9ones 2thousandths - 3ones
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Related Questions
Solve for y. y – (–19) = 25a. –44b. –6c. 6d. 44
the Gonzales family has three children. On summer break, they went to an amusement park. They bought 3 child tickets for 18.50 and 2 adult tickets. If they spent a total of 104.50, how much was the price of each adult ticket?
What is root 9 divided by root 25
Order from least to greatest: -0.8, 2/5, 0.825, -3/5
Answers
The fraction of the kittens that are not white is 3/4.
What are fractions?
Fractions are non-integers. Fractions are made up of numerators and denominators. An example of fractions is 1/2. 1 is the numerator and 2 is denominator.
What is the fraction of the kittens that are not white?
Number of kittens that are not white = number of non-white kittens / total number of kittens
(8 - 2) / 8 = 6/8 = 3/4.
To learn more about fractions, please check: brainly.com/question/25779356
Answer:
2/12 marbles
10/12+2/12=12/12=1
Step-by-step explanation:
Answers
Answer:
D. 18 bags
Step-by-step explanation:
Given:
Matilda is filling a circular section of her porch with colorful pebbles.
Diameter of circular section = 15 feet.
Each bag of pebbles covers 10 square feet.
Question asked:
How many bags of pebbles will Matilda need?
Solution:
Diameter of circular section = 15 feet
Radius, r =
10 square feet is covered by number of bag of pebbles = 1
1 square feet is covered by number of bag of pebbles =
176.78 square feet is covered by number of bags of pebbles =
We found up to 17 bags of pebbles there is still some place left to fill the section:-
Thus, Matilda need about 18 bags of pebbles to fill the circular section of her porch.
Answers
No. The area doesn't tell you the dimensions, and you need
the dimensions if you want the perimeter.
If you know the area, you only know the product of the length and width,
but you don't know what either of them is.
In fact, you can draw an infinite number of different rectangles
that all have the same area but different perimeters.
Here. Look at this.
I tell you that a rectangle's area is 256. What is its perimeter ?
-- If the rectangle is 16 by 16, then its perimeter is 64 .
-- If the rectangle is 8 by 32, then its perimeter is 80 .
-- If the rectangle is 4 by 64, then its perimeter is 136 .
-- If the rectangle is 2 by 128, then its perimeter is 260 .
-- If the rectangle is 1 by 256, then its perimeter is 514 .
-- If the rectangle is 0.01 by 25,600 then its perimeter is 51,200.02
Explanation please, not just the answer. Brainliest answer if you calculate it for 2 out of 251 total marbles as well.
Answers
Well, I agonized over this for a while, and I have something that we may want to consider.
The only probability formula I know how to use is
Probability = (number of possible successes) / (total number of possibilities).
Can we work with that ? Let's see . . .
The denominator of that fraction is the total number of ways to draw
10 marbles from a jar of 60 . . .
The first draw can be any one of 60 marbles. For each of those . . .
The second draw can be any one of the remaining 59. For each of those . . .
The third draw can be any one of the remaining 58.
.
.
etc.
So the total number of ways to draw 10 from 60 is
(60 x 59 x 58 x 57 x 56 x 55 x 54 x 53 x 52 x 51)
That's a very big number. My calculator says something that rounds to
2.736 x 10¹⁷. But my calculator only shows 10 digits, so it can't show
all 18 digits in the number. Fortunately, we don't need to see the whole
number written out. We'll just write it in factorial notation, and go on
to do the numerator of the fraction, which is going to be much harder.
That number that we just found is equal to (60!) / (50!) . It's going to be
the denominator of the big fraction.
Now for the numerator. That's going to be the number of ways that the
two red marbles can be included among the ten marbles drawn.
One red marble can be any one of the 10 marbles pulled out.
For each of those . . .
The other red marble can be any one of the other 9 that are picked.
So there are (10 x 9) = 90 ways for the selected 10 to include both red ones.
SO ! Now, the probability that the ten that are drawn will include the two
red ones should be (it might be, it could be) . . .
90 divided by (60! / 50!) .
Remember, that fraction on the right is just total number of ways
to pick 10 out of 60 . The probability of including both red ones
in the draw is 90 divided by that number. It's very small.
Again from my calculator, it's 3.29 x 10⁻¹⁴ percent.
I have no confidence in my answer, but I invite you to look it over, along with
all the real gurus out there.
If I'm wrong, then I've stolen only 5 points that I'm not entitled to, and at least
I did put some effort into it.
Giving you 20/120.
Simplify that to get 1/6. So you have a 1 in 6 chance of getting both the red marbles.
(I'm not 100% sure since it's been a while so you might want to get a second opinion.)
Not sure what you mean by the second part, but hope I provided some help :)
Answers
Answer:
x=6
Step-by-step explanation:
h(x) = -( x-2)^2 +16
We want when h(x) = 0
0 = -( x-2)^2 +16
Subtract 16 from each side
-16 = -( x-2)^2 +16-16
-16 = -( x-2)^2
Divide by -1
16= ( x-2)^2
Take the square root of each side
±sqrt(16) = sqrt(( x-2)^2 )
±4 = x-2
Add 2 to each sdie
2 ±4 = x-2+2
2+4 = x 2-4 =x
6 =x -2 =x
since time cannot be negative
x=6
345 cm
34.5 dl
345 cg
Answers
Answer:
3450 mm
Step-by-step explanation: