Use disability rules to determine whether the number is divisible by 2,3,5,6,9,10. 1044

Answers

Answer 1
Answer:

Answer:

Step-by-step explanation:

1044 is an even number so it is divisible by 2.

1+0+4+4= 9 , 9 is divisible by 3 so 1044 is divisible by 3.

1044 is not having 0 or 5 in unit digit so it is not divisible by 10 and 5.

1044 is divisible by 2 and 3 so it will be divisible by 6.


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Money adding how to do it

Simplify showing all steps:
4i( (1)/(2)i)^2(-2i)^2

Answers

we know that i=√-1
so we do pemdas
(1)/(2) i=( √(-1) )/(2)
exponents
( ( √(-1) )/(2) )^(2)= (( √(-1) )^(2))/(2^(2))=(-1)/(4)
then (-2i)^(2)=-2 times -2 times i times i=4 times -1=-4
now we have

4i( (-1)/(4) )(-4)=( (-4i)/(4) )(-4)=( -i)(-4)=4i=aprox 4√-1

the answer is 4i

What characteristics best describe the graph? Choose all that apply. *

Answers

Answer:

Options (1), (3) and (7)

Step-by-step explanation:

Characteristics of the given graph are as followed.

1). For every input value (x-value) there is a different output values (y-values).

   So the points on the graph represent a function.

2). Coordinates of all the points are distinct and separate (not in fractions or decimals).

    Function given is a discrete function.

3). For every increase in the x-values of the points there is a decrease in y-values.

  Therefore, given function is a decreasing function.

Therefore, Options (1), (3) and (7) are the correct options.

Find the two geometric means between 20 and 2500

Answers

Answer:

The two geometric means between 20 and 2500 are 100 and 500.

Step-by-step explanation:

First of all we all should know about a geometric progression to solve this question.

A geometric progression is a series in which there is a first term a and all the next terms are calculated by multiplying the previous term by a common number r.

where a is known as first term and

r is known as common ratio.

In the question we are given a as 20 and we have to find out 2 terms after 20 and 4th term is given as 2500.

Formula for n^(th) term in a geometric progression is:

a_(n)  = a* r^(n-1)

Here a_(4) = 2500

As per formula of n^(th) term:

a* r^(3) = 2500\n\Rightarrow 20 * r^(3) =2500\n\Rightarrow r^(3) = 125\n\Rightarrow r = 5

Now, 2nd term:

a_(2) = a * r\n\Rightarrow a_(2) = 20 * 5\n\Rightarrow a_(2) = 100

Now, 3rd term:

a_(3) = a * r^(2) \n\Rightarrow a_(3) = 20 * 5^(2)\n\Rightarrow a_(3) = 500

So, the two geometric means between 20 and 2500 are 100 and 500.

How many solutions are there to the equation below? 6x + 30 + 4x=10(x + 3) a. 0 b. infinetely many c. 1

Answers

Answer:

b

Step-by-step explanation:

given

6x + 30 + 4x = 10(x + 3) ← collect like terms on left side

10x + 30 = 10(x + 3) ← distribute parenthesis by 10

10x + 30 = 10x + 30

since both sides are the same , then any value of x will make the equation true.

The equation has infinitely many solutions

The square of a number is equal to 10 less than 7 times that number. What are the two possible solutions?Which of the following equations is used in the process of solving this problem?
x^2 - 7x + 70 = 0
x^2 - 7x + 10 = 0
x^2 + 7x - 10 = 0

Answers

x^2 = 7x - 10
x^2 - 7x + 10 = 0
(x - 5)(x - 2) = 0
x = 5 or x = 2

The answer is B.

Answer:

b

Step-by-step explanation:

Solve the following problem first using a tape diagram and then using an equation: In a school choir, 1/2 of the members were girls. At the end of the year, 3 boys left the choir, and the ratio of boys to girls became 3:4. How many boys remained in the choir?

Answers

Answer: 9 boys remained in the choir.

Step-by-step explanation:

Let x be the number of of boys and y be the number of girls.

In a school choir, 1/2(half) of the members were girls.

i.e x=y  (1)

At the end of the year, 3 boys left the choir, and the ratio of boys to girls became 3:4.

(x-3)/(y)=(3)/(4)\n\n\Rightarrow\ 4(x-3)=3(y)\n\n\Rightarrow\ 4x-12=3y  

Put y= x from (1), we get

4x-12=3x\n\n\Rightarrow\ 4x-3x=12\n\n\Rightarrow\ x=12

Thus , the number of boys : x= 12

Boys remained in the choir = 12-3=9