Angle ADB Is 3 Times Larger Than Angle BDC Mangle ADB= 。 _ Mangle BDC= 。 _ D

Answers

Answer 1

Answer: This is your answer. Thanks!

Answer 2

Answer:

Final answer:

Angle ADB is 3 times larger than angle BDC. By assigning a variable to BDC, an equation can be formed to find the values of both angles. BDC is 45 degrees and ADB is 135 degrees.

Explanation:

The given problem states that angle ADB is 3 times larger than angle BDC. Let's assign a variable to angle BDC, such as x degrees. Since angle ADB is 3 times larger, it would be 3x degrees. The sum of angle ADB and angle BDC is equal to 180 degrees, as they form a straight line.

Therefore, we can write the equation 3x + x = 180 to represent the sum of the angles.

Simplifying the equation, we get 4x = 180. Dividing both sides by 4, we find that x = 45 degrees. Hence, angle BDC is 45 degrees and angle ADB is 3 times larger, resulting in 3 * 45 = 135 degrees.

Learn more about angle relationships here:

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Suppose your gasoline tank holds 18 gallons of fuel. Your tank is currently 20% full. How many gallons of fuel do you need to add to fill the tank?

Answers

I believe the answer is 14.4 gallons of fuel.
To get the answer, I did x over 18 = 20% of 100. You cross-multiply to get 100x = 360. Divide each side by 100 to get x = 3.6. Subtract that from 18 gallons to get your answer.

If u have a coulculater do 18 times .20 and that will give u the answer

2. The height of a triangle is 5 m less than its base. The area of the triangle is 42 m2. Find the length of the base.(Points : 1)

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Let's start with what we know

Area:
$42 = (1)/(2)bh$ where 42 is the area, b = base, and h = height

Height:
Since we know the height is 5 less than the base, we can write that as an equation.
$h = b - 5$

Now let's go and plug $h = b - 5$ into $42 = (1)/(2)bh$

$42 = (b)/(2)(b-5)$
Let's distribute b over (b-5)

$42 = ( b^(2) - 5b )/(2)$
Let's move 42 over to the right side to make a quadratic formula

$0 = (1)/(2) b^(2) - (5)/(2)b - 42$

Let's plug that into the quadratic equation, which is:

$\frac{-b +/- \sqrt{ b^(2) - 4ac } }{2a}$
And we can now plug the pieces in to calculate b

$\frac{- (-(5)/(2)) +/- \sqrt{ (-(5)/(2))^(2) - 4 ((1)/(2))(-42) } }{2 ((1)/(2)) }$
$\frac{(5)/(2) +/- \sqrt{ (25)/(4) +84 } }{1 }$
${(5)/(2) +/- \sqrt{ (361)/(4) } }$
${(5)/(2) +/- { (19)/(2) }$
Since we can't have a negative value for b (a base can't be negative meters), let's add:

${(5)/(2) + { (19)/(2) }$
${ (24)/(2) }$
$12 = b$

So the base of the triangle is 12m

Answer:

took the quiz and it is correct the answer is 12

Why does it help to write a subtraction problem as an addition problem

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If you are doing negative subtraction it makes it addition automatically which helps to just add instead of reverse subtraction

Answer: If you are doing negative subtraction it makes it addition automatically which helps to just add instead of reverse subtraction

Step-by-step explanation:

Solve. 10/3x + 4/3 = 7+x/2x
A) X = 1/3
B) X = 17/5x
C) X = 1/5
D) X = 1/6

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well multiply both sides by 6x and you get 20+ 8x = 21 + 3x. so x=1/5 so (C)

What does m and b stand for in y=mx+b?

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B is where the line crosses the y axis

its called slope-intercept form. m is the slope where the lines cross and b is the y- coordinate of the y-intercept.

In the figure below, m < 1 = 26° and m < 2 = 28°
Find m< WXZ.

m