Rank in order, from largest to smallest, the electric field strengths E1, E2, E3, and E4 at the four labeled points in (figure 1). a) E1 > E2 > E3 > E4 b) E4 > E3 > E2 > E1 c) E2 > E1 > E4 > E3 d) E3 > E2 > E1 > E4

Answers

Answer 1
Answer:

Answer: E3 > E1 > E2 = E4

Explanation:


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an electron is very far away from a proton (fixed in place) and is released from rest. how fast will the electron be travelling when it is 0.03 m away from the proton?

Answers

The speed of electron be 183.73 m/s.

What is potential energy?

The energy held within an object is known as potential energy. There are several different types of potential energy, including gravitational potential energy, elastic potential energy, and electric potential energy. An object's energy as a result of the overall charge it contains is known as its electric potential.

Given parameters:

Distance between proton and electron: d = 0.03 m.

Let, at that point the speed of the electron be v.

So from conservation of energy:

Kinetic energy of electron + potential energy of electron = 0

1/2×mv² - 1/(4πε₀)(e²/d) = 0

⇒v = √(2e²/m(4πε₀)(d))

= √( 2 × (1.6 ×10⁻19)²× 9 × 10⁹/9.1093837 × 10⁻³¹×0.03) m/s

= 183.73 m/s.

The speed of electron be 183.73 m/s.

Learn more about potential energy here:

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the electron won't be traveling because it is as u say "fixed in place".

Which statement best describes the formation of diamonds? A. Diamonds form in kimberlites under very low pressure.
B. Diamonds form in kimberlites under very high pressure.
C. Diamonds form in talc under very high pressure.
D. Diamonds form in talc under very low pressure.

Answers

The correct answer would be (b.) Diamonds form in kimberlites under very high pressure. Kimberlites are one of the most important sources of the mined diamonds and these are formed with a very high pressure. The statement in (d.) would best describe the formation of diamonds.

An electromagnetic wave traveling through a vacuum has a wavelength of .15 meter. What is the period of this electromagnetic wave?

Answers

Tools we'll need:
Speed of EM wave in vacuum = 3 x 10⁸ meters per second.
Frequency = (speed) / (wavelength)
Period = 1/frequency

Period = (wavelength) / (speed) = (0.15) / (3 x 10⁸) = 0.5 nanosecond

( "nano..." = 10⁻⁹ )




Send helpI have to do test corrections but I have no idea what the speed vs time graph should look like

Answers

Answer:

A

Explanation:

at the same instant means in the same moment, same time thus A and B share the same starting time which is t=0

This is heat or electrical transfer by contact.

Answers

Answer:

The correct answer for this problem is conduction.

Explanation:

I just did the test and conduction was the correct answe.

Help me on this question? log x-log 9=1

Answers

\log { x } -\log { 9 } =1\n \n \log { \left( \frac { x }{ 9 }  \right)  } =1\n \n \log _( 10 ){ \left( \frac { x }{ 9 }  \right)  } =1\n \n { 10 }^( 1 )=\frac { x }{ 9 } \n \n 9\cdot 10=x\n \n x=90

This is because:

\log _( a ){ \left( \frac { x }{ p }  \right)  } \n \n =\log _( a ){ \left( \frac { { a }^( m ) }{ { a }^( n ) }  \right)  } \n \n =\log _( a ){ \left( { a }^( \left( m-n \right)  ) \right)  } \n \n =\left( m-n \right) \cdot \log _( a ){ a } \n \n =m-n\n \n =\log _( a ){ x } -\log _( a ){ p } \n

   log(x) - log(9) = 1

Subtracting the logs of numbers gives you the log of
the quotient of the numbers.

     Log(x) - log(9)  is the log of  (x/9).

So the equation says:    log (x/9) = 1

Raise 10 to the power of each side:  10^(log of x/9) = 10^1

But  10^(log of x/9) is x/9, and 10^1 is 10.

So        x/9 = 10

             x  =  90