The ____ law of thermodynamics states that a quantity of energy can't be completely transferred from one form into another

Answers

Answer 1

Answer:

Answer:

the first law of thermodynamic

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A diet rich in high-density lipoproteins (HDLs) can help cleanse and open arteries that are clogged with plaque.a. True
b. False

Answers

Correct answer choice is :

A) True

Explanation:

Lipoproteins are essentially a hub full of fat and cholesterol, along with a lipid layer that includes proteins named apolipoproteins. There are many kinds of lipoproteins, but the two most prominent ones are called Low-Density Lipoprotein and HDL.LDL particles are seldom related to as bad lipoprotein because of concentrations, dose-related, associated with atherosclerosis change. High-density lipoproteins (HDL) get fat molecules from the body's cells and take it back to the liver.

The correct answer for the question that is being presented above is this one: "TRUE." A diet rich in high-density lipoproteins (HDLs) can help cleanse and open arteries that are clogged with plaque. The statement that is presented is True.

Why are the inner planets not made of light elements?

Answers

Outter planets lol !

A 25.0-meter length of platinum wire with a cross-sectional area of 3.50 × 10^−6 meter^2 has a resistanceof 0.757 ohm at 20°C. Calculate the resistivity of the wire. [Show all work, including the equation and
substitution with units.]

Answers

The resistivity of the plantinum wire is 1.06 × 10⁻⁷Ωm

Calculating Resistivity

From the question,

We are to determine the resistivity of the wire

Resistivity can be calculated from the formula

$\rho = (RA)/(l)$

Where $\rho$ is the resistivity of the wire

R is the resistance

A is the cross-sectional area

and $l$ is the length of the wire

From the given information,

R = 0.757 ohm (Ω)

A = 3.50 × 10⁻⁶ m²

$l$ = 25.0 m

Putting the parameters into the formula, we get

$\rho = (0.757 * 3.50 * 10^(-6) )/(25)$

$\rho = 0.10598 * 10^(-6)$

$\rho = 1.0598 * 10^(-7)$

$\rho \approx 1.06 * 10^(-7) \ \Omega m$

Hence, the resistivity of the plantinum wire is 1.06 × 10⁻⁷Ωm

Learn more on Calculating Resistivity here: brainly.com/question/5595373

R= (rou * L) / area
where R is the wire resistance
rou: resistivity of the wire material
L : wire length
A : cross section area of wire
by sub.
0.757= (rou*25)/ 3.5*10^-6
25*rou = 2.6495*10^-6
rou= 1.0598*10^-7 ohm.m

A 1200 kg car starts from rest and travels 100m in a time of 10 seconds . A) what is the acceleration of the car? B) what force must have acted on the car during this time? C) what is the velocity of the car after 10 seconds? D) what work was done on the car? E) what minimum power did the engine produce?

Answers

Given:
Mass (m) = 1200 kg
Distance (s) = 100 m
Time (t) = 10 seconds
Now,
$velocity (v) = (distance)/(time)$

= $(100~ m)/(10~seconds)$

= 10 m/s
Note that this one is the final velocity.
We also know that,
initial velocity (u) = 0 m/s .......because the car starts from rest.
Now,
$acceleration (a)= (change~in~velocity)/(time)$

= $(v-u)/(t)$

= $(10-0)/(10)$

= 1 m/s²
Now,
Force (F) = mass (m) * acceleration (a)
= 1200 kg * 1 m/s²
= 1200 kg.m/s²
= 1200 N
Now,
Work Done (W) = Force (F) * displacement (s) ....note that displacement is same as distance.
= 1200 N * 100 m
= 120000 N.m
= 120000 J
Now,
Power (P) = $(Work~done(W))/(time(t))$

= $(120000~J)/(10s)$

= 12000 J/s
= 12000 watt
SO,
A) The acceleration of the car is 1 m/s².
B) 1200 Newton (N) force must have acted on the car.
C) The velocity of the car after 10 seconds is 10 m/s.
D) 120000 Joule (J) work was done on the car.
E) The engine produced a minimum power of 12000 watt.

How are work, force, and distance related?