What should you look for in a chemical formula to decide is a compound or element will not combust

Answers

Answer 1

Answer:

To determine whether a chemical formula represents a compound or element that will not combust, you need to consider the elements present in the formula and their respective properties.

How we can determine combustibility?

First, check if the formula contains only one type of element. If it does, then it represents an element, and the question of whether it will combust or not is irrelevant, as elements do not combust.

If the formula contains two or more different elements, then it represents a compound. To determine if the compound will combust, you need to look at the properties of its constituent elements.

Some elements, such as noble gases (e.g., helium, neon, argon), have very low reactivity and are unlikely to combust under normal conditions. Therefore, if the compound contains only noble gases, it is unlikely to combust.

Other elements, such as metals, are more reactive and can combust under certain conditions, such as exposure to heat or oxygen. Therefore, if the compound contains a metal, you need to check the reactivity of that metal to determine if the compound will combust.

Similarly, non-metals can also be combustible under certain conditions, such as exposure to heat or other reactive substances. Therefore, if the compound contains a non-metal, you need to check the reactivity of that non-metal to determine if the compound will combust.

Overall, to determine if a compound or element will combust, you need to consider the properties of its constituent elements and any external conditions that may affect its reactivity.

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Answer 2

Answer: You will look at its number lets say if you had H2O which is two hydrogen and one oxygen. The two hydrogen is combined with oxygen sharing it's electrons making it being covalent bonding. You need 8 valence electrons that meaning full outershell. Hydrogen only has one in it outershell oxygen has 6 that's what can make a compound

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Gloria is writing the chemical formula for a compound using its chemical name. She has just identified the names of the elements in the compound. What tool will she use next?
Count the total number of atoms in sio2:

How is molarity measured?O
A. In liters of water per moles of a dissolved substance
B. In liters of water per gram of a dissolved substance
O
C. In moles of a substance for 1 g of that substance
D. In moles of a substance dissolved in 1 L of water

Answers

Answer:

D. In moles of a substance dissolved in 1 L of water

Explanation:

Just took the test

Final answer:

Molarity is measured in moles of a substance dissolved in 1 L of water.

Explanation:

The molarity is measured in moles of a substance dissolved in 1 liter of water, so the correct option is D. In moles of a substance dissolved in 1 L of water. Molarity is a measure of the concentration of a solute in a solution. It is calculated by dividing the number of moles of solute by the volume of the solution in liters.

Molarity (M) is indeed a measure of the concentration of a solute in a solution and is defined as the number of moles of solute per liter of solution. This means it is measured in "moles of a substance dissolved in 1 liter of solution" or simply "moles/L" or "mol/L." Molarity is a fundamental concept in chemistry and is widely used in various chemical calculations and experiments to express the concentration of a substance in a solution.

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What’s the missing word

Answers

Answer:

crystallized by heating the salt solution

Salt solutions can be crystallized to give solid salts.

What net ionic equation describes the reaction when these solutions are mixed?Given the equation: Na3PO4 (aq) + CaCl2(aq) →

A. 2PO43–(aq) + Cl– (aq) → Cl2(PO4)3(s)
B. 2Ca2+(aq) + Na+(aq) → NaCa2(s)
C. Na+(aq) + Cl– (aq) → NaCl(s)
D. 2PO43–(aq) + 3Ca2+(aq) → Ca3(PO4)2(s)

Answers

I think the correct answer from the choices listed above is option D. The net ionic equation that will describe the reaction of the reactants when mixed is expressed as:

2PO43–(aq) + 3Ca2+(aq) → Ca3(PO4)2(s)

Hope this answers the question. Have a nice day.

Answer:

$2PO_(4)^(-3) (aq) + 3Ca^(+2)(aq)-->Ca_(3)(PO_(4))_(2)(s)$

Explanation:

In net ionic equation we remove the spectator ions. The ions which are present on both the side and are not forming any solid compound.

Let us write the balanced reaction first:

$2Na_(3)PO_(4)(aq)+3CaCl_(2)(aq)-->3Ca_(3)(PO_(4))_(2)+6NaCl(aq)$

The ionic reaction is:

$6Na^(+)(aq)++6Cl^(-)(aq)+2PO_(4)^(-3) (aq) + 3Ca^(+2)(aq)-->Ca_(3)(PO_(4))_(2)(s)+6Na^(+)(aq)+6Cl^(-)(aq)$

Thus net ionic reaction is

$2PO_(4)^(-3) (aq) + 3Ca^(+2)(aq)-->Ca_(3)(PO_(4))_(2)(s)$

State the characteristics of transition metals

Answers

Answer:

Conductivity, Malleability, High Melting Point, Luster

Explanation:

Transition metals have the following properties:

Conductivity (Electrical and Thermal)

Malleability (You can hit it with a hammer to mold it)

High melting point

Luster (Shininess)

Which statement regarding serum magnesium (Mg ++) is true? (Select all that apply.) Alcohol-related diseases frequently cause low Mg+ levels. Vomiting is not generally seen as a major cause of Mg+ loss. Mg++ levels present similarly to calcium (Ca++) levels in the blood. Mg+ deficiencies often result in low serum potassium (K+) levels. Mg+ deficiencies must be treated before potassium (K+) deficiencies.

Answers

Answer:

Alcohol-related diseases frequently cause low Mg+ levels.

- Mg+ deficiencies must be treated before potassium (K+) deficiencies.

- Mg+ deficiencies often result in low serum potassium (K+)

- Mg++ levels present similarly to calcium (Ca++) levels in the blood.

- Vomiting is not generally seen as a major cause of Mg+ loss

Rutherford’s gold foil experiment gave evidence that an atom is mostly empty space. true false

Answers

The given statement is true .

What is Rutherford’s gold foil experiment?

A piece of gold foil was hit with alpha particles, which have a favorable charge. Most alpha particles went right around. This showed that the gold particles were mostly space.

The Rutherford gold leaf investigation supposed that most (99%) of all the mass of an atom is in the middle of the atom, that the nucleus is very small (105 times small than the length of the atom) and that is positively captured.

For the distribution experiment, Rutherford enjoyed a metal sheet that could be as thin as practicable. Gold is the most malleable of all known metals. It can easily be converted into very thin sheets. Hence, Rutherford established a gold foil for his alpha-ray scattering experimentation.

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