Using the slope​ formula, find the slope of the line through the given points. (2,5) and (4,9)

Answers

Answer 1
Answer:

Answer: Slope is 2

Step-by-step explanation:

9-5.

-------      4/2 --- 2

4-2


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Solve the equation using the quadratic formula.x^2 + 3x -2 = 0
Question options:

x = −3±√17/2

x =−2±√17/3

x = −2±√29/4

x = 3±√11/2

Answers

Hello:
x²+3x-2 = 0
delta = b²-4ac       a=1       b = 3        c = -2
delta =(3)²-4(1)(-2) =17 =(√17)² 
x = −3±√17/2

4. A rectangle measures 20cm by 15cm If each dimension is increased by 2.5cm by what percentage is a) The perimeter of the rectangle increased b) The area of the rectangle is increased​

Answers

Answer:

The area of the rectangle is increased by 393.75.

Step-by-step explanation:

Add 2.5 to each number then multiply the sums. Please note I am actually in 7th grade.

Write an equation of a line that is parallel to y=-6x+4 and passes through(2,10).write an equation of line which is perpendicular to y=(-2/3)x-5 and passes through point (6,3).
write the equation of three lines so that the y-intercept of each is -3.

Answers

a)y=-6x+4
Slope and intercept a=-6 b=4
equation for new line:
y=cx+d
If new line is parallel c=a=-6 so
y=-6x+d
We substitude point (2,10)
10=-6*2+d /+12
d=22
so y=-6x+22
b) 
y=-(2)/(3)x-5
a=-2/3
b=-5
new line:
y=ex+f
If line is perpendicular e=-(1)/(a)
so e=(3)/(2)
we can write 
y=(3)/(2)x+f
Substituting point (6,3)
3=(3)/(2)*6+f
f=3-9
f=-6
y=(3)/(2)x-6

Jules kicks a soccer ball off the ground and into the air with an initial velocity of 25 feet per second. Assume the starting height of the ball is 0 feet. Approximately what maximum height does the soccer ball reach?0.8 ft

1.6 ft

9.8 ft

19.6 ft

Approximately, how long does it take until the soccer ball hits the ground again?

0.6 sec

0.8 sec

1.6 secs

2.8 secs

Answers

Answer:

Maximum height=9.8 ft and Time taken by soccer ball will be 0.8 secs

Step-by-step explanation:

Since, the ball kicked will take the motion of projectile, therefore using the equation: h(t)= at^(2) +vt+d, where h(t) is the height of the soccer ball, a is the acceleration whose value is -16 ft/sec^2 and v= 35 feet and d is the starting height which is equal to zero.

Therefore, h(t)=at^(2) +vt+d                                                     (1)

Differentiating this  equation with respect to t,

h^(')(t)= 2at+v

                      0   =2(-16)t+25

                     32t=25

                      t= 0.781sec

Substituting the value of t in equation (1),

h(t)=-16(0.781)^(2) +25(0.781)

           =(-16)(0.609)+19.525

           =9.766

           ≈9.8ft

Hence, option C is correct.

Now, In order to determine the time taken until the soccer ball hits the ground, we take the equation:

h(t)= at^(2) +vt+d

Since, when the ball hits the ground, the height will become equal to zero, therefore we have, h(t)=0

Now, h(t)= at^(2) +vt+d

0= -32.174t^(2) +25t

0=t(-32.174t+25)

Then, one solution is t=0 and the other is: 0=-32.174t+25

32t=25

t=(25)/(32.174)

t=0.777 sec

t0.8 sec

Hence, option B is correct.

Answer:

9.8 ft for the maximum height

1.6 sec for the time it’ll take for the ball to hit the ground again

I just took a test and it shows me what I got wrong alongside the correct answers. And this was a question it asked.

88% of 56.25 is what number?

Answers

Your answer is 88% of 56.25 is 49.5

Hope this helps.
My book said 88% of 56.25 is 49.5?

Real numbers that you cannot represent as a quotient of two integers are ? numbers

Answers

Answer: The set of numbers that cannot be represented as the quotient of two integers are the irrational numbers

which are neverending where the numbers after the decimal point don't repeat (there isn't a subsequence of digits that repeats, like in the number 3.33...) , then the irrational numbers of the form 1.31234.... and cannot be represented as the quotient of two integers.

Real numbers that you cannot represent as a quotient of two integers are irrational numbers.