CHEMISTRY HIGH SCHOOL

The molarity of a solution of 5.0 g of KCl in 100. mL of solution is ________. A) 0.038 M B) 0.067 M C) 0.67 M D) 0.13 M E) 1.3 M

Answers

Answer 1

Answer:

Answer:

$\huge{ \boxed{0.67 \: \text{M}}}$

Explanation:

The molarity of the solution can be found by using the formula:

$c = (m)/(M * v)$

c is the concentration in M , mol/dm³ or mol/L

v is the volume in L or dm³

m is the mass in grams

M is the molar mass in g/mol

From the question;

mass = 5 g

Molar mass (M) of KCl = 39 + 36.5 = 75.5 g/mol

Since the volume is in mL it has to be converted to litres.

$1000ml = 1l \n \therefore \: 100ml = (100ml)/(1000ml) * 1l \n = 0.1l$

v = 0.1 L

$\therefore \: c = (5)/(75.5 * 0.1) \n = 0.67 \:$

We have the final answer as;

0.67 M

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Newton’s first law of motion was a giant leap forward in scientific thought during Newton’s time. Even today, the idea is sometimes difficult at first for people to understand.

Answers

The correct answer for the question that is being presented above is this one: "A rolling ball eventually slows down and comes to a stop." Newton’s first law of motion was a giant leap forward in scientific thought during Newton’s time. Even today, the idea is sometimes difficult at first for people to understand.

Quantitative was to measure light intensity

Answers

One candela per steradian is termed a lumen, which is the measure of light intensity people are most familiar with One foot candle is equivalent to one lumen per square foot

whats the question tho??

The following balanced equation shows the decomposition of water (H2O). According to the equation, how many oxygen atoms are in the reactants? 2 H2O 2H2 + O2

Answers

Answer : The number of oxygen atoms present on reactant side are, 4

Explanation :

Balanced chemical reaction : It is defined as the number of atoms of individual elements present on reactant side must be equal to the product side.

Decomposition reaction : It is defined as the reaction in which the larger molecule decomposes to give two or more smaller molecules as a product.

The given balanced chemical reaction is,

$2H_2O\rightarrow 2H_2+O_2$

From the balanced chemical reaction we conclude that, there 4 atoms of hydrogen and 2 atoms of oxygen present on both reactant side and product side.

Hence, the number of oxygen atoms present on reactant side are, 4

2 atoms of oxygen are reactants.

Which solution has the same boiling point as 0.25 mol CaCl2 dissolved in 1000 g water?Help Please, Thanks!

0.75 mol sucrose dissolved in 1000 g water
1.0 mol ethylene glycol dissolved in 1000 g water
0.50 mol CaCl2 dissolved in 1000 g water
0.25 mol NaCl dissolved in 1000 g water

Answers

The boiling point of water at 1 atm is 100 degrees celsius. However, when water is added with another substance the boiling point of it rises than when it is still a pure solvent. This called boiling point elevation, a colligative property. The equation for the boiling point elevation is expressed as the product of the ebullioscopic constant (0.52 degrees celsius / m) for water), the vant hoff factor and the concentration of solute (in terms of molality).

ΔT(CaCl2) = i x K x m = 3 x 0.52 x 0.25 = 0.39 °C
ΔT(Sucrose) = 1 x 0.52 x 0.75 = 0.39 °C
ΔT(Ethylene glycol) = 1 x 0.52 x 1 = 0.52 °C
ΔT(CaCl2) = 3 x 0.52 x 0.50 = 0.78 °C
ΔT(NaCl) = 2 x 0.52 x 0.25 = 0.26 °C

Thus, from the calculated values, we see that 0.75 mol sucrose dissolved on 1 kg water has the same boiling point with 0.25 mol CaCl2 dissolved in 1 kg water.

Which substance will combine with oxygen gas to produce a greenhouse gas? a. Na
b. S
c. H₂
d. Ne
e. C

Answers

The substance that combined with the oxygen to form a greenhouse gas has been carbon (C). Thus, option E is correct.

The greenhouse gases have been responsible for the entrapment of the sun's energy in the atmosphere, leading to the increase in the temperature of earth and making earth an appropriate place to live.

The greenhouse gases have been the carbon dioxide, methane, sulfur etc. that are able to entrap the energy.

The reaction of carbon with oxygen has been resulted in the formation of carbon dioxide. It has been a green house gas.

Thus, the substance that combined with the oxygen to form a greenhouse gas has been carbon (C). Thus, option E is correct.

For more information about greenhouse gas, refer to the link:

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Carbon (C) will react with oxygen (O2) to produce CO2 (carbon dioxide) which is a greenhouse gas

What mass of magnesium bromide is formed when 1.00 g of magnesium reacts with 5.00 g of bromine?

Answers

Answer:

when 1.00 g of magnesium reacts with 5.00 g of bromine, approximately 7.57 g of magnesium bromide is formed.

Explanation:

To find the mass of magnesium bromide formed when 1.00 g of magnesium reacts with 5.00 g of bromine, you need to first write a balanced chemical equation for the reaction between magnesium and bromine. The balanced equation for the formation of magnesium bromide (MgBr2) is as follows:

Mg + Br2 → MgBr2

Now, you can calculate the molar mass of each substance involved in the reaction:

Molar mass of Mg (magnesium) = 24.31 g/mol

Molar mass of Br2 (bromine) = 2 * 79.90 g/mol = 159.80 g/mol

Molar mass of MgBr2 (magnesium bromide) = 24.31 g/mol + 2 * 79.90 g/mol = 184.11 g/mol

Next, calculate the number of moles for each reactant:

Moles of Mg = Mass (1.00 g) / Molar mass (24.31 g/mol) = 0.0411 moles

Moles of Br2 = Mass (5.00 g) / Molar mass (159.80 g/mol) = 0.0313 moles (approximately, rounded to four decimal places)

Now, determine the limiting reactant. To do this, compare the mole ratio between Mg and Br2 in the balanced equation. The balanced equation shows that 1 mole of Mg reacts with 1 mole of Br2. Therefore, the limiting reactant is the one that is present in the smaller amount relative to the balanced equation's stoichiometry.

In this case, magnesium (0.0411 moles) is present in a smaller amount than bromine (0.0313 moles). So, magnesium is the limiting reactant.

Now that you know magnesium is the limiting reactant, you can calculate the mass of magnesium bromide formed using the stoichiometry of the balanced equation. According to the balanced equation, 1 mole of Mg produces 1 mole of MgBr2.

Moles of MgBr2 formed = Moles of Mg (limiting reactant) = 0.0411 moles

Now, calculate the mass of magnesium bromide formed:

Mass of MgBr2 = Moles of MgBr2 × Molar mass of MgBr2

Mass of MgBr2 = 0.0411 moles × 184.11 g/mol = 7.57 g

So, when 1.00 g of magnesium reacts with 5.00 g of bromine, approximately 7.57 g of magnesium bromide is formed.

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