A square has an area of 144 in2 is reduced by a factor of 1/6

Answers

Answer 1

Answer:

Answer:

If a square has an area of 144 square inches and is reduced by a factor of 1/6, it means that both the length and width of the square are multiplied by the square root of 1/6.

To find the new side length, we can take the square root of 1/6 and multiply it by the original side length.

Original side length = sqrt(144) = 12 inches

New side length = (1/6)^(1/2) * 12 inches

Simplifying the calculation:

New side length = (1/√6) * 12 inches

Now we can calculate the new side length:

New side length ≈ 3.27 inches (rounded to two decimal places)

To find the new area, we square the new side length:

New area = (3.27 inches)^2 ≈ 10.68 square inches (rounded to two decimal places)

Therefore, after reducing the square by a factor of 1/6, the new side length is approximately 3.27 inches, and the new area is approximately 10.68 square inches.

Related Questions

A number is chosen at random from the positive, even integers from 2 to 50. Find the probability that the number chosen is divisible by 5 or 8. 1/25 2/5 11/25
The slope is 2 the points are (1,1). Déterminé the equation
65% of 80 is what number
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A hallway measuring 90 feet x 7 feet requires 1/2 a fluid oz of cleaning solution per sq ft. How much cleaning solution is needed to clean the hallway?

Answers

You want area of the floor to know how many square feet you have 90x7=630 630sq. ft of floor and it takes 1/2 an oz to clean one of them 630(1/2)=315oz

A group of students is arranging squares into layers to create a project. The first layer has 4 squares. The second layer has 8 squares. Which formula represents an arithmetic explicit formula to determine the number of squares in each layer?

Answers

Answer:

answer is d

Step-by-step explanation:

Please help I need to know before tomorrow

Answers

The answer is a since 150/6 is 25

I Believe it's a (25)

Which of the following statements are true? Check all that apply For all real numbers a and b, a b b+ a For all real numbers a and b, ab ba. For all real numbers a and b, a b a For all real numbers a and b For all real numbers a, and c, (a b) c a (b c) b For all real numbers a, b and c, (a b) c a (b-c For all real numbers a, b and c, a b c) ab ac

Answers

Among the options for the property of the real numbers, are as follows, 1,2,5, and 7.

Gvien that,
Among the option, to choose the correct option which holds the property mentioned for the real numbers

What is a number system?

A number system is described as a technique of composing to represent digits. It is the mathematical inscription for describing the numbers of a given set by using numbers or other characters in a uniform method. It delivers a special presentation of every digit and describes the arithmeticstructure.

Here,

for a and b, all real number
(1)
a + b = a + b, ture

(2)
ab = ba, true

(3)
a - b ≠ b - a false

(4)
a / b ≠ b/a, flase

(5)

(a + b) + c = a + (b + c), true

(6)

(a - b) - c = a - (b - c), false

(7)

a(b + c) = ab + ac

Thus, among the options, the correctoption is as follows, 1,2,5, and 7.

Learn more about the number system here:

brainly.com/question/22046046

#SPJ2

The actual answers are 1,2,5, and 7 ik this bc i got it wrong and it said these are correct

Choose the converse of the following statement.They are not left behind, if they are on time.

If they are not left behind, then they are on time.
If they are on time, then they are not left behind.
If they are not on time, then they are left behind.
If they are left behind, then they are not on time

Answers

The converse of a statement can be found by switching the hypothesis and the conclusion (the beginning and ending statements) of a phrase.

Therefore, we started with the statement

"They are not left behind, if they are on time."

To find the converse of this statement, we just need to switch the position of the two pieces.

Therefore, the converse is

"If they are on time, then they are not left behind."

You answer is the above statement or the second option.

Activity 4: Factor Then solve1. x^2+7x=0
2. 6s^2+18s=0
3. t^+8t+16=0
4. x^2-10x+25=0
5. h^2+6h=16
6. x^2-14=5x
7. 11r+15=-2r^2
8. x^2-25=0
9. 81-4x^2=0
10. 4s^2+9=12s

PLEAAASE HELP ME!

Answers

very complex, you should ask each individual question, or give more points
general strategy:
get 1 side to equal 0
factor
set each factor to 0
solve

1. factor out the x and set each to zero
x(x+7)=0
x=0

x+7=0
subtract 7
x=-7
x=0 or -7

2. factor out the 6s
6s(s+3)=0
6s=0
s=0

s+3=0
subtract 3
s=-3
s=-3 or 0

3. I'm assuming that the equation was supposed to be t^2+8t+16 so
find what 2 numbers multiply to get 16 and add to get 8
the numbers are 4 and 4
factor
(x+4)(x+4)=0
x+4=0
subtract 4
x=-4

4. find what 2 numbers multipy to get 25 and add to get -10
the numbers are -5 and -5
factor
(x-5)(x-5)=0
set each to zero
x-5=0
add 5
x=5

5. subtract 16 from both sides
h^2+6h-16=0
find what 2 numbers multiply to get -16 and add to get 6
the numbers are -6 and 10
factor
(h-6)(h+10)=0
set each to zero
h-6=0
add 6
h=6

h+10=0
subtract 10
h=-10
h=-10 or 6

6.subtract 5x from both sides
x^2-5x-14=0
find what 2 numbers multiply to get -14 and add to get -5
the numbers are -7 and 2
factor
(x-7)(x+2)=0
set each to zero
x-7=0
add 7
x=7

x+2=0
subtract 2
x=-2
x=-2 or 7

7.add 2r^2 to both sides
2r^2+11r+15=0
difficult so multiply 2 and 15 and get 30
not factor and find what 2 numbers multiply to get 30 and add to get 11
the numbers are 5 nd 6
split 11 up into 5 and 6
2r^2+6r+5r+15=0
group and factor
(2r^2+6r)+(5r+15)=0
factor
2r(r+3)+5(r+3)=0
reverse distribute
(2r+5)(r+3)=0
set each to zero
2r+5=0
subtract 5
2r=-5
divide 2
r=-5/2

r+3=0
subtract 3
r=-3
r=-3 or -5/2

8. this is a difference of 2 perfect squares in which if you have
x^2-y^2 that factors out of (x-y)(x+y) so
x^2-25=0
x^2-5^2=0
(x-5)(x+5)=0
set each to zero
x-5=0
add 5
x=5

x+5=0
subtract 5
x=-5
x=-5 or 5

9. differnce of 2 perfect squares
81-4x^2=0
9^2-(2x)^2=0
(9-2x)(9+2x)=0
set each to zero
9-2x=0
add 2x to both sides
9=2x
divde 2
9/2=x

9+2x=0
subtract 9 from both sidees
2x=-9
divide 2
x=-9/2
x=-9/2 or 9/2

10. subtract 12s from both sides
4s^2-12s+9=0
multiply 4 and 9 and get 36
find what 2 numbers multiply to get 36 and add to get -12
the numbers are -6 and -6
split up the -12s into -6s and -6s
4s^2-6s-6s+9=0
group
(4s^2-6s)+(-6s+9)=0
factor
2s(2s-3)+(-3)(2s-3)=0
reverse distribute
(2s-3)(2s-3)=0
set each to zero
2s-3=0
add 3
2s=3
divide 2
s=3/2

ANWERS:
1. x=0 or -7
2. s=-3 or 0
3. x=-4
4. x=5
5. h=-10 or 6
6. x=-2 or 7
7. r=-3 or -5/2
8. x=-5 or 5
9. x=-9/2 or 9/2
10. s=3/2

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