PHYSICS HIGH SCHOOL

Who was the woman to win Nobel Prize in physics in 1903?

Answers

Answer 1

Answer:

Answer:

Marie Curie

Explanation:

She was a physicist and chemist and also the first person to win the Nobel prize in physics

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Two bowling balls each have a mass of 6.9-kg.They are located next to each other with their centers 21.8-cm apart.What gravitational force do they exert on each other

Answers

We can start with Newton's Law of Universal Gravitation, which is
$F_(grav) = (G. m_(1) .m_(2))/d^(2)$
Otherwise known as... The force due to gravity between two objects is equal to G ( a universal constant G = 6.673 x 10-11 N m2/kg2) times the mass of the first object (kg) times the mass of the second object (kg) all divided by the distance between the two objects squared.

We can thus plug in the given values to receive the answer...
$F_(grav)=(6.673x10^(-11).(6.9)^(2))/(0.218)^2$
I converted the 21.8cm into 0.218m, for the equation calls for meters.

I hope this helps!
P.S. I'm currently enrolled in IB Physics, so if you have any more questions, feel free to contact me for help.

Final answer:

The gravitational force between two 6.9 kg bowling balls, which are 21.8 cm apart, is approximately 1.99 x 10^-9 Newtons, showing the relative weakness of gravitational forces at an everyday scale.

Explanation:

The gravitational force between two objects can be calculated using Newton's law of universal gravitation. The formula for this force is F = G * (M1 * M2) / R^2, where F is the force, G is the universal gravitational constant (6.67 × 10^-11 Nm^2/kg^2), M1 and M2 are the masses of the two objects, and R is the distance between the objects.

In this scenario, each of the bowling balls has a mass of 6.9 kg and their centers are 21.8 cm (or 0.218 m) apart. Substituting these values into the formula, we get the gravitational force to be approximately 1.99 x 10^-9 Newtons. This value is quite small, which is consistent with our intuition that everyday objects like bowling balls don't seem to attract each other noticeably — this is because the gravitational force is extremely weak in comparison to other forces such as electromagnetic forces.

Learn more about Gravitational Force here:

brainly.com/question/32609171

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What type of energy does a soccer player transfer to the ball?

Answers

kinetic energy plz mark me as brainlieset( i spelled that wrong)

Which scientist would best describe the motion of the earth?Ptolemy
Brahe
Kepler
Newton

Answers

Answer:

Newton

Explanation:

Ptolemy usually talked about "Earth-centered," or "geocentric" theory that all celestial objects — including the planets, Sun, Moon, and stars — orbited Earth. Earth, in the center of the universe, did not move at all and obviously this theory has been proven wrong.

Brahe model had all the planets (except Earth) orbiting around the Sun, but then the Sun orbited around the Earth. This is also a wrong concept.

Kepler's Laws are mostly based upon the Planetary Motion and are incomplete is some areas.

Only Newton law best describes the motion of all planets where he says that all motion, whether it was the orbit of the Moon around the Earth or an apple falling from a tree, followed the same basic principles.

Newton has the theory

An ultra-low friction pulley deal is as shown. The two weights experience an acceleration of 3.8m/s2. The first weight has 1.08kg. Find the mass of the second weight

Answers

Answer:

The mass of the second weight is approximately 0.477 kg

Explanation:

The given parameters are;

The acceleration experienced by the two weights = 3.8 m/s²

The mass of the first weight = 1.08 kg

The formula for the acceleration, a, of weights attached to a friction pulley, is given as follows;

$a = (g \cdot (M - m))/(M + m)$

Where;

a = The common acceleration of the two weights

g = The acceleration due to gravity = 9.81 m/s²

M = The mass of the first weight = 1.08 kg

m = The mass of the second weight

Therefore, we have;

$m = (M\cdot (g -a ))/(g + a) = (1.08* (9.81 -3.8 ))/(9.81 + 3.8) \approx 0.477$

The mass of the second weight = m ≈ 0.477 kg

The mass of the second weight ≈ 0.477 kg.

Two objects, Object A and Object B, need to be identified. Object A's index of refraction is determined to be 1.77, and Object B's index of refraction is determined to be 1.333. Knowing this information, which of the following must be true? A. Light can pass through Object A faster than it can pass through Object B.B. The optical density of Object A is lower than the optical density of Object B.
C. Light can pass through Object B faster than it can pass through Object A.
D. The optical density of Object B is higher than the optical density of Object A.

Answers

The correct answer is

C. Light can pass through Object B faster than it can pass through Object A.

In fact, the index of refraction of a material is defined as:

$n=(c)/(v)$

where c is the speed of light in vacuum and v is the speed of light in the material. Rearranging the equation, we can write the speed of light in the material as:

$v=(c)/(n)$

So we that, the smaller the refractive index n, the greater the speed of light in the material, v. In this problem, object B has lower refractive index than object A, so light travels faster in object B.

In the question "Two objects, Object A and Object B, need to be identified. Object A's index of refraction is determined to be 1.77, and Object B's index of refraction is determined to be 1.333. Knowing this information, which of the following must be true? A. Light can pass through Object A faster than it can pass through Object B." The correct answer is "Light can pass through Object B faster than it can pass through object A." (option C) The refractive index is a ratio of the speed of light in a medium relative to its speed in a vacuum. The refractive index of any other medium is defined relative to the refractive index of a vacuum, which is assigned a value of 1. Thus, a refractive index of 1.33 for water means that light travels 1.33 times faster in a vacuum than in water.

A 2.00 × 103 kg car rounds a circular turn of radius 20.0 m. If the road is flat and the coefficient of static friction between the tires and the road is 0.70, how fast can the car go without skidding?

Answers

Answer:

11.7 m/s

Explanation:

In order for the car to remain in circular motion along the road and not to skid, the frictional force between the tires and the road must be equal to the centripetal force.

Therefore, we can write:

$\mu mg = m(v^2)/(r)$