MATHEMATICS HIGH SCHOOL

What's the answer for 4820 divided 241

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

241×2=482

so; 241×20=4820

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how many triangles are formed by the diagonal from one vertex in quadrilateral, hexagon, octagon, and decagon??!

Answers

Quadrilateral: two (you can only trace one diagonal and it forms two triangles)

Hexagon: four (you can trace thre diagonals and four triangles are formed)

Octagon: six (you can trace five diagonals and six triangles are formed)

Degagon: eight (you can trace seven diagonals and eight triangles are formed)

It is always true that the number of triangles you can form from a vertex in a convex polygon is the number of sides minus 2.

What is the formula for P^c(n,r)

Answers

P(n,r)= n! /(n-r)!
C(n,r)= n! / r! (n-r)!
P^c(n,r)= P raised to power C(n.r)? (If so, you know C(n,r) ; raise P to power C(n,r))
P(A/B) = P(A ∩ B) / P(B)
Hope this helped :)

Which function has a minimum and is transformed to the right and down from the parent function, f(x) = x2?g(x) = –9(x2 + 2x + 1) – 7
g(x) = 4(x2 – 6x + 9) + 1
g(x) = –3(x2 – 8x + 16) – 6
g(x) = 8(x2 – 6x + 9) – 5

Answers

Answer:

g(x) = 8(x2 – 6x + 9) – 5

Step-by-step explanation:

A function with a form (x - a)^2 - b where a and b are some constants are a transformation to the right and down from the parent function, f(x) = x^2. Then, option:

g(x) = 4(x2 – 6x + 9) + 1 = 4(x - 3)^2 + 1

is discarded

The vertex form of a quadratic equation is f(x) = c*(x - h)^2 + k, where c, h and k are all constant, and point (h,k) is the vertex of the quadratic function. If c > 0, then the vertex is a minimum and if c < 0 then the vertex is a maximum. Therefore, options:

g(x) = –9(x2 + 2x + 1) – 7 = -9(x + 1)^2 - 7

g(x) = –3(x2 – 8x + 16) – 6 = -3(x - 4)^2 - 6

are dicarded

In consequence, the correct option is:

g(x) = 8(x2 – 6x + 9) – 5 = 8(x - 3)^2 - 5

Answer:

The last choice is the one you want

Step-by-step explanation:

First of all, a parabola has a minimum value if it is a positive parabola, one that opens upward. The first and the third parabolas are negative so they open upside down. That leaves us with choices 2 and 4. We find the side to side and up or down movement by finishing the completion of the square that has already been started for us. Do this by factoring what's inside the parenthesis into a perfect square binomial.

The second one factored becomes:

$g(x)=4(x-3)^2+1$

which reflects a shift to the right 3 and up 1. Not what we are asked to find.

The fourth one factored becomes:

$g(x)=8(x-3)^2-5$

which reflects a shift to the right 3 and down 5. That's what we want!

Need help again ?!???

Answers

Answer:

11.47

Solution,

Fromthe figure,

$cos \: 55 = (PQ)/(PR)$

$cos \: 55 = (PQ)/(20)$

$PQ = 20 \: cos \: 55$

$PQ= 11.472$

$PQ= 11 .47$

Hopethis helps...

Goodluck on your assignment...

Answer:

11.47

Step-by-step explanation:

Use SohCahToa. In this problem, you are given the hypotenuse and you are trying to solve for the adjacent side so it will be cosine. (cosine = $(adjacent)/(hypotenuse)$ )

1. set up the equation

cos55 = $(x)/(20)$

2. Multiply both sides by 20 to solve for x

20 · cos55 = 11.47

What is the greatest common factor of 24 44 52 in prime factorizations?

Answers

24
/\
6 2
/\ \
3 2 2

44
/\
11 4
/ /\
11 2 2

52
/\
13 4
/ /\
13 2 2

I know that this is prime factorization, so the greatest common factor is 2 because that's the greatest number they all in common.

The Museum of Science in Boston has an exhibit in which metal balls drop down a chute, bounce around, and wind up in one of 21 bins. After 1000 balls have dropped, the heights within the bins clearly follow a bell-shaped curve. If the standard deviation is 3 bins, approximately how many balls are in bins 1 through 7?A) 100
B) 160
C) 50
C) 330

Answers

if you have 21 bins then the 'middle bin' is bin 11 (starting at 1)So the 'mean' of this distribution is 11.The SD is 3so using the above calculator (or your own tables ) you get that the probability of a ball being in bin 7 or less is .091

A is you answer

A.100 so make sure you put your answer

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