6. A skydiver jumps out of a plane and reaches a terminal velocity (maximum speed) of 50 m/s after5 seconds. After an additional 10 seconds she opens her parachute and slows down for 2 seconds to a
new terminal velocity of 10 m/s. She falls at that speed for 3 seconds before landing on the ground.
Sketch the following graphs:
Position vs. Time
Velocity vs. Time
Acceleration vs. Time

Answers

Answer 1
Answer:

Final answer:

During freefall, the position and velocity of the skydiver increase at a constant rate until reaching terminal velocity. After opening the parachute, the position and velocity decrease to a new terminal velocity. The acceleration is constant during freefall and becomes negative when the parachute slows the skydiver down.

Explanation:

Position vs. Time:

During the first 5 seconds, the skydiver is in freefall and her position increases at a constant rate. After opening the parachute, her position still increases but at a slower rate due to the decrease in terminal velocity. When the parachute slows her down, the position increases at a slower rate again. The position remains constant during the final 3 seconds as the skydiver lands on the ground.

Velocity vs. Time:

During the freefall, the velocity of the skydiver steadily increases until it reaches the terminal velocity of 50 m/s. After opening the parachute, the velocity decreases to the new terminal velocity of 10 m/s. The velocity remains constant until the skydiver lands.

Acceleration vs. Time:

At the start of the jump, the skydiver experiences a constant acceleration due to gravity. After reaching terminal velocity, the acceleration becomes zero since there is no net force acting on the skydiver. When the parachute is opened, the skydiver experiences a negative acceleration due to air resistance, slowing down until the new terminal velocity is reached. The acceleration then becomes zero until the skydiver lands.

Learn more about Skydiver's motion here:

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Answers

Answer:

As ailtitudes rises air pressure drops ...... As altitude increases , the amount of gas molecules in the air decreases - so the air becomes less dense than air nearer to the sea level. So there is less air pressure at high altitudes

What will happen to the pitch of a sound as that sound’s source approaches an observer? Explain why this happens, based on what you have learned about wave properties. Please use 3 content related sentences

Answers

The pitch of a sound is decreased, when a sound source approaches the observer.

Explanation:

Pitch is nothing but it is a property that helps to determine whether the sound is high or low. Doppler effect helps to understand this concept easily. The pitch of the sound is mainly calculated based on the frequency of the sound wave arose from the sound source.

As the wellspring of sound waves moves toward an audience, the sound waves draw nearer together, expanding their recurrence and the pitch of the sound.

Help me on this question? log x-log 9=1

Answers

\log { x } -\log { 9 } =1\n \n \log { \left( \frac { x }{ 9 }  \right)  } =1\n \n \log _( 10 ){ \left( \frac { x }{ 9 }  \right)  } =1\n \n { 10 }^( 1 )=\frac { x }{ 9 } \n \n 9\cdot 10=x\n \n x=90

This is because:

\log _( a ){ \left( \frac { x }{ p }  \right)  } \n \n =\log _( a ){ \left( \frac { { a }^( m ) }{ { a }^( n ) }  \right)  } \n \n =\log _( a ){ \left( { a }^( \left( m-n \right)  ) \right)  } \n \n =\left( m-n \right) \cdot \log _( a ){ a } \n \n =m-n\n \n =\log _( a ){ x } -\log _( a ){ p } \n

   log(x) - log(9) = 1

Subtracting the logs of numbers gives you the log of
the quotient of the numbers.

     Log(x) - log(9)  is the log of  (x/9).

So the equation says:    log (x/9) = 1

Raise 10 to the power of each side:  10^(log of x/9) = 10^1

But  10^(log of x/9) is x/9, and 10^1 is 10.

So        x/9 = 10

             x  =  90

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Answers

Answer:

The work done and power are 60000 Pounds-feet and 3000 Pounds-feet/sec.

Explanation:

Given that,

Force F = 1500 pounds

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Time t = 40 sec

Work done :

The work done is the product of the force and distance.

The work done is defined as,

W = F * d

Where, W = work

F = force

d = distance

Put the value into the formula of work

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Power:

The power is equal to the work done divided by time.

The power is defined as,

P = (W)/(t)

Where, P = power

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t = time

Put the value into the formula of power

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P=3000\ Pounds-feet/s

Hence, The work done and power are 60000 Pounds-feet and 3000 Pounds-feet/sec.

work = f x s = 1500 x 40
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Answers

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Answers


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