Is the following sentence true or false? The lower the ionization energy, the easier it is to remove an electron from an atom. A. True B. False

Answers

Answer 1
Answer:

Answer: It is True

Explanation:Because  Ionization energy refers to the amount of energy required to remove an electron from an atom.


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A combustion reaction took place each time you used the Bunsen burner to burn methane gas (CH4). Write a balanced chemical equation for the combustion of methane. *HINT: All hydrocarbon combustion reactions need oxygen as a reactant and form the same two products.

Answers

Answer:

The answer to your question is    CH₄ + 2O₂  ⇒  CO₂  +  2H₂O

Explanation:

Data

Methane = CH₄

Oxygen = O₂

Process

A combustion reaction is a kind of chemical reaction in which an organic compound reacts with oxygen to generate water and carbon dioxide.

Chemical reaction

                   CH₄ + O₂  ⇒  CO₂  +  H₂O

             Reactants   Elements    Products

                    1                   C                1

                    4                  H                2

                    2                  O                3

Balanced chemical reaction

                   CH₄ + 2O₂  ⇒  CO₂  +  2H₂O

             Reactants   Elements    Products

                    1                   C                1

                    4                  H                4

                    4                  O                4

Final answer:

The balanced chemical equation for the combustion of methane is CH4 + 2O2 -> CO2 + 2H2O. This equation shows that a methane molecule reacts with two oxygen molecules to produce a carbon dioxide molecule and two water molecules while maintaining a balance as per the Law of Conservation of Mass.

Explanation:

The combustion of methane occurs when methane gas (CH4) combines with oxygen (O2) to produce carbon dioxide (CO2) and water (H2O). This reaction can be represented by the following balanced chemical equation:

CH4 + 2O2 -> CO2 + 2H2O

This means that one molecule of methane reacts with 2 molecules of oxygen to produce one molecule of carbon dioxide and two molecules of water. The chemical equation is balanced, meaning that the number of atoms of each element is the same on both sides of the equation as required by the Law of Conservation of Mass.

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An equilibrium mixture of PCl5(g), PCl3(g), and Cl2(g) has partial pressures of 217.0 Torr, 13.2 Torr, and 13.2 Torr, respectively. A quantity of Cl2(g) is injected into the mixture, and the total pressure jumps to 263.0 Torr (at the moment of mixing). The system then re-equilibrates. The appropriate chemical equation is:PCl3(g) + Cl2(g) ---> PCl5(g)

Calculate the new partial pressures after equilibrium is reestablished. [in torr]

PPCl3

PPCl2

PPCl5

Answers

equilibrium is a situation in which economic forces such as supply and demand are balanced and in the absence of external influences the values of economic variables will not change

The equilibrium constant depends on the following:-

  • Pressure
  • Volume

The formula used in the question is as follows:-

k_p = (P_1)/(P_1*P_2), After putting the value, the equilibrium constant is as follows:-

k_p = (217)/(13.2*13.2)

After solving it, the equilibrium constant is 1.245.

The pressure in different systems is as follows:-

Hence, the total pressure is:- P_1 + P_2+ P_3

263 = 13.2 + P_2 + 217

After solving it, the P2 is 32.8torr.

The equilibrium constant in the second case is:-

k_p = (P_1^')/(P_1^' * P_2^')

After putting the value,

1.245= (217+x)/((13.2-x )* (32.8-x))

After solving, the value of x is 6.402torr

Hence, the partial pressure PCL_3,\ CL2, \ PLC_5\ is 6.798, 26.398, and 223.402 respectively.

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Answer:

The new partial pressures after equilibrium is reestablished for PCl_3:

P_1'=6.798 Torr

The new partial pressures after equilibrium is reestablished Cl_2:

P_2'=26.398 Torr

The new partial pressures after equilibrium is reestablished for PCl_5:

P_3'=223.402 Torr

Explanation:

PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)

At equilibrium before adding chlorine gas:

Partial pressure of the PCl_3=P_1=13.2 Torr

Partial pressure of the Cl_2=P_2=13.2 Torr

Partial pressure of the PCl_5=P_3=217.0 Torr

The expression of an equilibrium constant is given by :

K_p=(P_1)/(P_1* P_2)

=(217.0 Torr)/(13.2 Torr* 13.2 Torr)=1.245

At equilibrium after adding chlorine gas:

Partial pressure of the PCl_3=P_1'=13.2 Torr

Partial pressure of the Cl_2=P_2'=?

