During a very cold winter, water pipes sometimes burst. Why?

Answers

Answer 1

Answer:

Water pipes can burst during very cold winters due to a phenomenon known as "freeze-thaw cycle." When temperatures plummet, water inside the pipes can freeze, causing it to expand and exert pressure on the pipe walls.

Water molecules expand as they freeze, creating a buildup of pressure within the pipe. Pipes are designed to withstand a certain amount of pressure, but when it exceeds their capacity, they can rupture or burst. Furthermore, pipes made of materials like metal or plastic can become brittle in extremely cold temperatures. The cold causes the material to contract, reducing its flexibility and making it more susceptible to cracks and breaks. This can weaken the structural integrity of the pipe, making it more likely to rupture when subjected to the internal pressure from the frozen water. Preventing pipe bursts during cold winters involves insulating pipes, maintaining a constant flow of water, and keeping indoor spaces adequately heated to mitigate the freezing and expansion of water within the pipes.

Additionally, stagnant water in pipes is more prone to freezing than flowing water. Pipes that aren't used frequently, like those in less-used areas of a building, may freeze more easily during extended cold periods.

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You ran 400 meters in 2 minutes what is your speed

Answers

The speed of an object is the distance divided by the time of travel. The speed of the person running 400 meters in 2 minutes is 3.3 m/s.

What is speed?

Speed is a physical quantity used to measure the distance covered per unit time. Speed is a scalar quantity thus, having magnitude only. The rate of speed is called velocity. Velocity is a vector quantity.

Speed in physics is the ratio of the distance covered per unit time. Thus, speed can have the units m/s, Km/hr, ft/s miles/s etc. As the time of the travel increases, speed is said to be decreasing.

The distance covered = 400 meters.

time = 2 minutes = 2 × 60 s = 120 s

Speed = distance / time

= 400 m/ 120 s

= 3.3 m/s.

Therefore, the speed is 3.3 m/s.

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Answer:

3.3m/s

Explanation:

speed =Distance /Time

x=400m

t=2mintues=2min*60sec/min=120seconds

S=400m/120s

S=3.33333...

therefore speed = 3.3m/s

Any help is appreciated

Answers

image distance,di=10 cm

object distance,do=20cm

magnification, m=di/do

=10/20

=0.5

since the image is virtual, magnification is negative.

therefore m=-0.5

What happens when a wave reflects?a. They are absorbed by the object they hit.
b. They travel through the object they hit.
c. They bend when they hit the medium.
d. They bounce off the object they hit.

Answers

they bounce off just like sun rays when they heat the atmosphere they bounce off reflection

A cellist tunes the C string of her instrument to a fundamental frequency of 65.4 Hz . The vibrating portion of the string is 0.600 m long and has a mass of 14.4 g .What is μ, the mass per unit length of the string?
To determine the wave speed from purely kinematic quantities, you need to know the wavelength of the wave. What is the wavelength λ of the fundamental mode in the C string of the cello?

Answers

Explanation:

Given that,

Fundamental frequency of the string, f = 65.4 Hz

Length of the string, l = 0.6 m

Mass, m = 14.4 g = 0.0144 kg

(a) Let $\mu$ is the mass per unit length of the string. It can be calculated as :

$\mu=(m)/(l)$

$\mu=(0.0144\ kg)/(0.6\ m)$

$\mu=0.024\ kg/m$

(b) If f is the fundamental frequency of the string, the wavelength of the fundamental mode is given by :

$l=(n\lambda)/(2)$

$\lambda=(2l)/(n)$

n = 1

$\lambda=2l=2* 0.6\ m$

$\lambda=1.2\ m$

Hence, this is the required solution.

The mass per unit length of the string is 0.024 kg/m, and the wavelength is 1.2 meters.

What is the frequency?

It is defined as the number of waves that crosses a fixed point in one second known as frequency. The unit of frequency is per second.

We have:

Fundamental frequency = 65.4 Hz

Length of the vibrating string portion = 0.6 meter

Mass of the vibrating string portion = 144 grams

We know the formula for mass per unit length:

$\rm \mu = (m)/(l)$

$=\rm (0.0144 \ kg)/(0.6 \ meter)$ ( m = 144 grams ⇒ 0.0144 kg)

$\rm \mu = 0.024 \ kg/m$

The wavelength of the fundamental mode is given by:

$\rm l =(n\lambda)/(2)$

$\rm \lambda = (2l)/(n)$

$\rm \lambda = 2* 0.6 \Rightarrow 1.2 meter$ (n = 1)

Thus, the mass per unit length of the string is 0.024 kg/m, and the wavelength is 1.2 meters.

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(a) What is the magnitude of the tangential acceleration of a bug on the rim of a 12.5-in.-diameter disk if the disk accelerates uniformly from rest to an angular speed of 75.0 rev/min in 3.80 s

Answers

Answer:

Explanation:

Given:

d=12.5in=0.3175m

r=d/2=0.3175/2=0.15875m

ωf=75rev/min=7.85rad/s

t=3.80s

The angular acceleration

$\alpha = (\omega _f - \omega _i)/(t)=(7.85-0)/(3.80)=2.07rad/s^2$

Tangential acceleration

$\alpha =r\alpha =0.15875* 2.07=0.33m/s^2$

The balls in the image above have different masses and speeds. Fill in the blanks in the following sentence: Ball ___ has the greatest amount of momentum and ball ___ has the least amount of momentum.

Answers

Explanation:

The given figure shows four balls A,B,C and D. Momentum of an object is defined as the product of its mass and velocity.

Momentum of ball A, p₁ = m₁v₁ = 0.7 kg × 15 m/s = 10.5 kg-m/s

Momentum of ball B, p₂ = m₂v₂ = 5.5 kg × 1.2 m/s = 6.6 kg-m/s

Momentum of ball C, p₃ = m₃v₃ = 5 kg × 2.5 m/s = 12.5 kg-m/s

Momentum of ball D, p₄ = m₄v₄ = 1.5 kg × 5 m/s = 7.5 kg-m/s

So, ball C has the greatest amount of momentum and ball B has the least amount of momentum.

Ball C has the greatest momentum and ball B has the least amount of momentum.

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