253, 248 ,243 find the 49th term

Answers

Answer 1

Answer:

Step-by-step explanation:

253 , 248 243 238 233 228 223 218 213 208 203 198 193 188 183 178 173 168 163 158 153 148 143 138 133 128 123 118 113 108 103 98 93 88 83 78 73 68 63 58 53 48 43 38 33 28 23 18 13 i

ts 13 i think
i just counted down ^^

Answer 2

Answer: To find the 49th term of the sequence 253, 248, 243, ... , we notice that the sequence is decreasing by 5 each time. This is an arithmetic sequence with a common difference of -5.

We use the formula for the nth term of an arithmetic sequence, which is:
nth term = first term + (n - 1) * common difference

Here, the first term is 253, the common difference is -5, and we're looking for the 49th term.

Plug these into the formula:
49th term = 253 + (49 - 1) * -5
49th term = 253 + 48 * -5
49th term = 253 - 240
49th term = 13

So, the 49th term of the sequence is 13.

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Z=2b+6 and y=3b-1 answer please?

Answers

You've given us two equations and asked for an answer.

What you haven't given us is a question.

Bridget needs an actor. Actor A is offering her services for an initial $250 in additionto $50 per day. Actor B is offering her services for an initial $200 in addition to $60
per day. When will the two actors charge the same amount of money?

Answers

$250 + 50x = $200 + 60x

Get like terms on the same side using subtraction
250 -200 + 50x = 60x
50 + 50x - 50x = 60x -50x
50 = 10x now divide by 10 and get 5 days.

Let's check

Day 1 Actor A is $250 + 50 = $300 Actor B = $200 + 60 = $260
Day 2 Actor A is $250 + 100 = $350 Actor B = $200 + 120 = $320
Day 3 Actor A is $250 + 150 = $400 Actor B = $200 + 180 = $380
Day 4 Actor A is $250 + 200 = $450 Actor B = $200 + 240 = $440
Day 5 Actor A is $250 + 250 = $500 Actor B = $200 + 300 = $500

Answer:

The two actors will have the same amount of money in 5 days.

Step-by-step explanation:

What is the value of a.

45/105 = 6/a

Answers

solve the rational equation by combining expressions and isolating the variable a and it equals 14

cross multiple and get

45a = 630 divide both sides by 45

a = 630/45

a = 14

hope helped

Given segment AB, explain how to construct a square with sides of length AB.

Answers

The square can be constructed by making perpendicular on vertex A and B. Then cut an arcs and obtain the points C and D and construct perpendicular on point C and D and get ABCD is required square.

Further Explanation:

Square is a 4 sided close figure.

Square has all sides equal and all angles are of .

The all sides of the square are perpendicular to each other.

Given:

A line segment AB.

Construction:

Steps involve in constructing a square from a line segment AB are as follows.

1. Draw a line segment AB.

2. Construct perpendicular AX at point A and then construct another perpendicular BY at point B.

3. Cut an arc on perpendicular line from A at point C that is equal to the length equal to side AB

4. Cut an arc on perpendicular line from B at point D that is equal to the length equal to side AB

5. Construct perpendicular at point C and then construct another perpendicular at point D.

6. The perpendicular intersects each other at point C and D.

The required square is ABCD is shown in figure attached.

Kindly refer to the image attached.

Learn more:

1. Learn more about inverse of the function brainly.com/question/1632445.

2. Learn more about equation of circle brainly.com/question/1506955.

3. Learn more about range and domain of the function brainly.com/question/3412497

Answer details:

Grade: Middle School

Subject: Mathematics

Chapter: Construction

Keywords: square, perpendicular, , intersect, construct, line, line segment, point, right angle, sides, close figure, arc, length.

1. Extend the segment AB twice left and twice right. Let the point that lies left be D and the point that lies right be C. Then AD=AB=BC.

2. Draw the circles with center at points D and B and congruent radii that are greater than AB. Denote two points of their intersection as E and F.

3. Combine points E and F. The segment EF is perpendicular to the segment AB and passes through the point A.

4. Draw the circles with center at points C and A and congruent radii that are greater than AB. Denote two points of their intersection as K and L.

5. Combine points K and L. The segment KL is perpendicular to the segment AB and passes through the point B.

6. Postpone on the segment EF point X such that AX=AB and on the segment KL point Y, such that BY=AB and X and Y lie for the same side.

7. Combine points X and Y. ABYX is required square.

Express each number in standard form
-9.5x10-3
This is 10 to the -3 power

Answers

$-9.5*10^(-3)=-9.5*0.001=-0.0095$

Calculate the size of side x to 1 decimal
place. Show your working.

Answers

Answer:

$x=7.4$ m and $x=11.2$ m

Step-by-step explanation:

To do these problems, we will need to use the Pythagorean Theorem.

Recall that it states $a^2+b^2=c^2$ , where c is the longest side, the hypotenuse, of the triangle.

a) We have a triangle with side lengths 4.2 m and 6.1 m. These two sides correspond to a and b in this equation.

Now, we can plug these values into the equation and solve for c, which is x.

$(4.2)^2+(6.1)^2=x^2\n\n17.64+37.21=x^2\n\nx=√(54.85)\n\nx=7.406\n\nx=7.4$

b) We have a triangle with side lengths 5.1 m and 12.3 m. These sides correspond to a and c, so b will be x.

Now, we can plug these values into the equation and solve for x.

$(5.1)^2+x^2=(12.3)^2\n\n26.01+x^2=151.29\n\nx=√(151.29-26.01)\n\nx=√(125.28)\n\nx=11.193\n\nx=11.2$

Answer:

Step-by-step explanation:

Formula: A squared + B squared = C squared

For the first question:

4.2 squared = 17.64

6.1 squared = 37.21

17.64+37.21 = 54.85

C squared = 54.85

The square root of 54.85 = 7.4

So, x = 7.4 m

For the second question:

5.1 squared = 26.01

12.3 squared = 151.29

26.01 + 151.29 = 177.3

C squared = 177.3

The square root of 177.3 = 13.3

So, x = 13.3 m

Hope this helps!

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HELP ASAP I NEED THIS DONE.