$120 is shared in the ratio 2:3. What is the larger share

Answers

Answer 1

Answer:

Step-by-step explanation:

The larger share is 3 out of (3+2 =5)

3/5 * 120 = 72 dollars

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If it is hot outside you buy an ice cream cone, and if you buy an ice cream cone it is hot outside. (Check all that apply.) Check All That Apply A. You buy an ice cream cone if and only if it is hot outside. B. You buy an ice cream cone if and only if it is not hot outside. C. You do not buy an ice cream cone if and only if it is hot outside. D. You do not buy an ice cream cone if and only if it is not hot outside.

Answers

Answer: A & D

Step-by-step explanation:

Hot Outside = Buy Ice cream cone

Buy Ice cream cone = Hot outside

A. You buy an ice cream cone if and only if it is hot outside.

This is true because you do buy ice cream when it is hot.

B. You buy an ice cream cone if and only if it is not hot outside.

This is false because you buy ice cream when it is hot.

C. You do not buy an ice cream cone if and only if it is hot outside.

This is false because you buy ice cream when it is hot.

D. You do not buy an ice cream cone if and only if it is not hot outside.

This is true because you only buy ice cream when it is hot, which means you do not buy ice cream when it is not hot.

Given the function g(x) = 8x − 2, compare and contrast g(−2) and g(4). Choose the statement that is true concerning these two values. A) The value of g(−2) is larger than the value of g(4).
B) The value of g(−2) is the same as the value of g(4).
C) The value of g(−2) is smaller than the value of g(4).
D) The values of g(−2) and g(4) cannot be compared.

Answers

g(-2) = 8(-2) -2 = -16 - 2 = -18
g(4) = 8*(4) - 2 = 32 - 2 = 30
as you can see 30 is greater than -18 so the answer is C

your answer is C I don't know how to show you my work.

the flight of an aircraft from toronto to montrel can be modelled by he relation h=-2.5t2+200t where t is the time, in minutes, and h is the height in metre

Answers

Final answer:

The equation for the aircraft's flight is a quadratic equation representing the height of the aircraft at any given time. By rearranging the equation to isolate time and applying the quadratic formula, we can find the time at which the aircraft reaches its maximum height, which in this case is 3.79 minutes.

Explanation:

The flight of an aircraft from Toronto to Montreal is modeled by the equation h = -2.5t2 + 200t where t represents time in minutes and h represents height in meters. This is fundamentally a quadratic equation which is utilized in physics to characterize motion under constant acceleration. In this case, it models the height of the aircraft at any given time.

To find the time at which the airplane's maximum height is achieved, we must solve the equation for t. By rearranging the equation, we can isolate t, yielding a quadratic equation as follows: 0 m = 0 m + (10.0 m/s) t + (2.00 m/s2) t2. This simplifies to 200 = 10t + t2.

Applying the quadratic formula, we find two solutions for t, 3.79 s and 0.54 s. The time it takes the aircraft to reach its maximum height would be the longer solution, which is 3.79 minutes in this case.

Learn more about Quadratic Equations in Motion here:

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Final answer:

The question provides a quadratic equation to model the flight of an aircraft. This equation can be used to calculate the height of the aircraft at a specific time or to determine when the aircraft reaches its maximum height.

Explanation:

The question is asking about the trajectory of an aircraft as modelled by a quadratic equation, and specifically, how time influences height. The equation given is h = -2.5t²+200t. Quadratic equations are frequently used to describe the motion of objects when the acceleration is constant. This equation tells us that the height of the aircraft is dependent on the time squared and the time.

To solve for a specific time (t), we can plug the desired time into the equation to find the height of the aircraft at that time. For instance, if we want to find out the height of the aircraft 10 minutes into the flight, we would substitute t=10 into the equation, giving us h=-2.5 × (10)²+200 × (10). Simplifying this equation would provide the height of the aircraft 10 minutes into the flight.

Additionally, this equation could also be used to find the maximum height of the aircraft. The maximum height is reached when the derivative of the equation equals zero. Taking the derivative of h = -2.5t²+200t and setting it equal to zero will provide the time when the maximum height is reached.

Learn more about Quadratic Equations here:

brainly.com/question/30098550

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What is the intersection point of 2x+19y=3 and 1x-3=7y

Answers

$2x+19y=3\n19y=-2x+3\ny=-(2)/(19)x+(3)/(19)\n\nx-3=7y\ny=(1)/(7)x-(3)/(7)\n\n-(2)/(19)x+(3)/(19)=(1)/(7)x-(3)/(7)\n-(14)/(133)x+(21)/(133)=(19)/(133)x-(57)/(133)\n(78)/(133)=(33)/(133)x\n(78)/(33)=x\nx=(26)/(11)\n\n((26)/(11))-3=7y\n((26)/(11))-(33)/(11)=7y\n(-7)/(11)=7y\n-11=y$

(26/11, -11)

2x + 19y = 3 ⇒ 2x + 19y = 3 ⇒ 2x + 19y = 3
1x - 3 = 7y    ⇒ 1x -   7y = 3 ⇒ 2x + 14y = 6
      5y = -3
   5     5
   y = -3/5
      2x + 19(-3/5) = 3
   2x - 11 2/5 = 3
      +11 2/5 +11 2/5
   2x = 14 2/5
      2 2
       x = 7 1/5
   (x, y) = (7 1/5, -3/5)

Using the graph of f(x) = log10x below, approximate the value of y in the equation 10y = 6

Answers

The given function is

f(x)= log 10 x

Taking base as 10

$y=\log_(10)10 +\log_(10)x$ →→Using the property of, log a b= log a + log b

→y = 1 + $\log_(10)x$ as, $\log_(10)10=1$

we have to approximate the value of y in the equation

→10 y = 6

→y= $(6)/(10)$

$(6)/(10)$ = 1 + $\log_(10)x$

$\log_(10)x$ = $(-4)/(10)$

x= $(10)^{(-4)/(10)}$ = $(10)^(-0.4)$ =0.398

Solving graphically,

we get , x= 0.398 for , y= $(6)/(10)$ =.6

f(x) = ㏒(10x)
f(x) = ㏒₁₀(10x)

10y = 6
10 10
y = 0.6

f(x) = ㏒₁₀(10x)
0.6 = ㏒₁₀(10x)
$10^(0.6) = 10x$
$10^{(3)/(5)} = 10x$
$\sqrt[5]{10^(3)} = 10x$
$\sqrt[5]{1000} = 10x$
$\frac{\sqrt[5]{1000}}{10} = x$
$(3.98)/(10) \approx x$
$0.398 \approx x$

What’s the slope pls answer quickk

Answers

Answer:

slope is -1

Step-by-step explanation:

The line is decreasing from left to right, so the slope is going to be negative. If you count down, then move to the right, you would get one down, one to the right continually.

Answer:

y=-1x-2

Step-by-step explanation:

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