3 tbsp mayonnaise is how many servings of oil?

Answers

Answer 1

Answer:

Answer:126 grams

Step-by-step explanation:

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A cube with side length 5h^2 is stacked on another cube with side length 3k What is the total volume of the cubes in factored form?

Answers

Answer:

$(5h^2+3k)(25h^4-15h^2k+9k^2)$

Step-by-step explanation:

We have been given that a cube with side length 5h^2 is stacked on another cube with side length 3k.

Since we know that the volume of cube is $a^3$ , where a represents the length of each side of cube.

Since one cubes is stacked on another cube, so the total volumes of both cubes will be equal to the sum of volumes of both cubes.

$\text{Total volume of both cubes}=(5h^2)^3+(3k)^3$

Since the volume of both cubes is sum of cubes, so we will use formula:

$a^3+b^3=(a+b)(a^2-ab+b^2)$

So factoring the volumes of cubes using sum of cubes we will get,

$\text{Total volume of both cubes}=(5h^2+3k)((5h^2)^2-5h^2* 3k+(3k)^2)$

$\text{Total volume of both cubes}=(5h^2+3k)(25h^4-15h^2k+9k^2)$

Therefore, the total volume of both cubes in factored form will be: $(5h^2+3k)(25h^4-15h^2k+9k^2)$

In order to compute the combined volume of the cubes, we may simply add the individual volumes of the cube. The volume of a cube is equivalent to the cube of one of its sides. The volume of the first cube is (5h^2)^3 = 125h^6. The volume of the second cube is (3k)^3 = 27k^3. The total volume is: 125h^6 + 27k^3Hope this helps. Let me know if you need additional help!

A segment of a circle has 120 degree arc and a cord of 8 square root 3 in. Find the area of the segment

Answers

Answer:

ok then

Step-by-step explanation:

Segementhaveangleof120degree

sorryissseaaghenhiaate

120 is the right answer

In Vancouver, the high temperature for the day was 6° C. On the same day, the high temperature in Calgary was −3° C. What was the difference in high temperatures between the two cities?

Answers

Answer:

Step-by-step explanation:

|6|+|-3|=9

In ΔOPQ, p = 180 inches, q = 120 inches and ∠O=171°. Find the length of o, to the nearest inch.

Answers

Given:

In ΔOPQ, p = 180 inches, q = 120 inches and ∠O=171°.

To find:

The length of o, to the nearest inch.

Solution:

According to cosine formula,

$a^2=b^2+c^2-2bc\cos A$

Using cosine formula in ΔOPQ, we get

$o^2=p^2+q^2-2pq\cos O$

On substituting the values, we get

$o^2=(180)^2+(120)^2-2(180)(120)\cos (171^\circ)$

$o^2=32400+14400-43200(-0.9877)$

$o^2=46800+42668.64$

$o^2=89468.64$

Taking square root on both sides.

$o=√(89468.64)$

$o=299.113$

$o\approx 299$

Therefore, the length of o is about 299 inches.

Answer:299

Step-by-step explanation:

What is A2 – (B + C) in simplest form?A=8x2 – 25x + 7
B=8x2– 25x + 11
C=10x2 – 25x + 7
D=10x2 – 25x + 11

A, B, and C are polynomials, where:
A = 3x – 4
B = x + 7
C = x2 + 2

Answers

A2 - (B + C) = (3x - 4)2 - ((x + 7)+ (x2 + 2))
A2 - (B + C) = 9x2 - 24x + 16 - (x2 + x + 9)
A2 - (B + C) = 9x2 - 24x + 16 - x2 - x - 9
A2 - (B + C) = 8x2 - 25x + 7

So, the answer is
A:
8x2 – 25x + 7

Answer: $8x^2 - 25x + 7$