Ms. Cassidy is taking students to the movies. Each ticket costs $6. Ms. Cassidydecides that if she has any extra money left after buying tickets she will buy an
extra-large popcorn that costs $5. If Ms. Cassidy has $395 to spend on tickets,
will she have any leftover money to buy the extra-large popcorn? Explain why or
why not on the lines below.
Answers
Answer: 64 tickets with $5 left for the extra-large popcorn.
Explanation:
To solve this, we can divide $395 by 6. If the remainder is greater than or equal to 5, she can afford the popcorn. If not, she won't be able to. See attached for the long division. This shows she can buy 65 tickets with $5 left for the popcorn.
Answer:
To determine whether Ms. Cassidy will have any leftover money to buy the extra-large popcorn, we need to calculate the total cost of the movie tickets and compare it to the amount of money she has.
Let's assume Ms. Cassidy buys 'x' tickets. Each ticket costs $6, so the total cost of the tickets can be calculated as 6x.
Given that Ms. Cassidy has $395 to spend on tickets, we can set up an equation:
6x = 395
Now let's solve for 'x':
x = 395 / 6 ≈ 65.83
Since we cannot have a fraction of a ticket, we can round down to the nearest whole number:
x = 65
So Ms. Cassidy can buy a maximum of 65 tickets with $395.
Now, let's calculate the total cost of 65 tickets:
Total cost = 6 * 65 = $390
Since the total cost of the tickets is $390, which is less than the $395 Ms. Cassidy has, she will have some money leftover.
The question states that if she has any extra money left after buying tickets, Ms. Cassidy will buy an extra-large popcorn that costs $5. Since she has $5 left after buying the tickets, she will be able to buy the extra-large popcorn.
Therefore, Ms. Cassidy will have enough money ($5) to buy the extra-large popcorn after purchasing the tickets.
Step-by-step explanation:
Related Questions
G is the incenter, or point of concurrency, of the angle bisectors of ΔACE.Triangle A C E has point G as its incenter. Lines are drawn from the points of the triangle to point G. Lines are drawn from point G to the sides of the triangle to form right angles. Line segments G B, G D, and G F are formed. Angle F E G is (3 n minus 1) degrees and angle D E G is 20 degrees.What is the value of n?672059G is the incenter, or point of concurrency, of the angle bisectors of ΔACE.Triangle A C E has point G as its incenter. Lines are drawn from the points of the triangle to point G. Lines are drawn from point G to the sides of the triangle to form right angles. Line segments G B, G D, and G F are formed. Angle F E G is (3 n minus 1) degrees and angle D E G is 20 degrees.What is the value of n?672059
Solve for x 5x−1=6x−9 It would be better for more of a simpler and easier method if possible.
How do you find the largest 6-digit multiple of 11 such that the sum of all its digits equals 40. What is the answer?
-4x-8 and -4(x-2) *A: Yes, they are equivalentB: No, they're not equivalent
Answers
Answer with Step-by-step explanation:
Members pay a $12 membership fee and $5 for each aerobic class.
i.e. if x is the number of aerobic classes then,
Members have to pay=5x+12
Nonmembers pay $6 for each aerobic class.
i.e. if x is the number of aerobic classes then,
Non members have to pay=6x
We have to determine the number of classes so that they both have to pay same amount
i.e. we have to find the value of x in
6x=5x+12
Subtracting both sides by 5x, we get
x=12
Hence, for 12 classes members and nonmembers have to pay the same amount
Make an equation:
5x+12=6x
Use the subtraction property:
x=12
The final answer is that the cost for members and nonmembers will be the same when there have been 12 classes.
Answers
The value of x in the equation a – bx = cx + d is = a - d / c + b
The value of x in the equation 5 – 6x = 8x + 17 is - 6 / 7
a - bx = cx + d
add bx to both sides of the equation
a - bx + bx = cx + bx + d
a = cx + bx + d
subtract d form both sides of the equation
a - d = cx + bx + d - d
a - d = cx + bx
Distributive law:
using distributive law on the right side of the equation
a - d = x (c + b)
divide both sides by (c + b)
Therefore,
x = a - d / c + b
Let's use the same method to solve 5 – 6x = 8x + 17
5 – 6x = 8x + 17
add 6x to both sides
5 – 6x + 6x= 8x + 6x + 17
5 = 14x + 17
subtract 17 from both sides
5 - 17 = 14x + 17 - 17
-12 = 14x
divide both sides by 14
x = -12 / 14
x = - 6 / 7
learn more on equations here: brainly.com/question/7838122
Answers
Answers
Answer: 880
Step-by-step explanation:
4xy 2 + 8x 2y
4xy 3 + 8x 2
4xy 3 + 8x 2y
Answers
4xy(y² + 2x)
When we have brackets like this, we multiply whatever is left of the brackets by everything inside.
1) 4xy multiplied by y²
4xy x y² = 4xy³
2) 4xy multiplied by 2x
4xy x 2x = 8x²y
3) Add together 4xy³ and 8x²y
4xy³ + 8x²y
Answers
The weight of each bag filled by Brandon, is .
Further explanation:
The amount of cashews and pistachios mixed are and
respectively then the total weight of mixture is the sum of cashews and pistachios.
After the above nut mixture created by mixing cashews and pistachios is filled in six bags, the weight of remaining nuts is .
Therefore, the total mixture that is filled in 6 bags is obtained as the difference of total amount and the remaining mixture amount.
Now, this obtained amount of mixture weighing is filled equally in 6 bags as the size of bags is same then the amount of mixture in one bag or each bag is calculated as,
Thus, the weight of each of the six bags that Brandon fills, is .
Learn more:
1. Linear equation application brainly.com/question/2479097
2. Composite functions brainly.com/question/2142762
3. Linear equation application brainly.com/question/2479097
Answer details:
Grade: Middle school
Subject: Mathematics
Chapter: Mixtures and ratios
Keywords: cashews, pistachios, one bag, six bag, each bag, weight, Brandon, same size, mixture, nuts, 6.83lb, 3.57lb, 0.35lb, total mixture, amount of mixture, remaining amount, remaining weight, total weight, nut mixture.
weight of mixture = 6.83+3.57=10.40lb
amount left= 0.35lb
rest = 10.4-0.35= 10.05lb
rest is filled in 6 bags.
weight in each bag=10.05/6= 1.675lb
hence weight of each bag is 1.675lb