PHYSICS HIGH SCHOOL

The angle between the two vectors A=3i^+4j^+5k^ and B=3i^+4j^−5k^ will be: a. 90 degree b. 0 degree . 60 degree d. 30 degree

Answers

Answer 1

Answer:

Answer:

Both vectors have the same X and Y components therefore

the angle between the two vectors is zero

(B) is correct

Related Questions

A hair dryer uses 72,000 joules of energy in 60 seconds. What is the power of this hair dryer?
One of your delivery trucks traveled 1,200 miles on 55 gallons of gas. How many miles per gallon did the truck get? (Round off your answer to the nearest hundredth.) A. 45.84B. 21.81C. 45.83D. 21.82
Which of the following is not one of the observed characteristics of our solar system?all planets go in the same circular direction all planets look as though they lie along a flattened circular plane or disk the Sun and planets rotate in the same direction all moons orbit planets in a counterclockwise direction
If the tension in a rope is increased what will happen to the speed of a wave traveling through the rope
How much work is required to move3.0 coulombs of electric charge a distance of0.010 meter through a potential difference of9.0 volts?(1) 2.7 × 10^3 J (3) 3.0 J(2) 27 J (4) 3.0 × 10^−2 J

Displacement is the change in velocity of an object.

True or false

Answers

Words less true are seldom if ever spoken.

False, it is the change in distance. Chance in velocity would be Δv

What is transferred by a force moving an object through a distance? A. force
B. mass
C. motion
D. energy

Answers

When you apply force to move anobject at a distance, you are applying work. And work is energy in transit. Theanswer is letter D. For example, you see a cart at a distance. You observe thatit is not moving. You want to transfer it to your backyard. You apply force tothe cart and observed that the cart is not at the same position as it wasbefore. You are applying work to the cart by transferring your energy to it.

Answer:

When you apply force to move an object at a distance, you are applying work. And work is energy in transit. The answer is letter D. For example, you see a cart at a distance. You observe that it is not moving. You want to transfer it to your backyard. You apply force to the cart and observed that the cart is not at the same position as it was before. You are applying work to the cart by transferring your energy to it.

Explanation:

During which period did the first large herbivores and carnivores appear?

Answers

The first large herbivores and carnivores appeared during the Mesozoic Era, which is divided into three periods-- Triassic, Jurassic and Cretaceous. The herbivores and and carnivores increased in size during the Jurassic Period. And some of the largest dinosaurs emerged during this period as well.

A 0.145 kg baseball is thrown horizontally at 15 m/s from a platform, so that it starts at 5.2 m above the ground. How much has its kinetic energy increased when it reaches the ground? 16 J , 24 J , 0 J , or 7.4 J ? :/

Answers

7.4J
final kinetic energy
= initial potential energy
= mass x gravitational force x height
= 0.145 x 9.81 x 5.2
= 7.39674 J

How much amount of heat is required to raise the temperature of 20 grams of water from 10°C to 30°C? The specific heat of water is 4.18 J/g°C.

Answers

The amount of heat:
Q = m c ΔT
m = 20 g, c = 4.18 J/g°C, ΔT = 30° - 10° = 20° C
Q = 20 g · 4.18 J/g°C · 20°C = 1672 J
Answer: C ) 1700 J

Answer : The amount of heat is required is, 1672 J

Solution :

Formula used :

$Q= m* c* \Delta T$

$Q= m* c* (T_(final)-T_(initial))$

Q= heat gained

m= mass of the substance = 20 g

c = heat capacity of water = 4.18 J/g ° C

$T_(final)$ = final temperature = $30^oC$

$T_(initial)$ = initial temperature = $10^oC$

Now put all the given values in the above formula, we get the heat required.

$Q= (20g)* (4.18 J/g^oC)* (30-10)^oC$

Q = 1672 Joules

Therefore, the amount of heat is required is, 1672 J

A stone is dropped from a tower 100 meters above the ground. The stone falls past ground level and into a well. It hits the water at the bottom of the well 5.00 seconds after being dropped from the tower. Calculate the depth of the well. Given: g = -9.81 meters/second2.

Answers

The distance that an object falls from rest in ' T ' seconds is

   Distance = (1/2) (gravity) ( T² )

In this question,

   Distance = (1/2) (9.81 m/s²) (5.00 s)²

   =    (4.905 m/s²) (25.0 s²)

   =    (4.905 x 25) m

   = 122.63 meters .

The first 100 meters of fall was from the tower to ground level,
so the distance into the well must be the remaining 22.63 meters.

Answer:

22.5 meters

Explanation:

Other Questions

A box is being pulled to the right on flat ground with a force of 112 N at an angle of 42° to the horizontal. What is the x-component of the force of tension?

Recognize the relationship between stiffness of the medium and the speed of a wave.

Why would an airplane flying at 10,000 meters above the ground have more gravitational potentialenergy than the same airplane flying at 1,000 meters above the ground?

What is the magnitude of the electric field at a point 0.0075 m from a 0.0035 C charge?