MATHEMATICS HIGH SCHOOL

0.000 007 as standard form

Answers

Answer 1

Answer:

Answer:

$\sf 7.0 * 10^(-6)$

Step-by-step explanation:

Writing in standard form or scientific form:

0.000007

As we have to move the decimal point to right, the power of 10 will be negative and as the decimal point is moved 6 times to the right, the power of 10 is (-6).

0.000007 = 7.0 *10⁻⁶

Answer: 7.0 *10⁻⁶

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Round the answer to the nearest cent.

A 30% discount on $47.50 is $

Answers

Let's find out how much is the 30% discount to 47.50 dollars.
=> 30% = 30% /100 = .30
Now, multiply this decimal to the given amount in dollars.
=> 47.50 dollars * .30 = 14.25 dollars
Thus the 30% discount of 47.50 dollars is 14.25 dollars.

2. How many solutions does this system have? 2x + y = 3, 6x = 9 – 3yA) 1
B) None
C) Infinite
D) 2

Answers

Answer:

The system of equation has infinite solution.

C is correct.

Step-by-step explanation:

We are given system of equation

2x + y = 3

6x = 9 – 3y

First we re-write the second equation in standard form

So, we add 3y both sides

6x+3y=9 ---------------- (2)

2x+y = 3----------------- (1)

Multiply equation 1 by 3

3(2x)+3y = 3(3)

6x+3y=9

Subtract new equation from 2nd equation

6x-6x + 3y-3y = 9-9

0=0

LHS=RHS

This is true statement. If statement is true then infinite number of many solution.

Hence, The system of equation has infinite solution.

2x + y = 3
6x = 9 - 3y
↓
2x + y = 3
6x + 3y = 9

3(2x + y = 3)
3(2x) + 3(y) = 3(3)
6x + 3y = 9

There is an infinite number of solutions in the system (the answer is C).

Rachel told mariana that if she rolls two number cubes 100 times she will never get aproduct of 23 mariana toldbher that she cant be sure. whos right? explain

Answers

rachel is right because nothing under the number 100 can be multiplied to get the product of 23

Answer:

Rachel is right.

Step-by-step explanation:

You cannot get over 12 when you roll two regular dice. 6 Is the highest number, so if you roll two 6's, the highest you can roll is a 12.

The function g(x) = –3x2 – 36x – 60 written in vertex form is g(x) = –3(x + 6)2 + 48. Which is one of the transformations applied to the graph of f(x) = x2 to change it into the graph of g(x) = –3x2 – 36x – 60? The graph of f(x) = x2 is made narrower. The graph of f(x) = x2 is shifted right 6 units. The graph of f(x) = x2 is shifted down 48 units. The graph of f(x) = x2 is reflected over the y-axis.

Answers

The general vertex form is this:
v(x) = a (x-h)2 + k
where (h,k) is the coordinates of the of vertex.
and a indicates the widening or shrinking of the function compared to another parabolic function. If a become bigger, the graph becomes narrower. If a becomes negative, the graph is reflected over the x-axis.

Comparing f(x) = x2 with g(x) = -3(x+6)2 + 48, we have the following transformations:
The graph is reflected over the x-axis
The graph is made narrower.
The graph is shifted 6 units to the left.
The graph is shifted 48 units up.

From the choices we only have:
The graph of f(x) = x2 is made narrower

A. The graph of f(x) = x2 is made narrower.

I took the test and that was the answer i got.

Give the first four terms of a geometric sequence having a1=18 and r = 2.

Answers

Hello,

$a_(1)=9*2=18$
$a_(2)=9*2^(2)=36$
$a_(3)=9*2^(3)=72$
$a_(4)=9*2^(4)=144$

$a_(n)=9*2^(n)$

PLEASE HELP !The graph shows the ages of different concertgoers who have backstage passes.

Which statement is true about the graph?

A) A late arrival who is 21 years old with a back-stage pass will make the mean greater than the median.
B) The two holders of back-stage passes whose ages are above 40 make the mean age higher than the median age.
C) The ages of concert-goers with backstage passes are skewed left, so the mean age is less than the median age.
D) A concert-goer who is 18 years old and wins a back-stage pass will pull the mean more than 2 years less than the median.

Answers

In the given graph, we calculate the mean by dividing the product of the midpoint of each age interval and the frequency by the total frequency. Mean = [13.5(3) + 16.5(6) + 19.5(8) + 22.5(6) + 25.5(5) + 28.5(4) + 31.5(3) + 43.5 + 46.5] / (3 + 6 + 8 + 6 + 5 + 4 + 3 + 1 + 1) = 856.5 / 37 = 23.15 The median is given by the middle age interval (i.e. the age interval which falls in the (37 + 1) / 2 = 38 / 2 = 19th position) which is the 21 - 24 age inteval. To get the value of the median we use the formular Median = L1 + C[n/2 - summation (Fl)] / Fm where: L1 is the lower class boundary of the median class, C is the class size, n is the total frequency, summation (Fl) is the summation of all frequencies below the mediam class and Fm is the median class frequency. Median = 21 + 4[37/2 - (3 + 6 + 8)] / 6 = 21 + 4[18.5 - 17] / 6 = 21 + 4(1.5) / 6 = 21 + 6 / 6 = 21 + 1 = 22. Thus the mean of 23.15 is greater than the median of 22. Calculating the mean without the two numbers above 40 gives Mean = (856.5 - 43.5 - 46.5) / 35 = 766.5 / 35 = 21.9 Therefore, the statement that is true about the graph is "The two holders of back-stage passes whose ages are above 40 make the mean age higher than the median age." (option B)

The two holders of back-stage passes whose ages are above 40 making the mean age higher than the median age is correct about the graph.

What is a Graph?

This can be defined as pictorial representation of data or values in an organized manner.

From the graph we can calculate mean.

Mean = [13.5(3) + 16.5(6) + 19.5(8) + 22.5(6) + 25.5(5) + 28.5(4) + 31.5(3) + 43.5 + 46.5] / (3 + 6 + 8 + 6 + 5 + 4 + 3 + 1 + 1)

= 856.5 / 37

= 23.15

Median = (37 + 1) / 2 = 38 / 2 = 19th position between 21 - 24 age interval. Median = L1 + C[n/2 - summation (Fl)] / Fm

where L1 = lower class boundary of the median class, C = class size, n = total frequency, summation (Fl) = summation of all frequencies below median class, Fm= median class frequency.

Median = 21 + 4[37/2 - (3 + 6 + 8)] / 6

= 21 + 4[18.5 - 17] / 6

= 21 + 4(1.5) / 6

= 21 + 6 / 6 = 21 + 1 = 22.

Mean of 23.15 is greater than the median of 22.

Mean without two numbers above 40

= (856.5 - 43.5 - 46.5) / 35 = 766.5 / 35 = 21.9.

Therefore the two holders of back-stage passes whose ages are above 40 make the mean age higher than the median age which makes option B the most appropriate choice

Read more about Graph here brainly.com/question/25184007

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