MATHEMATICS MIDDLE SCHOOL

I need help with the five on the bottom. The PowerPoint didn’t make sense to me so im hoping that someone can explain how to do these?

Answers

Answer 1

Answer:

Answer:

1) 3<x≤15

2) w>-3

3) t>2 and t<-6

4) q<-15 and q≥-3

5) -6<p<5

Step-by-step explanation:

I will solve one problem to show you.

1) -2<x-5≤10

add 5 on both sides

-2+5<x-5+5≤10+5

3<x<15

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Ignore my errors please. how would i solve these problems... please explain step by step

Answers

1.

Make the fractions improper.

72/12 x 19/6 = 19.

2.

Area = L x W

L = 3 1/6 x
W = 6 7/12

= 19.

#1 = 19 feet
#2 = 9 3/4 feet

A triangular pyramid has a base that is 31 feet and a height that is three times its base. What is the volume of the triangular pyramid?

Answers

Answer:

2,883

Step-by-step explanation:

Well the base of the triangle is

Put in order of smallest to the biggest these numbers 0.56, 0.4, 0.07, 0.34

Answers

In order from smallest to biggest, this is the order in which the following numbers would go --

0.07 (Or, 7%)

0.34 (Or, 34%

0.4 (Or, 40%)

0.56 (Or, 56%)

(Remember, to get the answer, you would multiply each decimal by 100 and then compare them all and put them in order that way. That's how I find it easiest to put decimals in smallest to biggest :D)

What is 11(x+10)+5x=11+7x

Answers

X = -11.

11(x+10)+5x=11+7x

11x + 110 + 5x = 11 + 7x

(11x + 5x) + 110 = 7x + 11.

16x + 110 = 7x + 11.

16x + 110 - 7x = 7x + 11 - 7x

9x + 110 + 11.

9x + 110 - 110 =11 - 110.

9x/9 = -99/9

X = -11

How to get answer by Mimiwhatsup:

$11\left(x+10\right)+5x=11+7x\n11\left(x+10\right)+5x\n\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\na=11,\:b=x,\:c=10\na=11,\:b=x,\:c=10\n\mathrm{Multiply\:the\:numbers:}\:11\cdot \:10=110\n=11x+110\n=11x+110+5x\n11x+110+5x\nGroup\:like\:terms\n=11x+5x+110\n\mathrm{Add\:similar\:elements:}\:11x+5x=16x\n=16x+110\n16x+110=11+7x\n\mathrm{Subtract\:}110\mathrm{\:from\:both\:sides}\n16x+110-110=11+7x-110\nSimplify\n16x=7x-99\n$

$\mathrm{Subtract\:}7x\mathrm{\:from\:both\:sides}\n16x-7x=7x-99-7x\n\mathrm{Simplify}\n9x=-99\n\mathrm{Divide\:both\:sides\:by\:}9\n(9x)/(9)=(-99)/(9)\nSimplify\n(9x)/(9)=x\n(9x)/(9)\n\mathrm{Divide\:the\:numbers:}\:(9)/(9)=1\n=x\n(-99)/(9)=-11\n(-99)/(9)\n\mathrm{Apply\:the\:fraction\:rule}:\quad (-a)/(b)=-(a)/(b)\n=-(99)/(9)\n\mathrm{Divide\:the\:numbers:}\:(99)/(9)=11\n\nAnswer: -11$

Directions: Drag each tile to the correct box.Order the following conditions in order from the largest number of possible triangles to the least number of possible triangles.

Condition A: a perimeter of 12 and even-numbered side lengths
Condition B: a side length of 4 inches, a side length of 5 inches, an included angle of 110º, and a perimeter of 11 inches
Condition C: a right triangle with an area less than 13 square inches and odd-numbered leg lengths greater than 1 inch
Condition D: an isosceles triangle with two angles that measure 50º

Answers

D, C, A nad then B
Figure out the number of possible triangles that fit condition A. There are 3 possible combinations of three even numbers that sum to 12.Of these three, there is only one where every length is less than the sum of the other two: 4 inches,4 inches, 4 inches. So, there is only one triangle that fits condition A.Figure out the number of possible triangles that fit condition B. Since the perimeter and two side lengths are given, subtract the two side lengths from the perimeter to get the length of the third side.Sketch a triangle with lengths of 2 inches, 4 inches, and 5 inches.From the sketch, the angle between the 4-inch length and 5-inch length has to be the smallest angle. Since it has to be the smallest angle, it cannot be more than a right angle. So, there is zero triangles that fit condition B.Figure out the number of possible triangles that fit condition C. For the area to be less than13 square inches, the product of the legs must be less than 26 square inches. The right triangles with odd-numbered legs greater than 1 inch whose product is less than 26 square inches are shown below.So, three triangles fit condition C.Figure out the number of possible triangles that fit condition D. If two angles of an isosceles triangle measure 50º, the third can be found by subtraction both angle measures from 180º.So, the angle measures must be 50º, 50º, and 80º. There is no condition on the lengths, so there are an infinite number of triangles that fit condition D.Therefore, the conditions in order of greatest possible triangles to least are shown below.condition D, condition C, condition A, condition B

Which of these expressions represent solutions to the equation

Answers

3 and -3

I think, I’m not really sure though.