MATHEMATICS HIGH SCHOOL

3x−8y+44=0 7x=12y−56

Answers

Answer 1

Answer:

Answer:

(4, 7 )

Step-by-step explanation:

given the 2 equations

3x - 8y + 44 = 0 → (1)

7x = 12y - 56 ( subtract 12y - 56 from bpth sides )

7x - 12y + 56 = 0 → (2)

multiplying (1) by 7 and (2) by - 3 and adding the result will eliminate x

21x - 56y + 308 = 0 → (3)

-21x + 36y - 168 = 0 → (4)

add (3) and (4) term by term to eliminate x

(21x - 21x) + (- 56y + 36y) + (308 - 168) = 0

0 - 20y + 140 = 0 ( subtract 140 from both sides )

- 20y = - 140 ( divide both sides by - 20 )

y = 7

substitute y = 7 into either of the 2 orinal equations and solve for x

substituting into (1)

3x - 8(7) + 44 = 0

3x - 56 + 44 = 0

3x - 12 = 0 ( add 12 to both sides )

3x = 12 ( divide both sides by 3 )

x = 4

solution is (4, 7 )

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Determine whether the system of linear equations has one and only one solution, infinitely many solutions, or no solution. Find all solutions whenever they exist.x+3y=9
3x-y=7

Answers

$\left \{ {{x+3y=9~(3)} \atop {3x-y=7(-1)}} \right. \n \n \left \{ {{3x+9y=27} \atop {-3x+y=-7}} \right. \n \n10y=20\n \ny= (20)/(10) \ny=2$

$x+3y=9\nx=9-3y\nx=9-3.2\nx=3$

$S=\{3,2\}$

One solution.

$x+3y=9\n 3x-y=7\ / \cdot 3\n \n x+3y=9\n 9x-3y=21\n \n 10x=30\ /:10\n x=3\n \n x+3y=9\n 3+3y=9\n 3y=6\n y=2\n one\ solution - (3;2)$

8k-1=15 ? Help I have a question were we have to work this out what do I do?

Answers

$8k-1=15\ \ \ \ /+1\n\n8k-1+1=15+1\n\n8k=16\ \ \ \ /:8\n\n8k:8=16:8\n\nk=2$

you have to add 1 to the -1 and you will get 0.What you have to do next is also add 1 to 15 because you want a variable on one side and a number on the other.So now you have 8k=16. So you divide 8 to 8k and you get nothing divide 8 and 16 and your answer for k =2 hope you get it right.trust mw it is very easy when you get use to it

What are the vertex and x-intercepts of the graph of the function below? y =(x + 4)(x - 2)

Answers

y = (x + 4)(x - 2)

The x-intercepts:

0 = x + 4
0 = x - 2

x = -4
x = 2

The vertex:

y = (x + 4)(x - 2)
y = x^2 + 2x - 8
x = -b/2a
If ax^2 + bx + c, then:
a = 1
b = 2
c - 8
x -2/2(1)
x = -1
y = (-1)^2 + 2(-1) - 8
y = -9

The vertex is (-1, -9)
The x-intercepts are -4 and 2

Answer: vertex: (1,-9); intercepts: x=4,-2

Step-by-step explanation:

Just got it wrong on ap3x so I could give y’all the right answer

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