Formic acid, HCOOH, is a weak electrolyte what solutes are present in an aqueous solution of this compound write the chemical equation for the ionization of HCOOH

Answers

Answer 1
Answer:

Answer:

Explanation:

Formic acid (HCOOH) is a weak electrolyte when dissolved in water. In an aqueous solution of formic acid, it partially ionizes into its constituent ions. The solutes present in this solution are the ions produced during ionization.

The chemical equation for the ionization of formic acid (HCOOH) in water is as follows:

HCOOH (aq) ⇌ H⁺ (aq) + HCOO⁻ (aq)

In this equation:

HCOOH represents formic acid molecules.

H⁺ represents the hydrogen ions (protons) that are formed when a molecule of formic acid loses a hydrogen ion (H⁺).

HCOO⁻ represents the formate ion, which is the conjugate base formed when a molecule of formic acid donates a hydrogen ion (H⁺).

Since formic acid only partially ionizes in water, not all molecules of formic acid dissociate into ions. This is why it is considered a weak electrolyte.


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Mendeleev’s principle of chemical periodicity states that when the elements are arranged according to their atomic numbers. This periodic law allows elements with similar properties to appear at regular intervals. Predict the group of elements and their number of valence electrons that will combine in a 2:1 ratio to with sodium. A)bromine, chlorine, iodine, 7 B)sulfur, selenium, polonium, 6 EliminateC)hydrogen, fluorine, potassium, 1 D)calcium, phosphorus, tellurium, 2

Which statement describes a major drawback of the Bohr model that caused scientists to replace it?a) It worked only for helium and larger atoms.
b) It did not identify the distance between an electron and the nucleus.
c) It contradicted the Heisenberg uncertainty principle.
d) It stated that spectral lines of atoms are similar.

Answers

The statement that best describe a major drawback of the Bohr model that caused scientists to replace it is it did not identify the distance between an electron and the nucleus. The answer is letter B. The rest of the choices don not answer the question above.

Answer: C

Explanation: Just took it

The following reaction does not proceed to form a product: H2O + Au---> no reaction. Why is that?. . A. Gold has a higher activity than hydrogen and cannot replace it.. . B. Gold has a lower activity than hydrogen and cannot replace it.. . C. The reaction cannot occur because water is a reactant.. . D. The reaction proceeds too slowly to create products..

Answers

I think the correct answer from the choices listed above is option B. The following reaction does not proceed to form a product: H2O + Au---> no reaction because gold has a lower activity than hydrogen and cannot replace it. Hope this answers the question.

Mixtures have strong chemical bonds true or false ?

Answers

false Because they

A group of atoms that are held together by covalent bonds so that they move as a group

Which of the following is most likely to be amorphous?-glass
-solid sulfur
-solid calcium
-gold

Answers

Answer: Option (a) is the correct answer.

Explanation:

Amorphous means without any crystalline structure or definite shape. Whereas a solid whose atoms are not bonded together in a definite lattice pattern. This solid is non-crystalline in nature.

For example, glass, gel, plastic etc are all amorphous solids.

Whereas solid sulfur, solid calcium, and gold have a definite lattice pattern and has a crystalline structure. Thus, they are not amorphous solids.

Thus, we can conclude that out of the given options glass is most likely to be amorphous.

the best answer here would be glass.

If 20.0 ml of glacial acetic acid (pure hc2h3o2 is diluted to 1.70 l with water, what is the ph of the resulting solution? the density of glacial acetic acid is 1.05 g/ml.

Answers

The pH of the resulting solution is 2.72

Data;

  • volume of acid = 20mL
  • density of acid = 1.05 g/ml
  • mass = 1.05 * 20  = 21g

pH of a solution

The number of moles of acetic acid is

n = 21/60 = 0.333 moles

The concentration of acetic acid in 1.7L is

c = (0.333)/(1.7) = 0.196M

The equation for dissociation is

CH_3COOH + H_2O \to CH_3COO^- +H_3O^+

The Ka of this reaction is

K_a = ([CH_3COO^-][H_3O^+)/([CH_3COOH)

The Ka of acetic acid = 1.8*10^-5

1.8*10^-^5 = (x*x)/(0.196) \nx = 0.187*10^-^2M\n

The concentration of hydrogen ion is

[H^+] = 1.87*10^-^3M

The pH of this solution is

pH = -log[H^+]\npH = -log(1.87*10^-^3)\npH = 2.72

The pH of the resulting solution is 2.72

Learn more on pH of a solution here;

brainly.com/question/25639733

Given:
20.0 ml of glacial acetic acid
1.70 L with water
density of the glacial acetic acid is 1.05 g/ml ; Ka = 1.8 x 10⁻⁵

1) find out how many grams of HC2H3O2 is in this glacial matter. It says here it has a density of 1.05g/mL. 
So we find the grams from that => 1.05 g/mL * (20.0 mL) = 21 grams of HC2H3O2. 
Convert this to moles => 21 grams (1 mol / 60 g) = 0.35 mol HC2H3O2 

We then get the Ka formula from that equation so it is 
Ka = [H3O+] [C2H3O2] / [HC2H3O2] (Remember H2O has an activity of 1 so we exclude it) 

We know the concentration of HC2H3O2 because we have moles of HC2H3O2 
Finding concentration of HC2H3O2 => 0.35 mol HC2H3O2/1.70 L = 0.20588 M - initial concentration

1.8 x 10⁻⁵ = (x) (x) / (0.20588 M - x)  
1.8 X 10⁻⁵ (0.20588 M) = x²
3.70584⁻ x 10⁻⁶ = x²
x = 1.9251 x 10⁻³

pH = -log (H₃O⁺) = - log (1.9251 x 10⁻³) = -(-2.7156) = 2.7156

pH of the resulting solution is 2.7156 

A 1.0 liter container is filled with 0.300 M ofPCl5 at 250◦C. The vessel is then held at a
constant temperature until the reaction
PCl5(g) ⇀↽ PCl3(g) + Cl2(g)
comes to equilibrium. It is found that the
vessel contains 0.200 moles of PCl5. What is
the value of the equilibrium constant for the
reaction at this temperature?

Answers

If there is 1.0 liters of 0.300 M at the beginning, that means there was 0.300 moles (because 1 L times 0.300 moles/L = 0.300 mol).  It says that, at equilibrium, there is 0.200 mol PCL5.  That means 0.100 mol PCl5 reacted.  Therefore, 0.100 mol each was created of PCl3 and Cl2.

Equilibrium constant Kc can be found with this:
K_c= (concentration\ of\ the\ products)/(concentration\ of\ the\ reactants)\nK_c=([PCl_3][Cl_2])/([PCl_5])=((0.100)(0.100))/((0.200))=0.0500