3. Reading the graph, we find the velocity is 8 m/s at t-2 s and 16 m/s at t-4 s. Based on this information,what is the acceleration?

Answers

Answer 1

Answer: first take the change in time, which is the difference of 4 & 2, so 2 and that’s that’s denominator, then take the change in velocity, which is the difference of 16 and 8, which is 8 ( ur numerator)

8 / 2 = 4 so ur acceleration should be 4

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How long will it take a car to accelerate from 15.2 to 23.5 m/s if the car has an average acceleration of 3.2 m/s?

Answers

It will take a car, 2.59 s to accelerate from 15.2 to 23.5 m/s.

What is Speed?

speed is described as. the pace at which an object's location changes in any direction. Speed is defined as the distance traveled divided by the travel time. Speed is a scalar quantity because it just has a direction and no magnitude.

Given, the car has an average acceleration of 3.2 m/s².

To solve this problem, we can use the following kinematic equation:

v = u +at

where:

v is the final velocity (23.5 m/s)

u is the initial velocity (15.2 m/s)

a is the acceleration (3.2 m/s^2)

t is the time

We can rearrange this equation to solve for t:

t = (v -u)/a

substituting the values we have:

t = (23.5 - 15.2 ) / 3.2

t = 2.59375 seconds

Therefore, it will take approximately 2.59 seconds for the car to accelerate from 15.2 m/s to 23.5 m/s with an average acceleration of 3.2 m/s².

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Hello!

How long will it take a car to accelerate from 15.2 m/s to 23.5 m/s if the car has an average acceleration of 3.2 m/s² ?

We have the following data:

Vf (final velocity) = 23.5 m/s

Vi (initial velocity) = 15.2 m/s

ΔV (speed interval) = Vf - Vi → ΔV = 23.5 - 15.2 → ΔV = 8.3 m/s

ΔT (time interval) = ? (in s)

a (average acceleration) = 3.2 m/s²

Formula:

$a = \frac{\Delta{V}}{\Delta{T^}}$

Solving:

$a = \frac{\Delta{V}}{\Delta{T^}}$

$3.2 = \frac{8.3}{\Delta{T^}}$

$\Delta{T^} = (8.3)/(3.2)$

$\Delta{T^} = 2.59375 \to \boxed{\boxed{\Delta{T^} \approx 2.6\:s}}\:\:\:\:\:\:\bf\green{\checkmark}$

Answer:

The car will take approximately 2.6 seconds to accelerate

____________________________________

I Hope this helps, greetings ... Dexteright02! =)

Democritus was the first to state that matter is made of tiny particles that? a-cannot be divided b- can be divided c-are small and round

Answers

a. Cannot be divided.
He is also attributed with the creation of the name "Atomos" to indicate not-divisible.

Answer:

cant be dived or destroyed

Physics question WILL GIVE BRAINLIEST!!! A 1,600 kg train car rolling freely on level track at 16 m/s bumps into a 1.0 x 10^3 kg train car moving at 10.0 m/s in the same direction, and the two latch onto each other and continue together. What is their final speed?10 m/s
14 m/s
6.0 m/s
16 m/s

Answers

Answer:

$v'\approx 14\ m/s$

Explanation:

Linear Momentum

Two objects of masses and moving in a linear path at speeds and respectively have a total momentum of

$p=m_1v_1+m_2v_2$

When the objects collide, a change of conditions occurs and they start to move at different speeds. The necessary condition to find the after-colliding speeds is the conservation of linear momentum that states the total momentum of an isolated system doesn't change regardless of the internal interactions of the objects. Thus, the new momentum is

$p'=m_1v_1'+m_2v_2'$

And they must be the same, thus

$m_1v_1'+m_2v_2'=m_1v_1+m_2v_2$

We know both cars stick together after the collision, so the final speed is common to both, and the above formula becomes

$(m_1+m_2)v'=m_1v_1+m_2v_2$

Solving for v'

$\displaystyle v'=(m_1v_1+m_2v_2)/((m_1+m_2))$

Plugging in the values, we have

$\displaystyle v'=((1600)(16)+(1000)(10))/((1600+1000))$

$\boxed{v'=13.69\ m/s}$

Correct option (closest to the computed speed): 14 m/s

The velocity of the source is positive if the source is ______________. Note that this equation may not use the sign convention you are accustomed to. Think about the physical situation before answering.a. traveling in the +x direction
b. traveling toward the listener
c. traveling away from the listener

Answers

Answer: Answer is "B"

Explanation:

A physical situation of this question can be conceived as follows: If a siren is blowing through a certain distance in motion, then the listener find out that the velocity of the sound wave increases as the source of the siren is approaching the listener. The listener hear the maximum sound frequency and velocity of the source as it reaches him. However, the source velocity decreases as the siten moves away from the listener which can be said to be negative. Therefore, the correct answer is that the velocity increases as the source is moving towards the listener which is option "B"

Final answer:

In Physics, a positive velocity of a source usually indicates that the source is moving towards the observer or listener. This is based on the principles of the Doppler effect. The sign convention can change depending on the reference system

Explanation:

In the realm of Physics, particularly in the study of waves and sound, when we say that the velocity of the source is positive, it generally means that the source is traveling towards the listener. This is in line with the convention in Doppler effect, a phenomenon observed whenever the source of waves is moving with respect to the observer. Given this, the correct answer to your question would be (b) traveling toward the listener.

However, be mindful that the sign convention may vary depending on the context or the reference system being used. Still, the major principle remains: the perceived frequency is higher if the source is moving towards the observer, associated with a positive velocity; and lower if it's moving away, associated with a negative velocity.

Learn more about Velocity and Direction here:

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A dog looking for its bone in the yard, first heads 160.0° for 14.0 m and then turns and heads west for 8.50 m.a. What is the magnitude of the dog's displacement?
b. What is the direction of the dog's displacement?