SOMEONE HELP PLEASEData:

Record the results of each of your physical property tests in the table below.

Wood Clay Brick Iron Aluminum Copper Nickel

Flexibility

(?/10)

Magnetism

(number of paper clips)

Thermal Conductivity

(W/(m·K))

Electrical Conductivity

(x107 S/m)

Mass (g) 10g 10g 10g 10g 10g 10g

Volume (cm3)

Formula:

L x W x H

Density

(g/cm3)

Formula:

D=M/V

Answers

Answer 1
Answer:

The exercise is to measure and record the Physical properties of materials, such as flexibility, magnetism, thermal conductivity, electrical conductivity and density. Magnetism and flexibility can be observed directly, while density, thermal conductivity, and electrical conductivity require calculations.

The student is asked to measure and record the physical properties of various materials.

Flexibility can be rated subjectively on a scale of 1-10, with 10 being most flexible.

Magnetism can be tested by seeing how many paper clips each material can hold.

Thermal Conductivity (W/(m·K)) is a measure of a material's ability to conduct heat, while Electrical Conductivity (x107 S/m) measures the material's ability to conduct electricity.

For density, you need the mass (M) and volume (V) of the material.

The mass is given as 10g for all materials. You have to measure the volume (V) using the formula length x width x height (L x W x H).

Then plug M and V into the density formula D=M/V to get the density in g/cm3. Keep in mind that each material will have different properties.

Learn more about Physical properties of materials here:

brainly.com/question/34913809

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Answers

Answer:

1.25 moles NaNO

Explanation:

Molarity = moles/Volume (L)

moles = Molarity (M) x Volume (L)

M = 2.5 M

V = 500 mL = 0.5L

moles = M x V = 2.5 x 0.5 = 1.25 moles

A certain substance melts at a temperature of . But if a sample of is prepared with of urea dissolved in it, the sample is found to have a melting point of instead. Calculate the molal freezing point depression constant of . Round your answer to significant digits.

Answers

Answer:

2.2 °C/m

Explanation:

It seems the question is incomplete. However, this problem has been found in a web search, with values as follow:

" A certain substance X melts at a temperature of -9.9 °C. But if a 350 g sample of X is prepared with 31.8 g of urea (CH₄N₂O) dissolved in it, the sample is found to have a melting point of -13.2°C instead. Calculate the molal freezing point depression constant of X. Round your answer to 2 significant digits. "

So we use the formula for freezing point depression:

  • ΔTf = Kf * m

In this case, ΔTf = 13.2 - 9.9 = 3.3°C

m is the molality (moles solute/kg solvent)

  • 350 g X ⇒ 350/1000 = 0.35 kg X
  • 31.8 g Urea ÷ 60 g/mol = 0.53 mol Urea

Molality = 0.53 / 0.35 = 1.51 m

So now we have all the required data to solve for Kf:

  • ΔTf = Kf * m
  • 3.3 °C = Kf * 1.51 m
  • Kf = 2.2 °C/m

Which of the following is a correct definition of the term armature? A. A type of resistant wire B. A type of dry cell battery C. A circuit diagram D. A small lever in a relay switch

Answers

option a. a type of resistant wire

a revolving structure in an electric motor or generator, wound with the coils that carry the current.

Answer:

The correct option is: D. A small lever in a relay switch

Explanation:

Armature is a constituting part of an electric machine, that can be used as a stationary or rotating part. It is a conductor or a conducting coil that carries alternating current and can generate electromotive force.

In a solenoid, the movable steel or iron part that functions as a switch or relay is also termed as the armature.

What is the length of time an organism is expected to live?

Answers

This is called a life span.

In amino acid "valine", the terminal groups attach with what atom?

Answers