MATHEMATICS HIGH SCHOOL

Determine whether the equation defines y as a function of x+y2=1

Answers

Answer 1

Answer:

x+y2=14

⟹y2=14−x

⟹y=±14−x−−−−−√

Let’s say we plug in x=5

, we will get y=±3

The definition of a function says that one input must give us at most one output. This tells us that from this equation we cannot have y

as a function of x

x3−y3=27

⟹y3=x3−27

⟹y=x3–27−−−−−√3

The cube root function gives us one output per input. As a consequence of the previous statement and using the definition of function we can say that from this equation we can write y

as a function of x

Related Questions

No trick. Pure math. Gud luck Solve it You are standing in one big palace where a king and his 5 queens stay. Each queen has 5 rooms. In each room there are 5 big cats. Each big cat has 5 little cats. Each cat has 4 legs.How many legs are there in the palace?
Find the measure of angle X in the figure below Choices: 35°, 47°, 73°, 78°
Which of the following is a polynomial with roots 4, −5, and 7?Question 4 options: 1) f(x) = x3 − 6x2 − 27x + 1402) f(x) = x3 − 6x2 − 20x + 273) f(x) = x3 − 20x2 − 27x + 35 4) f(x) = x3 − 20x2 − 35x + 140
If an equation of the linear function in the figure above is y=mx=b, than m=
Steven wants to buy a $495 bicycle. Steven has no money saved, but will be able to deposit $40 into a savings account when he receives his paycheck each Friday. However, before Steven can buy the bike, he must give his sister $65 that he owes her. For how many weeks will Steven need to deposit money into his savings account before he can pay back his sister and buy the bike?

What multiplys to 6 and adds to 6

Answers

There is no answer to your question.

To prove so, lets look at all of the factor pairs of six

1,6

2,3

^^These numbers when multiplied equal 6. However, neither of them have a sum of 6.

1+6=7
1+6≠6

2+3=5
2+3≠6

What is the answer 8x-7 = 3x-7+5x

Answers

The answer is x=0 cause everything cancels out

20a + 158 + 6c = 20 (6) +15(4) + 6(8)
?
?
+
?
2
+
?

Answers

a=7/2-3/10

Step-by-step explanation:

20a +158+6c= 120+60+48

20a +158+6c=228

20a =228-158-6c

20a =70-6c

a= 7/2 - 3/10

Answer:

120 + 60 + 48 would be the correct answer !

Step-by-step explanation:

PLS I NEED HELP WILL MAKE BRAINLEST

Answers

Answer:

then1,5 1,5

0,3

2,2

Which of the following represents the zeros of f(x) = x3 − 12x2 + 41x − 42?7, −3, 2
7, −3, −2
7, 3, 2
7, 3, −2

Answers

Given the polynomial function $f(x)=x^3-12x^2+41x-42.$

The integer zeros should be divisors of free term -42.

The divisors of -42 are:

$\pm 1, \pm 2, \pm 3, \pm 6, \pm 7, \pm 14, \pm 21, \pm 42.$

If some of these number is zero of f(x), then f takes 0 value at this point.

Check them:

$f(1)=1^3-12\cdot 1^2 + 41\cdot 1-42=1-12+41-42=-12\neq 0;$

$f(-1)=(-1)^3-12\cdot (-1)^2 + 41\cdot (-1)-42=-1-12-41-42=-96\neq 0;$

$f(2)=2^3-12\cdot 2^2 + 41\cdot 2-42=8-48+82-42=0;$

$f(-2)=(-2)^3-12\cdot (-2)^2 + 41\cdot (-2)-42=-8-48-82-42=-180\neq 0;$

$f(3)=3^3-12\cdot 3^2 + 41\cdot 3-42=27-108+123-42=0;$

$f(-3)=(-3)^3-12\cdot (-3)^2 + 41\cdot (-3)-42=-27-108-123-42=-300\neq 0;$

$f(6)=6^3-12\cdot 6^2 + 41\cdot 6-42=216-432+246-42=-12\neq 0;$

$f(-6)=(-6)^3-12\cdot (-6)^2 + 41\cdot (-6)-42=-216-432-246-42=-936\neq 0;$

$f(7)=7^3-12\cdot 7^2 + 41\cdot 7-42=343-588+287-42=0.$

Since the third degree polynomial function may have only 3 zeros, then you can end this process and state that zeros are 2, 3 and 7, because f(2)=0, f(3)=0 and f(7)=0.

Answer: correct choice is C

Answer: Zeroes are,

7, 3, 2

Step-by-step explanation:

Here, the given cubic equation,

$f(x) = x^3 - 12x^2 + 41x - 42$