WILL GIVE BRAINLIEST!! What type of chemical weathering do you see in this photo?
A. Hydrolysis
B. Oxidation
C. Exfoliation
D. Frost Wedging
WILL GIVE BRAINLIEST!! What type of chemical weathering do you - 1

Answers

Answer 1
Answer:

Answer:

Hydrolysis

Explanation: You can see green growing from the rocks and as such, caused by constant water flow and sunlight. it is similar to a fishtank.


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a cell with 18 chromosomes divided by meiosis. which of the following statements best describes the expected daughter cells?

Snake venom contains a mixture of enzymes, which include phospholipase that break down cell membranes, proteinases that destroy proteins, as well as amino acid oxidases and nucleotidases that break down the monomers for protein and DNA synthesis, which is why they can be so deadly. If you were bitten by a venomous snake you may be treated with an antivenom. In addition to antibodies that help your immune system recognize and fight the foreign molecules, what else does the antivenom most likely contain

Answers

Answer:

The correct answer is - Venom enzyme inhibitors.

Explanation:

The snake venoms are the complex mixtures of phospholipase A2s, disintegrins, serine proteases, C-lectins, and metalloproteases, and others. The snake venom phospholipase A2s (svPLA2s) enzymes found in most of the families of venomous snakes that cause anticoagulant effects, cardiotoxicity, neurotoxicity, and cytotoxicity, and other effects.

In antivenom, there are Venom enzyme inhibitors other than antibodies that help inneutralizing these enzymes by weakening or inhibiting these toxic actions.

Was the rate of increase of sucrase activity greater when sucrose concentration went from 2.5 to 7.5 g/l or when it went from 22.5 to 27.5 g/l?

Answers

Answer: It is greater when sucrose concentration went from 2.5 to 7.5g/l.

Explanation: The rate of reaction of an enzyme is known to be affected by the rate of concentration of its substrate, which in this case is the sucrose Solution.

If the rate of increase of concentration is high,the activities of the enzyme SUCRASE will increase accordingly, in order to breakdown the substrate.

The rate of increase of Sucrose from 2.5 to 7.5g/l is higher(300%) than the rate of Increase of Sucrose from 22.5 to 27.5g/l (1.22%). It is expected under circumstances that the action of SUCRASE will increase at a rate higher in the first Solution than in the second Solution.

Final answer:

The rate of increase in sucrase activity depends on the concentration of sucrose and whether or not the enzyme is saturated. The increase could be greater at lower concentrations (2.5 to 7.5 g/l) if sucrase is not yet saturated. The increase might be less at higher concentrations (22.5 to 27.5 g/l) if sucrase is near or at saturation point.

Explanation:

The increase in sucrase activity is generally considered to be a response to the concentration of substrate present, in this case, sucrose. The increase in activity happens because more substrate (sucrose) is available for the enzyme (sucrase) to act upon. However, there is a limit to this increase. Once the enzyme is saturated with substrate, further increases in substrate concentration do not increase the enzyme's activity. This is known as the saturation point.

To determine whether sucrase activity increased more when sucrose concentration increased from 2.5 to 7.5 g/l or from 22.5 to 27.5 g/l, we would need specific data on the rate of sucrase activity at these different concentrations. It's possible that the increase from 2.5 to 7.5 g/l was greater if this is in the ascending portion of the enzyme activity curve and the sucrase was not yet saturated with sucrose. Conversely, the increase from 22.5 to 27.5 could be lesser if the sucrase is near or at saturation point.

Learn more about sucrase activity

Match up macromolecules with example.a. carbohydrates __cholesterol or fat
b. proteins __dna or rna
c. lipids __hemoglobin or enzyme
d. nucleic acids __glycogen or starch

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I get it! 

a. carbohydrates - glycogen or starch (these are sugars)
b. proteins - hemoglobin or enzyme (these are examples of proteins)
c. lipids - cholesterol or fat
d. nucleic acids - DNA or RNA

How would having a large surface area to volume ratio affect diffusion rates of a cell? Offering 50 points.

Answers

The following life cycle stages do both complete and incomplete metamorphosis of insects have in common is adult. Thus, option B is correct.

What is larva?

Larva" is a stage in the life cycle of an insect among the following choices given in the question that a caterpillar represents. A Caterpillar represents the larva stage in the life cycle of an insect. The Caterpillar is most specifically Butterfly Larva. In this stage of the Butterfly life cycle, the Caterpillar spends most time eating, growing and shedding their exoskeleton.

Life cycle stages do both complete and incomplete metamorphosis of insects have in common is adult. A Caterpillar represents the larva stage in the life cycle of an insect. The Caterpillar is most specifically Butterfly Larva. Larva" is a stage in the life cycle of an insect among the following choices given in the question that a caterpillar represents.

Therefore, The following life cycle stages do both complete and incomplete metamorphosis of insects have in common is adult. Thus, option B is correct.

Learn more about metamorphosis on:

brainly.com/question/29061320

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Surface area to volume ratio, in simple means the size of surface area to the volume of substance that can pass through it at a particular time.

Amoeba and some bacteria are flat and have large surface area to volume ratio. So the diffusion rate is very high due to large surface area.

Where as humans have small surface area: volume so diffusion is very slow or does not take place at all.

Ms. Brown’s class built series and parallel circuits during science lab. After the results of the experiments are collected, the students should

Answers

Answer:

B

Explanation: because the teacher is in charge

After the rain of 12th june 2017 an ecologist measured a volume of 1414cm cube of rain water from a rain gauge wish a funnel diameter of 24cm. Calculate the mm of rain that fell that day

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Rainfall is measured as depth on the surface of the Earth, typically in mm. We know the volume of water in the rain gauge: 1414 cubic centimetres. We know need to know the area of the Earth that this volume fell on. This would be the area of the funnel opening that points up to the sky to catch the rain. We know the diameter is 24 cm. So we need to determine the area of a circle with a diameter of 24 cm. The equation to use is: area = pi * radius^2. Since the radius of a circle is half the diameter, the equation is:
So area is 3.14159 * 12^2
= 452.39 cm^2Volume = depth * areadepth = volume/areadepth = 1414/452.39= 3.13 cm = 31.3 mm