the metal iridium becomes superconducting at temperatures below . calculate the temperature at which iridium becomes superconducting in degrees celsius. be sure your answer has the correct number of significant digits.

Answers

Answer 1
Answer:

Answer:

Iridium becomes superconducting at extremely low temperatures, and its critical temperature (Tc) for superconductivity is approximately 0.11 Kelvin (K), or 0.11°C.

Explanation:

Given that the critical temperature is given to two significant digits (0.11), your answer should also have two significant digits. Therefore, the temperature at which iridium becomes superconducting is approximately 0.11°C.


Related Questions

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What region of the atom contains most of the atoms mass?

Answers

Answer:

Nucleus

Explanation: it is the center of the atom, and contains protons and nuetrons

Consider the two facts below:Fact 1: Dissolved oxygen is one of the most
important nutrients needed by fish in the aquatic
environment to survive.
Which scenarios may be explained by the facts on
the left? Check all that apply.
ID There is more dissolved oxygen in colder
waters than in warm water.
IM
Fact 2: Unlike solids, whose solubility increases
with increasing temperature, the solubility of gases
generally decreases with increasing temperature.
IND
There is less dissolved oxygen in colder
waters than in warm water.
Fish life in the ocean is more abundant during
the seaons with warmer water than seasons
with cooler water
HII
If ocean temperatures rise, then the risk to
the fish population increases.
DONE W

Answers

Answer:

A. There is more dissolved oxygen in colder waters than in warm water.

D. If ocean temperature rise, then the risk to the fish population increases.

Explanation:

Conclusion that can be drawn from the two facts stated above:

*Dissolved oxygen is essential nutrient for fish survival in their aquatic habitat.

*Dissolved oxygen would decrease as the temperature of aquatic habit rises, and vice versa.

*Fishes, therefore, would thrive best in colder waters than warmer waters.

The following are scenarios that can be explained by the facts given and conclusions arrived:

A. There is more dissolved oxygen in colder waters than in warm water (solubility of gases decreases with increase in temperature)

D. If ocean temperature rise, then the risk to the fish population increases (fishes will thrive best in colder waters where dissolved oxygen is readily available).

Answer: the answers are A and D

Explanation:

i got it right

Physical signs of stress typically include ________.a. Stomach growling
b. Tense muscles
c. Tickling sensation
d. All of the above

Answers

This answer was pretty obvious, if you think about it....Your answer is B.

if measurements of a gas are 75l and 300 kilopascals and then the gas is measured a second Time and found to be 50L describe what had to happen to the pressure

Answers

In this problem, the ideal gas equation PV=nRT is applied. In this relationship, volume is inversely proportional to pressure. Hence, pressure increases when volume decreases, vice versa. In this case, volume is decreased from 75 to 50 L, so the pressure is expected to increase above 300 kilopascals.

Enter the the ksp expression for the solid ab2 in terms of the molar solubility x.

Answers

The Ksp Expression for the given solid in molar solubility terms is; Ksp = 4x³

What is the expression of Molar Solubility?

Ksp is simply defined as solubility product constant and it is the equilibrium expression for the dissolving of a solid.

Now, the solid ab₂ dissolved as shown in the formula;

ab₂(s) → a(aq) + 2b(aq)

Thus, the equilibrium constant is;

Ksp = ([a][b]²)/[ab₂]

Now, since the solids are not put into the equation as a result of not having enough concentration, it can be simplified to;

Ksp = [a][b]².  

Now, Molar solubility another term for molarity and as such it means we will say; x = a

Since b = 2x, there is twice the amount of b than a and as such we can write a and b in terms of x to get;

Ksp = [x][2x]² = 4x³

Read more about Molar Solubility at; brainly.com/question/9732001

Ksp is the equilibrium expression for the dissolving of a solid. The solid ab2 dissolved with the formula ab2(s)-->a(aq)+2b(aq) so the equilibrium comstant is K=([a][b]^2)/[ab2] and since solids are not put into the equation due to the fact that solids don't really have a concentration, it simplifies to K=[a][b]^2. Since Ksp is is how much solute can dissolve at equilibrium Ksp=[a][b]^2. Molar solubility is just another way of saying molarity so if you make x=a you know that b=2x since there is twice the amount of b than a. With those values for a and b in terms of x you can make Ksp=[x][2x]^2 which means that Ksp=4x^3. I hope that helps. Let me know if anything is unclear.

A patient is given 0.050 mg of technetium-99 m (where m means metastable—an unstable but long-lived state), a radioactive isotope with a half-life of about 6.0 hours.How long until the radioactive isotope decays to 1.3×10−2 mg ?

Answers

The correct answer is 9.6h.

As you know, a radioactive isotope's nuclear half-life tells you exactly how much time must pass in order for an initial sample of this isotope to be halved.

Using the formula , A = Ao.1/2^n

where , A- final mass after decay

Ao - initial mass

n - the number of half-lives that pass in the given period of time

Now, putting all the values, we get

1.3 × 10^-2 mg = 0.050 mg × 1/ 2^n

Take the natural log of both sides of the equation to get,

(1.3 . 10^(-2) / 0.050 ) = ㏑((1/2)^(n))

(1.3 . 10^(-2) / 0.050 ) = n. ln(1/2)\n

n = 1.6

Since n represents the number of half-lives that pass in a given period of time, you can say that

n = t /  t _(1/2)

t= 1.6 × 6 h

t = 9.6h
Hence, it will take 9.6 h  until the radioactive isotope decays.

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Final answer:

Using the formula for radioactive decay and the provided half-life of technetium-99m, it can be calculated that it takes approximately 28.5 hours for 0.050 mg of technetium-99m to decay to a quantity of 1.3 x 10^-2 mg.

Explanation:

The decay of a radioactive isotope is an exponential process based on the half-life, which is, in turn, constant for any given isotope. The general formula for the remaining quantity of a radioactive isotope after a given time is given by: N = N0 (0.5) ^(t/t1/2), where (N0) is the initial amount, (N) is the remaining amount, (t) is time, and (t1/2) is the half-life of the isotope. In this case, we are given the initial quantity (N0 = 0.050 mg), the remaining quantity (N = 1.3 x 10^-2 mg), and the half-life (t1/2 = 6.0 hours).

We can solve for time (t) in the equation: N = N0 (0.5) ^(t/t1/2). Plugging in the values, we get 1.3 x 10^-2 = 0.050 x (0.5)^(t/6), and solving for t, we find that it takes approximately 28.5 hours for the technetium-99m to decay to 1.3 x 10^-2 mg.

Learn more about Radioactive Decay here:

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