MATHEMATICS HIGH SCHOOL

True or false a liter is 1000 times as much as a milliliter

Answers

Answer 1
Answer:

Answer:

True. A liter is indeed 1000 times as much as a milliliter.

Therefore, the statement "A liter is 1000 times as much as a milliliter" is true.

Step-by-step explanation:

To understand this, let's break it down:

1 liter (L) is a unit of volume equal to 1000 milliliters (mL). This means that if we have 1 liter of a substance, we can divide it into 1000 equal parts, each of which would be 1 milliliter.

So, in terms of quantity, 1 liter is 1000 times greater than 1 milliliter.

For example, if you have a 1-liter bottle of water and you pour it into milliliter-sized cups, you would need 1000 cups to contain the entire liter.

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Joe says there is a total of 40 students. Do you agree with Joe? Why or Why not?

Answers

Answer:

Step-by-step explanation:

Well the question you should be asking first is....what is part a? Because if you put that picture up i could mostly help sooo

The difference of a number q and 8

Answers

The difference of a number q and 8 is q-8.

It is required to write thedifference of a number q and 8.

What is algebra?

A part of mathematics in which letters and other general symbols are used to represent numbers and quantities in formulae and equations.

Given that:

considering the word "difference" means subtraction, so to  subtract 8 from q.

the difference of a number q and 8 is

q-8.

Therefore, the difference of a number q and 8 is q-8.

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8-q, considering the word "difference" means subtraction, so you are subtracting 8 from q.

HELLPP WORTH 20 POINTS ✨

Answers

Answer:

it's radius is 9 and diameter is 18

Answer:

diameter=18cm

radius =diameter/2=18/2=9cm

Determine the area word problem

Answers

Answer: 30 dollars in total

Step-by-step explanation: first multiply 15 times 0.75 which is 11.25 then multiply 15 times 1.25 which is 18.75 if you add these two numbers together you get 30 dollars which is the total amount spent.

hope this helps mark me brainliest if it helped

Answer:

(15 x 0.75) + (15 x 1.25)=$30

Step-by-step explanation

A curve is traced by a point P(x, y) which moves such that its distance from the point A(1, -2) is twice its distance from the point B(4, -3). Determine the equation of the curve.

Answers

|PA|=√((1-x)^2+(-2-y)^2)\n\n|PB|=√((4-x)^2+(-3-y)^2)\n\n|PA|=2|PB|\n\n√((1-x)^2+(-2-y)^2)=2√((4-x)^2+(-3-y)^2)\n\n(1-x)^2+(-2-y)^2=4[(4-x)^2+(-3-y)^2]\n\n1-2x+x^2+4+4y+y^2=4(16-8x+x^2+9+6y+y^2)

x^2+y^2-2x+4y+5=4(x^2+y^2-8x+6y+25)\n\nx^2+y^2-2x+4y+5=4x^2+4y^2-32x+24y+100\n\nx^2-4x^2-2x+32x+y^2-4y^2+4y-24y+5-100=0\n\n-3x^2+30x-3y^2-20y-95=0\ \ \ \ /:(-3)\n\nx^2-10x+y^2+(20)/(3)y+(95)/(3)=0\n\nx^2-2x\cdot5+5^2-5^2+y^2+2y\cdot(10)/(3)+\left((10)/(3)\right)^2-\left((10)/(3)\right)^2=-(95)/(3)

(x-5)^2+(y+(10)/(3))^2=-(95)/(3)+(100)/(9)+25\n\n(x-5)^2+(y+(10)/(3))^2=-(285)/(9)+(100)/(9)+(225)/(9)\n\n(x-5)^2+(y+(10)/(3))^2=(40)/(9)\n\nit's\ the\ circle\n\ncenter:(5;-(10)/(3))\n\nradius:r=\sqrt(40)/(9)=(√(4\cdot10))/(\sqrt9)=(2√(10))/(3)

Y = 10 + 16x − x^2y = 3x + 50
If (x1, y1) and (x2, y2) are distinct solutions to the system of equations shown above, what is the sum of the y1 and y2​?

Answers

Solving the system we can see that the sum of the y-values of the two solutions is 139.

How to get the sum of y₁ and y₂?

Let's solve the system of equations.

y = 10 + 16x − x²

y = 3x + 50

We can write this as a single quadratic equation:

10 + 16x - x² = 3x + 50

10 + 16x - x² - 3x - 50 = 0

-x² + 13x - 40 = 0

Using the quadratic formula we will get the two solutions for x:

x = (-13 \pm √(13^2 - 4*-1*-40) )/(-2) \n\nx = (-13 \pm 3 )/(-2)

So the two solutions are:

x = (-13 + 3)/-2 = 5

x = (-13 - 3)/-2 = 8

Evaluating the linear equation in these two values we will get y1 and y2.

if x = 5

y₁ = 3*5 + 50 = 65

if x= 8

y₂ = 3*8 + 50 = 74

The sum is:

65 + 74  =139

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Final answer:

The distinct solutions to the system of equations are (5, 65) and (8, 74), and the sum of the y-values is 139.

Explanation:

To find the sum of y-values of the distinct solutions to this system of equations, first, you need to set the two equations equal to each other to find the x-values of the solutions:

10 + 16x − x^2 = 3x + 50.

Then, solve the resulting equation for x:

x^2 - 13x + 40 = 0.

This is a quadratic equation, and it can be solved either by factoring or using the quadratic formula. The solutions for x result in:

x = 5 and x = 8.

These are the two distinct x-values for the intersections of the graphs of the two equations. To find the corresponding y-values, plug these x-values into either of the original equations. We'll use the simpler equation, y = 3x + 50:

For x = 5, y = 65 and for x = 8, y = 74.

Therefore, the distinct solutions to the system of equations are (5, 65) and (8, 74). Finally, the sum of y1 and y2 is 65 + 74 = 139.

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