A diver shines light up to the surface of a smooth pond at a 10 degree angle to the normal. Some light passes into the air above, and the part that reflects back into the water makes an angle to the normal of __________. A) less than 10 degrees. B) 10 degrees. C) more than 10 degrees.

Answers

Answer 1

Answer:

When light passes from one medium (water in this case) into another medium with a different refractive index (air), it follows the law of reflection and refraction.

The law of reflection states that the angle of incidence (the angle at which the light enters the second medium) is equal to the angle of reflection (the angle at which the light reflects back into the first medium), both measured with respect to the normal (a line perpendicular to the surface).

In this scenario, the diver shines light into the pond at a 10-degree angle to the normal. When the light reaches the air-water interface, some of it reflects back into the water. According to the law of reflection, the angle of reflection will be equal to the angle of incidence.

So, the correct answer is:

B) 10 degrees.

The angle at which the light reflects back into the water is 10 degrees, the same as the angle of incidence.

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Explain why Mercury,Venus,and Mars are not likely to support life as we know it.

How is balanced force applied to the egg drop project?

Answers

Answer:

It is the gravity of the angles that connect with the egg and the angles of it

What is the gravitational force acting on a 70.0 kg object standing on the earth's surface ?

Answers

g( gravitational acceleration)=-9.81 m/s^2
m(mass) = 70.0 kg

According to Newton's second law of motion:

"F=ma"

Force is equal mass per acceleration therefore

W=mg
This is because weigth is the force of gravity acting in a body and "a" is replaced by "g" because "g"
is gravitational acceleration

Therefore:

W= mg
W= (70.0 kg) (-9.81m/s^2)
W= -686.7 N

* The "N" means newton which is (kg* m/s^2)

Final answer:

The gravitational force acting on a 70.0 kg object on Earth is calculated using the formula w=mg and is equal to 686 N.

Explanation:

The gravitational force acting on a 70.0 kg object standing on the earth's surface can be calculated using the formula for weight (which is essentially the gravitational force on the object): w = mg, where m is the mass of the object and g is the acceleration due to gravity. On Earth, g is approximately 9.8 m/s².

Therefore, the gravitational force (weight) acting on this object can be calculated as follows: w = mg = (70.0 kg)(9.8 m/s²) = 686 N. Thus, the gravitational force on this 70.0 kg object standing on the earth's surface is 686 Newtons. It's important to understand that this force will vary if the object is moved to a location where g is different, like on the moon.

Learn more about Gravitational Force here:

brainly.com/question/32609171

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Melody is riding her mountain bike along a trail with multiple hills. At the bottom of the second hill, she has 3200 J of kinetic energy. At the top of the third hill, when she is going the slowest, her potential energy measures 1650 J. Which statement below is true? A. The total amount of energy at the bottom of the hill cannot equal the amount at the top, because some of the energy from the environment is gained. B. The total amount of energy at the top is equal to the amount at the bottowm, but she gained some energy as she traveled due to a higher speed going down the first two hills. C. The total amount of energy at the bottom of the hill cannot be equal to the amount at the top, because some of the energy is lost.

Answers

Answer:

Eventually it reaches bottom of hill so C

Explanation:

5. Projectile A with mass m is launched at an angle of 20° above the horizontal with a speed v0. Projectile B also with mass m is launched from the same location at an angle of 70° above the horizontal, also with speed v0. Thus, both projectiles have the same initial total energy. a. Which projectile has a larger speed when it hits the ground or do they have the same speed? Explain using energy. b. Which projectile reaches a greater height? Given that both projectiles have the same initial energy, how is this possible?

Answers

Answer:

a) They both have the same final speed.

b) Projectile B reaches a greater height

Explanation:

The initial total energy of both projectiles is the same, and since the initial height is zero, that initial energy is entirely kinetic energy:

$E_0=K_0=(1)/(2)mv_0^(2)$

Now, when the projectiles are going to reach the ground, their height also becomes zero, so the final energy is also entirely kinetic energy:

$E_f=K_f=(1)/(2)mv_f^(2)$

As stated in the conservation of mechanical energy, the final total energy has to be equal to the initial total energy, and then:

$E_0=E_f\n \n (1)/(2)mv_0^(2)=(1)/(2)mv_f^(2)\n\n\implies v_0=v_f$

Finally, since the initial speed is the same for both projectiles, they have the same speed when they hit the ground (a).

Next, we know that the height reached by a projectile depends only of their initial vertical velocity, nor their horizontal one. So, the projectile with the highest initial vertical velocity has to reach a greater height. We use trigonometry to calculate that:

$v_0_A_y=v_0\sin20\°=0.34v_0\n\nv_0_B_y=v_0\sin70\°=0.93v_0$

It means that projectile B has a higher initial vertical velocity, so it reaches a greater height (b).

This is possible because some of the kinetic energy of both projectiles is never transformed to gravitational potential energy (because is related to the horizontal velocity) and this amount of kinetic energy depends on the angle at which the projectile is launched. As their potential energies at the highest points are different, their maximum heights are, too.

Walking across a carpet is an example of charge being transferred bya. contact.
b. induction.
c. static electricity.
d. friction.

Answers

Answer : The correct answer is- D) Friction.

There are three modes of charging, which are Conduction, induction, and friction.

The static electricity is produced due to the rubbing of one substance with another. This is called charing by friction.

Hence, the correct answer is friction as there is friction between carpet and the feet of person walking over it.

Walking across a carpet is an example of charge being transferred by friction. The answer is letter D. The carpet, which is at rest, will resist the motion cause by your walking. This resistive motion d the friction the carpet obtained from you and you from the carpet.

A 2.75 kg sample of a substance occupies a volume of 250 cm³ . Find the density in g/cm³ and kg/m³