Using the property find the sum: (4/3 + 3/5 + "-2/3" + "-11/5)"
Answers
Answer:
-14/15
Step-by-step explanation:
First the denominator must be the same so mutiply three with 5 to get 15. Don't forget to mutiply numrator!
After that, sump up the first numerator and second numerator because both are plus so you will get 29
Then, sum up the third numrator and forth numrator because both are minus so you will get -43.
Finally, you have 29 + -43 by 15.
You have to substract small number from large number so you will get -14. We use minus sign because -43 is larger than 29.
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Write a linear function that passes through (1,5) and (2,15)
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Identify the vertex of y = -1 (x-4)^2 +9 and tell whether it’s a minimum or maximumplease and thanks!
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Answers
the answer is 28
Answers
therefor we have an exponential function
we take 2 points (0, 25,000) and (1, 23,750) and use our trusty TI and find the equation
equatin is y=25000(0.95^x) or
f(x)=25000(0.95^x)
Answers
well if you have the cost of a pretzel then multiply that by 4 then add 3
in
the length of the rectangle is 8 inches. Find the perimeter of the rectangle. show all of your work for full credit.
Answers
Answer:
It is 40 in.
Step-by-step explanation:
1) 96 divided by 8 = 12, which means that is what multiplied with.
2) 8+8+12+12= 40
3) hope that helps!!!
log base four of x equals two.
Answers
Answer:
x = 16
Step-by-step explanation:
The equation is
Now, converting this logarithmic equation into exponential equation, we get
(Answer)
Alternate solution:
Given,
⇒
{Since, we know that }
⇒
{Since, is a property of logarithm}
Cancelling log from both sides we get,
⇒ x = 16 (Answer)
Answer:
Step-by-step explanation:
hey there,
< Here is what is given:
㏒
There's actually a lot of different ways you can remember this but the way I remember this is x is equal to 2nd to the power of last.
So 8 is the 2nd (since log is first), 4 is last (very last thing in the equation).
x = 8^4
You can use any of your own ways to remember this, but this is just my personal way. :) >
Hope this helped! Feel free to ask anything else.