Solve for x: 45>4x+9 53≤4x+9

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Answer 1

Answer:

Answer:

The system of inequalities 45 > 4x + 9 and 53 ≤ 4x + 9 doesn't have any solution, because the restrictions on x are contradictory (x can't be both less than 9 and greater than or equal to 11).

Step-by-step explanation:

These are a set of compound inequalities. Let's solve these equations step by step. The first inequality 45 > 4x + 9, we start to solve it by subtracting 9 from both sides of the inequality, which gives us 36 > 4x. Then, we divide each side by 4 to get x < 9.

The second inequality is 53 ≤ 4x + 9. We solve this by subtracting 9 from both sides to get 44 ≤ 4x. Then, we divide each side by 4 to find x ≥ 11.

However, these two results are contradictory (as x cannot be both less than 9 and greater than or equal to 11 simultaneously). So, there is no solution to this system of inequalities.

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The weights (to the nearest pound) of some boxes to be shipped are found to be: Weight 65 68 69 70 71 72 90 95 frequency 1 2 5 8 7 3 2 2 Explain why or why not this could be represented by a bell curve (a normal distribution).

Answers

The given weights do not exhibit the characteristics of a bell curve or a normal distribution. The data is skewed, lacks a clear central tendency, and contains outliers. Therefore, it cannot be accurately represented by a normal distribution.

Here, we have,

To determine whether the given weights can be represented by a bell curve (normal distribution), we need to assess if the data exhibits the characteristics of a normal distribution.

Here are a few considerations:

Symmetry: A normal distribution is symmetric, meaning the data is equally distributed around the mean. In the given data, there are more observations on one side of the distribution (higher weights) than the other. This indicates a lack of symmetry, which is not characteristic of a bell curve.

Central tendency: A normal distribution typically has a single peak or mode at the center. In this case, there isn't a clear central tendency as the weights seem to be spread across different ranges without a dominant peak.

Outliers: Normal distributions tend to have minimal outliers or extreme values. The presence of weights like 90 and 95, which are noticeably higher than the other values, suggests the presence of outliers. This goes against the assumption of a bell curve.

Based on these considerations, it appears that the given weights do not exhibit the characteristics of a bell curve or a normal distribution. The data is skewed, lacks a clear central tendency, and contains outliers. Therefore, it cannot be accurately represented by a normal distribution.

learn more on normal distribution :

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because the data is not a normal distribution because the second half of the data is too far away from the first half i think its also called unproportional or something like that feel free to add me as a friend

Y''+2y'+y=2e^(-t)
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