides and 2 pairs of opposite angles that are equal is ________

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Answer: Parallelogram.
Explanation: A simple quadrilateral with two pairs of equal opposite angles is a parallelogram. (Because then the opposite sides are parallel.) A simple quadrilateral with two pairs of equal opposite sides is a parallelogram.

Solve this problem using estimation.The Cimarron Middle School orchestra sold $8720.00 worth of candy bars in 28 days. About how much did they make each day?

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If they sold $8,720.00 worth of candy bars in just 28 days, that means they have approximately sold $311.43 worth of candy bars each day.

Find the seventh term of the expansion of (-3x-2y)^11

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Answer:

The answer is A

Step-by-step explanation:

I hope this helps you

Determine if the side lengths 12, 13, and 13 form a triangle. If it is a triangle, classify it by its sides.It's not a triangle.
scalene triangle
isosceles triangle
equilateral triangle

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it would be isosceles, since two of the sides are equal. if none of the sides were equal, it would be scalene, and if all of the sides were equal, it would be equilateral.

How do I solve this?

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Work is attached..

:D

Solve the equation 36x^2 25=0

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The equation 36x^2 + 25 = 0 possesses no real solutions; however, it yields two complex roots: x = (5/6)i and x = -(5/6)i.

The equation provided, 36x^2 + 25 = 0, is a quadratic equation in one variable, x. To solve it, we'll first isolate the x^2 term:

36x^2 = -25

Next, we'll divide both sides by 36:

x^2 = -25/36

Taking the square root of both sides, we get:

x = ±√(-25/36)

Since the square root of a negative number is imaginary, there are no real solutions to this equation. This means that the equation 36x^2 + 25 = 0 has no real roots, but it does have complex roots in the form of x = ±(5/6)i, where i is the imaginary unit.

The equation 36x^2 + 25 = 0 has no real solutions, but it does have two complex solutions: x = (5/6)i and x = -(5/6)i.

To learn more about variable

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Would assume it to be 36x² - 25 = 0

36x² - 25 = 0

(6x)² - 5² = 0

(6x + 5)(6x - 5) = 0 By difference of two squares.

6x + 5 = 0 or 6x - 5 = 0

6x = -5 6x = 5

x = -5/6 x = 5/6

x = +5/6 or - 5/6

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