Which substrate, enzyme pair from the citric acid cycle is INCORRECT? A) Isocitrate, isocitrate dehydrogenase B) Succinyl CoA, succinate dehydrogenase C) Fumarate, fumarase D) Oxaloacetate, citrate synthase E) Citrate, aconitase

Answers

Answer 1
Answer:

The substrate, enzyme pair from the citric acid cycle that is INCORRECT is E) Citrate, aconitase.

The citric acid cycle, also known as the Krebs cycle, is a crucial metabolic pathway for generating energy in cells. Each step involves specific substrates and enzymes. While all other options (A, B, C, and D) correctly match substrates and enzymes involved in the cycle, option E (Citrate, aconitase) is incorrect.

Aconitase is responsible for catalyzing the interconversion of citrate and isocitrate, not for the conversion of citrate itself. The correct pair for citrate is citrate synthase, which catalyzes the formation of citrate from oxaloacetate and acetyl-CoA.

Understanding these substrate-enzyme pairs is essential in comprehending the citric acid cycle's intricacies. Accurate knowledge of these reactions aids in grasping how cells produce energy through this pathway. This emphasizes the significance of precise knowledge of biochemical pathways for an accurate understanding of cellular processes.

In the context of cellular metabolism, identifying the correct enzyme for each substrate is vital for accurate biochemical analysis and the design of targeted interventions for metabolic disorders. Among the given options, the substrate, enzyme pair that is incorrect in the citric acid cycle is Citrate, aconitase.

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Answer 2
Answer:

Final answer:

The incorrect substrate-enzyme pair from the citric acid cycle is Oxaloacetate, citrate synthase.

Explanation:

The citric acid cycle, also known as the Krebs cycle or tricarboxylic acid cycle, is a series of chemical reactions that occur in the mitochondria of cells. It plays a crucial role in the aerobic respiration process, generating energy-rich molecules such as ATP.

The citric acid cycle involves the oxidation of acetyl-CoA derived from carbohydrates, fats, and proteins. Each step of the cycle is catalyzed by a specific enzyme, which acts on a particular substrate.

The correct substrate-enzyme pairs in the citric acid cycle are as follows:

  1. Isocitrate, isocitrate dehydrogenase
  2. Succinyl CoA, succinate dehydrogenase
  3. Fumarate, fumarase
  4. Oxaloacetate, citrate synthase
  5. Citrate, aconitase

Therefore, the incorrect substrate-enzyme pair from the given options is D) Oxaloacetate, citrate synthase.

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Why do saturated fatty acids have straight structures, while unsaturated fatty acids have bent structures?a. Saturated fatty acids have a larger mass.
b. Saturated fatty acids contain many more bonds.
c. Saturated fatty acids have single carbon-to-carbon bonds.
d. Saturated fatty acids contain more carbon atoms.

Answers

C) saturated fatty acids have single carbon-to carbon bonds

The _______ elements tend to lose electrons and form positive ions, while the _______ elements tend to gain electrons and form negative ions. A. Nonmetal, metal B. Metal, noble gas C. Metal, nonmetal D. Noble gas, nonmetal

Answers

Answer:

C.

Explanation:

Metals tends to lose electrons and form positive ions, known as cations. Whereas, non-metals tend to gain electrons and form negative ions known as anions.

Answer:

C. Metal, nonmetal

Explanation:

Fill in the blanks

The metal elements tend to lose electrons and form positive ions, while the non-metal elements tend to gain electrons and form negative ions.

Your teacher placed a drop of food coloring in a cup of water. the color slowly mixed into the water without being stirred. what does this tell you about water molecules?

Answers

Answer:

water molicules have space between them thus letting the food colour spread without stiring the water.

How many moles of h2o would be produced from 1.75 moles of o2 with unlimited c3h6

Answers

1.75 (moles O2) × 6 (moles H2O) ÷ 9 (moles O2) = 1.17 (moles H2O)

You have to convert moles of O2 into moles of H2O so it's the number of moles you start with (1.75 O2) × the number of moles from the element you want (6 H20), then ÷ by the number of moles that the element that you already have (9 O2).

What is true of valence electrons?a) They exist in the outer orbital.

b) they easily move from one orbital to another

c) they have difficulty moving from one orbital to another

d) they are always the lowest energy electrons of the atom

Answers

Answer:

They exist in the outter orbital

Explanation:

i think c may be your anwser but im not too sure :/ srry if u get it wrong!

Which formula represents an ionic compound?
(1) H2 (3) CH3OH
(2) CH4 (4) NH4Cl

Answers

Answer is: (4) NH4Cl.

Name of this chemical copmpound is ammonium chloride.

Ammonium chloride (NH₄Cl) is chemical compound with neutral charge.

1) Hydrogen (H) has oxidation number +1 in compounds with nonmetals (nitrogen and chlorine).

2) Chlorine has oxidation number -1, because ammonium ion (NH₄⁺) has positive charge.

3) In ammonium cation (NH₄⁺), nitrogen has higher electronegativity than hydrogen, so it has negative oxidation number -3:

x + 4 · (+1) = +1.

x = 1 - 4.

x = -3; oxidation number of nitrogen.

Electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

Other molecules have covalent chemical bonds.

An ionic compound is formed when there is a transfer of electrons between two atoms. The formula for an ionic compound is usually written as the combination of the symbols of the two ions. (4) NH4Cl represents an ionic compound as it follows the criteria of an atom losing or gaining electrons.

An ionic compound is formed when there is a transfer of electrons between two atoms. In an ionic compound, one atom will lose electrons to become a positively charged ion, while the other atom will gain those electrons to become a negatively charged ion. The formula for an ionic compound is usually written as the combination of the symbols of the two ions.

Out of the given options, (4) NH4Cl represents an ionic compound. In this formula, the ammonium ion (NH4+) loses one electron to become positively charged, and the chloride ion (Cl-) gains that electron to become negatively charged.

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