Halothane is an alkyl halide used as an inhalational general anesthetic. Which of the following could be used to reduce an alkyl halide to an alkane? Please select the correct option: LiAlH4 Zn, H+ Mg in anhydrous ether, then water All of the above

Answers

Answer 1
Answer:

Answer:

The answer is D) All the above

Explanation:


Related Questions

What can be added to an atom to cause a nonvalence electron in the atom to temporarily become a valence electron?energymassneutronselectrons
Which condensed structural formula represents an unsaturated compound?(1) CH3CHCHCH3 (2) CH3CH2CH3 (3) CH3CH3(4) CH4
Which of these 1 M solutions will have the highest pH?(1) NaOH (3) HCl(2) CH3OH (4) NaCl
Using ohm's law, explain how voltage changes in relation to current, assuming that resistance remains constant.
When the blood supply to a portion of the brain is blocked, this causesa. a. blackout b. dizzy spells c. stroke d. heart attack

Which of these statements is correct about how the first forms of life appeared on Earth?A.Non-living molecules evolved into living molecules by chemical changes.
B.Reproducing molecules evolved into living organisms by biological processes.
C.Rocks and fossils were transformed into living molecules by biological processes.
D.Atmospheric gases were transformed into living organisms by chemical changes.

Answers

the answer to your question would be A


hope i heled

Answer:

A.  Non-living molecules evolved into living molecules by chemical changes.

Explanation:

The atomic mass of an element is 32.07 u and its atomic number is 16. The number of protons contained in the nucleus of an atom of this element is (A) 16
(B) 31
(C) 32
(D) 48

Answers


I THINK IT IS 16 BECAUSE THE ATOMIC NUMBER AND THE NUMBER OF PROTONS ARE THE SAME
atomic number = number of electrons = number of protons( by JJ thomson's theory)

Thus, the number of protons is 16

making predictions, categorizing things, spotting something unusual, identifying themes, discovering connections, finding patterns are all apart of?

Answers

Monopoly GO! bye bye guys i gtg

Which of the notations below is another way to write the name of the following nuclide?A.iodine-53

B.iodide-53

C.iodide-127

D.iodine-127

Answers

Answer: D.iodine-127:


Explanation:


1) As per the definition of nuclide, it is the atomic spieces (the atom) characterized by the nucleons (protons and neutros).

2) To notation for a nuclide is the name of the atom followed by a hypen (without blank spaces) and the mass number.

3)   The mass number is the sum of protons and neutrons.

4) From that, you can tell this about the four choices given:

A.iodine-53: is not correct because that would mean that the mass number is 53, which cannot be right as the atomic number of iodine is 53 meaning that it has 53 protons, and so that notation is not including the neutrons.

B.iodide-53: is not correct because the name of the atom is iodine, not iodide (also the mass number cannot be for the same reason explained above)


The name iodide is reserved for the ions from iodine not for the atom.


C.iodide-127: incorrect due to the name iodide, for the same reason explained above.


D.iodine-127: this is correct choice. It is the name of the isotope of the iodine with mass number 127, which means that the atom has 53 protons and 74 neutrons (53 is the atomic number and 74 is calculated from 127 - 53)


Answer:

iodine-127

Explanation:

I did a quiz and it was correct.



Bombarding sodium-23 with a
proton produces nuclide X and a neutron. What is nuclide X?









Answers:



magnesium-24






magnesium-23






neon-23





s
odium-24






none of the above




The isotope P
has a half-life of 14.3 days. If a sample originally contained 1.00 g of P,
how much was left after 43 days?







Answers:


0.250 g






0.125 g





0.750 g






0.500 g




Identify X in the reaction
below.
 U
+  C
→  Cf
+ X








Answers:



1
alpha particle






3
protons






6
neutrons





6
electrons







A .20 gram sample of C-14 was allowed to decay for 3 half-lives.  What mass
of the sample will remain?  Carbon-14 has a half life of 5730
years.  







Answers:



0.025






0.05







0.1






0
.01






0.05







The isotope Cu
has a half-life of 30 s. If a sample originally contained 48 mg of Cu,
how much time passed before the amount fell to 3 mg?



