MATHEMATICS HIGH SCHOOL

Which of the following is the value of 'm' in the equation 2m - 12 = 6?

Answers

Answer 1

Answer:

m = 9

Step-by-step explanation:

Given equation : 2m - 12 = 6

To calculate : value of m

$2m - 12 = 6$

Add 12 on both sides,

$2m - 12 + 12 = 6 + 12$

$2m = 18$

Divide both sides by 2,

$m = 9$

Hence the value of m is 9.

Answer 2

Answer:

Solving equations

----------------------------------------------------

Let's solve the problem given to us today! The problem is :

$\mapsto\quad\bf{2m-12=6}$

We need to find the value of m by solving this equation.

-----------------------------------

In order to solve for m, begin by adding 12 to both sides:

$\mapsto\quad\bf{2m=18}$

Then, to get your answer, divide both sides by 2 :

$\mapsto\quad\bf{m=9}$

Therefore, m = 9.

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1,574/18 Long Division Please And Thank You

Answers

87.4
______
18 | 15740
144
--------
134
126
----------
80
72
--------
8
this is gonna just keep repeating....so ur answer is 87.444.....or 87 4/9

Hello there.

1,574/18 Long Division Please And Thank You

87.444

Solve the formula for the indicated variable c=yt+y,for t (the solution is t=___)

Answers

C=yt+y. Divide both sides by y and u get c/y=t+1 subtract 1. The ANSWER IS c/y-1=t

albert tilman wishes to buy a house selling for $90,000. his credit union requires him to make a%15 down payment . the current mortage rate is 10.0% .Find the required down payment and the total monthly payment for a 30 year loan

Answers

$the\ current\ mortage\ rate\ is\ 10.0\%\n\nthe\ value\ of\ mortgage\ is\ \$90,000+10\%\cdot\$90,000=\$99,000\n\nthe\ required\ down\ payment\ 15\%:\n\n\ \ \rightarrow\ \ 15\%\ of\ \$99,000=0.15\cdot\$99,000=\$14,850\n\n the\ total\ monthly\ payment\ for\ a\ 30\ year\ loan:\n\n \frac{\big{\$99,000-\$14,850}}{\big{30\cdot12}} =\frac{\big{\$84,150}}{\big{30\cdot12}} =\$233.75$

The diameter of a circle has endpoints whose coordinates are R(-2, 2) and S(4, 2). what is the length of the radius?

Answers

Answer: 3 units

Step-by-step explanation:

Using distance formula :

$√((x_2-x_1)^2+(y_2-y_1)^2)$

The diameter of the circle with endpoints R(-2, 2) and S(4, 2) will be

$d=√((4+2)^2+(2-2)^2)=√(36)=6\ units$

Since, the radius of a circle is half of the diameter.

Then the radius of the circle will be

$r=(d)/(2)=(6)/(2)=3\ units$

Hence, the radius of the circle = 3 units.

Answer:

the answer is 3

Step-by-step explanation:

Compare partial products and regrouping. describe how the methods are alike and different

Answers

Partial product multiplication is the process of multiplying the numbers partially (respectively to ones, tens and hundreds) and adding them together in the end. For example, in order to find the product of 3 8 × 6 we should write that,
1) 3 8
× 6
___
4 8

2) 3 8
× 6
_____
4 8
1 8 0

3) 3 8
× 6
______
+ 4 8
1 8 0
______
2 2 8

Regrouping is the multiplication process when we add the partial products to the next tens and hundreds and so on without writing them down. For example, in order to find the product of 3 8 × 6 with the help of regrouping, we write that
4
3 8
× 6
___
228
, where the number 4 above 8 shows the tens of 4 (40), which is going to be added to the tens of the product of 30 times 6. The two processes are the same in a way that you are getting the same result. In the end, it is a multiplication process. The processes differ because of the methods we apply. In partial product multiplication, we break down the number in its ones, tens, hundreds steps and then calculate. However, in regrouping process we consider those steps without breaking them down.

Partial products and regrouping are similar in breaking down complex calculations but differ in their application, partial products for multiplication and regrouping for addition/subtraction and methods partial products involve multiplying digits while regrouping involves carrying or borrowing digits.

Given that,

Compare partial products and regrouping.

Now, Partial products is a multiplication method where you break down a larger multiplication problem into smaller, more manageable parts.

Multiply each digit of one number by each digit of the other number and then add up all the partial products to get the final answer.

For example, if you were to multiply 23 by 45 using partial products, you would multiply 2 by 4, then 2 by 5, then 3 by 4, and finally 3 by 5.

Then, add up all these partial products to get the final result.

Now, Regrouping is a method used in addition and subtraction when the sum or difference of two digits is greater than 9.

In regrouping, carry the extra value to the next place value or borrow from the next place value to ensure an accurate calculation.

For example, if you were to add 78 and 65, you would regroup when adding the units digit (8 + 5 = 13).

Then, carry the 1 to the tens place and add it to the sum of the tens digits (7 + 6 + 1 = 14).

Now, compare the two methods:

Alike: Both partial products and regrouping involve breaking down larger problems into smaller, more manageable parts.

They both help in simplifying complex calculations and finding accurate results.

Different: Partial products are specifically used for multiplication while regrouping is mainly used in addition and subtraction.

Partial products involve multiplying each digit to get partial results, while regrouping involves carrying or borrowing digits to ensure accuracy in calculations.

Learn more about the multiplication visit:

brainly.com/question/10873737

#SPJ6

I need help with this question

Answers

With all due respect, I'm guessing that you're fine with the question,
but you could use some help on the answer. Am I right ?

-- The answer has something to do with the total amount the coach spent,
so we'll need to know that amount. Let's find it now:

(9 chickens) x ($5 each) = $45 for chicken
(15 burgers) x ($6 each) = $90 for burgers

Total amount he spent: ($45 + $90) = $135 all together ( nice coach ! )

What part of it was used for the chickens ?
Remember, he spent $45 for chickens.

$45 / $135 = 1/3 = 0.33333.... = ( 33 and 1/3 ) percent

Now I'm wondering ... it doesn't say anywhere in the problem ...
do you think he gave any of that food to the team ?

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