Find the area of blah blah blah blah blah
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Answer: hope this helps ♡
The area of blah blah blah blah blah is blah*blah LOL
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Answer:
The number is 8.
To solve this equation, we can set it up as follows:
Let x be the unknown number.
- The equation "A number increased by seven is 15" can be written as:
x + 7 = 15
- Now, to find the value of x, we need to isolate it on one side of the equation. We can do this by subtracting 7 from both sides of the equation:
x + 7 - 7 = 15 - 7
- On the left side, the +7 and -7 cancel out, leaving us with just x:
x = 15 - 7
- Now, simplify the right side of the equation:
x = 8
So, the unknown number is 8.
To write the expression, I'll follow these steps :
↠ First, I am going to choose a letter that will represent my number.
↠ Then I'll plug it into the expression, and write the rest.
STEP ONE
I'll choose d for my number.
STEP TWO
We now have : d increased by 7 is 15, which is the same thing as d + 7 = 15.
To find d, subtract 7 from both sides :
d = 15 - 7 = 8
Therefore, d = 8.
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Answer:
Step-by-step explanation:
5[2p-4(p+5)]=25
or, 2p-4(p+5)=5
or, 2p-4p-20=5
or, -2p=5+20
or, -2p=25
or, 2p=-25
or, p=25/2
so, p=12.5
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I think I conducted the equation correctly (:
f = 12.56
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It's a right triangle. So
(x²) + (10²) = (7+x)²
x² + 100 = 49 + x² + 14x
That may look ugly, but I'm pretty sure you can handle it from this point.
Wow ! I just noticed that you can subtract x² from each side
and not even have to mess with it again.
x^2
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Answer:
(D) p = 50.55 (Round to the nearest hundredth).
Step-by-step explanation:
Given: Right triangle SIP such that i = 54 and s = 19.
To find: Which of the following statements are true, round to the nearest hundredth.
Solution: We have given that Right triangle SIP , i = 54 and s = 19.
By the Pythagoras theorem (IP)²+(SI)² = (SP)².
Plugging the values
(19)²+(p)² = (54)².
361+(p)² =2916
On subtracting both side by 361.
(p)²+ 361 - 361 =2916 -361
(p)² = 2555
Taking square root both sides .
√(p)² = .
p = 50.547
p = 50.55 (Round to the nearest hundredth).
Therefore, (D) p = 50.55 (Round to the nearest hundredth).
sin S=19/54==>mes S=20.60...° A is false
cos P=19/54==>mes P=69.3993...° B is true
==> C is false
p =√(54²-19²)=50.5470...≈50.55 is true
Answer B AND D
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Answer:
its -3
Step-by-step explanation:
since the bases are equal then the powers are equal