Partial pressure of the PCl_5=P_3'=217.0 Torr

Total pressure of the system = P = 263.0 Torr

P=P_1'+P_2'+P_3'

263.0Torr=13.2 Torr+P_2'+217.0 Torr

P_2'=32.8 Torr

PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)

At initail

(13.2) Torr     (32.8) Torr                        (13.2) Torr

At equilbriumm

(13.2-x) Torr     (32.8-x) Torr                        (217.0+x) Torr

K_p=(P_3')/(P_1'* P_2')

1.245=((217.0+x))/((13.2-x)(32.8-x))

Solving for x;

x = 6.402 Torr

The new partial pressures after equilibrium is reestablished for PCl_3:

P_1'=(13.2-x) Torr=(13.2-6.402) Torr=6.798 Torr

The new partial pressures after equilibrium is reestablished Cl_2:

P_2'=(32.8-x) Torr=(32.8-6.402) Torr=26.398 Torr

The new partial pressures after equilibrium is reestablished for PCl_5:

P_3'=(217.0+x) Torr=(217+6.402) Torr=223.402 Torr

Which of these changes produces the greatestincrease in entropy?
(1) CaCO3(s) --> CaO(s) + CO2(g)
(2) 2 Mg(s) + O2(g) --> 2 MgO(s)
(3) H2O(g) --> H2O(l)
(4) CO2(g) --> CO2(s)

Answers

Answer:

Was this correct? I am pretty sure it is since you are going from a solid to a gas in the first reaction.

Explanation:

(1) CaCO3(s) --> CaO(s) + CO2(g) --- solid to solid & gas ** most entropy here

(2) 2 Mg(s) + O2(g) --> 2 MgO(s) solid & gas to a solid

(3) H2O(g) --> H2O(l) gas to a liquid

(4) CO2(g) --> CO2(s)   gas to a solid

As temperature rises and a substance transforms from a solid to a liquid to a gas, entropy increases. Because they have the most flexibility to move, gases have the highest entropy values. Here the first reaction has high entropy. The correct option is 1.

The level of unpredictability in a system is known as entropy. The degree of randomness is highest when comparing the three forms of matter solid, liquid, and gas because the gas particles move freely.

(1) CaCO3(s) --> CaO(s) + CO2(g) --- solid to solid & gas - most entropy here

(2) 2 Mg(s) + O2(g) --> 2 MgO(s) solid & gas to a solid

(3) H2O(g) --> H2O(l) gas to a liquid

(4) CO2(g) --> CO2(s)   gas to a solid

Thus the correct option is 1.

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if a jar of honey sits for a long time, sugar may crystallize in the jar.describe two possible cause for this crystallization?

Answers

Answer:

Temperature and humidity

Explanation:

Crystallization occurs in super saturated solution. These are the solutions that have solute to solvent ratio of 2:1 or more. Typical honey is 70% sugar and 20% water (the solute concentration is too high).  

Two things cause honey to crystallize.

  1. Temperature
  2. Humidity level

If temperature is lowered the rate of crystallization increases. This is because at low temperature the molecules of solvent come closer and the space between them reduces. This causes the additional solute molecules to be pushed up to form crystals.  

Secondly, humidity also plays a key role. If the humidity reduces, the water molecules evaporates from honey into air. This increases the relative concentration of the solute inside the honey, which causes the honey to crystallize.  

The two possible causes for crystallization in honey is 1. The condition of the room. (if the temperature keeps rising and dropping rapidly) 2. Crystallization rate also depends on the type of honey you keep in your cabinet. There are 300 different kinds of honey and each type crystalizes differently

What is the gram molecular mass of a compound if 5 moles of the compound has a mass of 100 grams?

Answers

Answer:

1 gram molecular mass of this compound = 20

Explanation:

Gram Molecular Mass is the mass of a chemical that is obtained by the number of grams in the chemical determined by the masses obtained from the periodic table and the number of mols determined from the Chemical formula.

That's quite a mouthful. Here's what it means in plain language.

Find the Gram molecular mass of C2H6

The periodic table tells us that 1 mol of C2H6 has

2 mols of Carbon which is 2*C or 2 * 12 = 24 and

6 mols of Hydrogen which is 6*H or 6*1 =  6

The gram molecular mass is 6 + 24 = 30

Your question doesn't require all that background.

5 gram molecular masses = 100 grams       Given

1 gram molecular mass   = x

5/1 = 100/x          Cross multiply

5x = 100             Divide by 5

x = 100 / 5

x = 20

                 

The gram molecular mass of a compound whose 5 moles has a mass of 100 grams would be 20 grams per mole.

The gram molecular mass of a substance is simply the mass (in gram) of 1 mole of the same substance. In other words, the gram molecular mass of a substance is also the same as the molar mass of the substance.

In this case, 5 moles of the substance weigh 100 grams

Therefore, 1 mole of the same substance would weigh:

                     1 x 100/5 = 20 grams

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If you make an electromagnet using a battery circuit and a steel nail, how can you increase its magnetic strength? A. replace the nail with a copper rod B. wrap more coils of wire around the nail C. use a longer nail D. remove the plastic insulation from the wire coil

Answers

Answer: The correct answer is "wrap more coils of wire around the nail".

Explanation:

Electromagnet:  When the current passes through iron core wounded by the coils then it will get magnetized. It is not a permanent magnet.

It will loose its magnetism  when the current does not flow in it.

The poles of the electromagnet can be changed. They are not fixed.

In the electromagnet, the strength of the magnetism can be increased or decreased by increasing the number of turns in the coil and by increasing the current.

In the given problem, If you make an electromagnet using a battery circuit and a steel nail, the magnetic strength can be increased by wrapping more coils of wire around the nails.

Therefore, the correct option is (B).

we can increase the strength of an electromagnet by wrapping more coils of wire around the nail.