A car accelerates uniformly from rest to a speed of 10 meters per second in2 seconds. The acceleration of the car is
A 0.2 m/sec²
B 5 m/sec²
C10 m/sec²
D 20 m/sec2
An object starting from rest accelerates at a rate of 3.0 meters/seconds squared for
the obiect at the end of this time is

Answers

Answer 1
Answer:

Answer:

Let's solve these two problems step by step:

1. The acceleration of the car:

You can use the formula for acceleration, which is:

\(a = {v - u}/{t})

where:

- \(a\) is acceleration,

- \(v\) is final velocity (10 m/s in this case),

- \(u\) is initial velocity (0 m/s since the car starts from rest), and

- \(t\) is time (2 seconds).

Plugging in the values:

\(a = {10 m/s - 0 m/s}/{2 s} = {10 m/s}/{2 s} = 5 m/s²)

So, the acceleration of the car is 5 m/s², which corresponds to option B.

2. The final velocity of an object starting from rest with an acceleration of 3.0 m/s² after a certain time:

You can use the following kinematic equation:

\(v = u + at)

where:

- \(v\) is the final velocity (which you want to find),

- \(u\) is the initial velocity (0 m/s since it starts from rest),

- \(a\) is the acceleration (3.0 m/s²), and

- \(t\) is the time (you haven't provided this value).

If you provide the value of time, I can calculate the final velocity for you.


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Answers

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:

In this exercise we have to use the knowledge of finance to calculate the  profits that Korey expect to make is $15,149.72.

So organizing the information given in the statement we find that:

  • average $1,000 of profit
  • 6% each year for the next 4 years

Doing these calculations we find that:

1000*12 = $12,000\n12,000 * 1.06^1\n12,000 * 1.06^2\n12,000 * 1.06^3\n12,000 * 1.06^4 =$15,149.72

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