MATHEMATICS HIGH SCHOOL

Suppose that X and Y have the following joint probability function: f(x,y) = { 3x, | 32, if 0 ≤ y ≤1 0, otherwise. a) Find the variance of the random variables X. b) Find the conditional PDF of Y given X.

Answers

Answer 1

Answer:

Answer:

see below

Step-by-step explanation:

a) The variance of random variable X is

−

b) The conditional PDF of Y given X is:

For

≤

�

≤

0≤y≤1,

�

(

�

∣

�

)

f(y∣x)=1.

For

�

y outside the range [0, 1],

�

(

�

∣

�

)

f(y∣x)=0.

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Given the function rule f(x) = x^2 - 3x + 2, what is the output of f(-2)

Answers

Answer:

The output value of f(-2) is, 14

Step-by-step explanation:

Given the function:

$f(x) = x^2-3x+2$ ......[1]

We have to find the output of f(-2).

Substitute x = -2 in [1] we have;

$f(-2) = (-2)^2-3(-2)+2$

⇒ $f(-2) = 4+6+2$

Simplify:

$f(-2) = 12$

therefore, the output value of f(-2) is, 12

f(-2) = -2 ^ 2 - 3 * -2 + 2
f(-2) = 4 - (-6) + 2
f(-2) = 10 + 2
f(-2) = 12

Fill on the other coordinate for the line 2x-3y=4 (2,)

Answers

For the first coordinate they have given it to you, so plug it in to get the y coordinate.
2x -3y = 4
2 * 2 - 3y = 4
4 - 3y = 4
4 - 4 - 3y = 4 - 4
-3y = 0
-3y/-3 = 0/-3
y = 0
(2, 0)
To find another set of coordinate to form a line, all you have to do is put in an x value that would make the line true.
2x -3y =4
2 * 8 - 3y = 4
16 - 3y = 4
16 - 16 -3y = 4 - 16
-3y = -12
-3y/-3 = -12/-3
y = 4

for this question we have:
(2, y)
and we know:
2x -3y = 4
so the only thing u need is to put 2 for x and find y:
2(2) - 3y = 4
4 - 3y = 4
-3y = 0
y =0 :)))
I hope this is helpful
have a nice day

If square root 10 = 3.162 ,then the value of 1/square root 10 is 0.3162. prove it

Answers

$√(10)\approx3.162\n\n(1)/(√(10))=(1)/(√(10))\cdot(√(10))/(√(10))=(√(10))/(10)\approx(3.162)/(10)=0.3162$

Help asap

A -1/3
B 3
C 1/3
D -3