Answers:



120 s






240s



30 s





60 s
(when I did my calculation for the question above, I got 60 seconds)



What radionuclide decays to Fe-56
by beta emission?









Answers:


 Fe





 Co





 Mn





 Co





 Mn
How do I know wat it becomes. I put 57 Co 27 and it's wrong.




The Cf
to Cf
conversion is accompanied by __________.








Answers:



an alpha
emission






a
neutron capture






an electron
capture






an electron release
I would greatly appreciate your help...ASAP. Thank you.

Answers

Bombarding sodium-23 with a proton produces nuclide X and a neutron. What is nuclide X?

^(23)_(11)Na--^(\beta^+)--> ^(23)_(10)Ne + e^(+)

answer:  neon
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
The isotope P has a half-life of 14.3 days. If a sample originally contained 1.00 g of P, 
how much was left after 43 days?

0 days >>> 1.00g
14,3 days >>> 1.00g :2 = 0,5g
(14.3+14.3) days >>> 0.5g : 2 = 0.25g
(14.3+14.3+14.3) days >>>  0.25g : 2 = 0.125g 

answer: 0.125g
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Identify X in the reaction 
below.
 U +  C →  Cf + X

^(238)_(92)U ---> ^(251)_(98)Cf+6e^-

answer: 6 electrons  (so it's beta
⁻)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

A .20 gram sample of C-14 was allowed to decay for 3 half-lives.  What mass 
of the sample will remain?  Carbon-14 has a half life of 5730 
years.  

at the beginning >>> 0.20g
1 half-live >>> 0.20g : 2 = 0.10g
2 half-live >>> 0.10g : 2 = 0.05g
3 half-live >>> 0.05g : 2 = 0.025g

answer: 0.025g
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The isotope Cu has a half-life of 30 s. If a sample originally contained 48 mg of Cu, 
how much time passed before the amount fell to 3 mg?

0 s (at the beginning) >>> 48mg
30s >>>>>>>>>>>>>>> 48mg : 2 = 24mg
(30+30)s >>>>>>>>>>> 24mg : 2 = 12mg
(30+30+30)s >>>>>>>> 12mg : 2 = 6mg
(30+30+30+30)s >>>>> 6mg : 2 = 3mg

answer: 30+30+30+30 = 120s
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
What radionuclide decays to Fe-56 by beta emission?

^(56)_(26)Fe--^(\beta^-)-->^(56)_(27)Co + e^-

answer: ⁵⁶₂₇Co
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
The Cf to Cf conversion is accompanied by __________.

Cf to Cf ????  maybe...mistake?

Carbon monoxide (CO) reacts with hydrogen (H2) to form methane (CH4) and water (H20).CO(g) + 3H2(g) + CH4(g)+H20(9)
The reaction is at equilibrium at 1,000 K. The equilibrium constant of the reaction is 3.90. At equilibrium, the concentrations are as
follows.
[CO] = 0.30 M
[H2] = 0.10 M
[H20] = 0.020 M
What is the equilibrium concentration of CH, expressed in scientific notation?
0.0059
5.9 x 10-2
0.059
5.9 x 102

Answers

Answer: The equilibrium concentration of CH_4 , expressed in scientific notation is 5.9* 10^(-2)M

Explanation:

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients.

The given balanced equilibrium reaction is,

                          CO(g)+3H_2(g)\rightleftharpoons CH_4(g)+H_2O(g)

At eqm. conc.     (0.30) M     (0.10) M      (x) M   (0.020) M

The expression for equilibrium constant for this reaction will be,

K_c=([CH_4]* [H_2O])/([CO]* [H_2]^3)

Now put all the given values in this expression, we get :

3.90=(x* (0.020))/((0.30)* (0.10)^3)

By solving the term 'x', we get :

x = 0.059 M=  5.9* 10^(-2)M

Thus, the concentrations of CH_4 at equilibrium is :

Concentration of CH_4 = (x) M  = 5.9* 10^(-2)M

The equilibrium concentration of CH_4 , expressed in scientific notation is 5.9* 10^(-2)M

Answer:B

Explanation:B