PHYSICS HIGH SCHOOL

If a radio and a bulb each of resistance 3 ohm are connected in series to a 12 volts battery, the potential difference across each will be;a) 3V

b) 6V

c) 12V

d) 9V

Can u please solve and then explain answer

Answers

Answer 1
Answer:

Answer:

\rm{Option \:B) \: 6V}

Explanation:

Given resistance of the radio is 3Ω and the resistance of the bulb is 3Ω. The total resistance in the circuit is

R_1 + R_2 = 6 Ω</p><p>

NowapplyOhm'sLaw,

V \:=\: IR

The voltage of the battery is V = 12V. And we have the total resistance of the circuit. Substituting the values to find current:

I = 12 V / 6 Ω = 2A

The potential difference across the radio or the bulb (using V = IR) is:

V = 3 * 2 = 6V

~The answer is option(b) 6 volts.

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