"For a many-electron atom, which of the following sublevels has the highest energy? A. 3p. B. 3d. C. 3s. D. 4s".

Answers

Answer 1
Answer: Empty 4s orbitals are slightly lower in energy than empty 3d orbitals however, in the context of this question, in a many electron atom where the 4s orbitals are filled, they are repelled to a higher energy level than 3d orbitals and hence the answer should be D.

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I have an unknown volume of gas at a pressure of 0.5 atm and a temperature of 325k if I raise the pressure to 1.2 atm, decrease the temperature to 320k, and measures the final volume to be 48 liters what was the initial volume of the gas?

Answers

The initial volume of the gas is 117L.

What is volume?

Volume is the amount of space the matter occupies.

What do you mean by combined gas law?

  • The combined gas law combines the three gas laws: Boyle's Law, Charles' Law, and Gay-Lussac's Law.
  • It states that the ratio of the product of pressure and volume and the absolute temperature of a gas is equal to a constant.
  • When Avogadro's law is added to the combined gas law, the ideal gas law results.
  • It is a combination of the other gas laws that works when everything except temperature, pressure, and volume are kept constant.
  • There are a couple of common equations for writing the combined gas law. The classic law relates Boyle's law and Charles' law to state:

                                     PV/T = k

where P = pressure, V = volume, T = absolute temperature in K and k= constant.

  • Another common formula for the combined gas law relates before and after conditions of a gas:

          P1V1 / T1 = P2V2 / T2

Where P1 and P2 = initial and final pressure in atm

           T1 and T2 = Initial and final temperature in K

            V1 and V2 = initial and final volume in L

Using combined gas law:

P1V1/T1 = P2V2/T2

Given:

P1 = 0.5 atm

T1 = 325K

P2 = 1.2 atm

V2 = 48L

T2 = 320K

Assuming that the number of moles are constant for both conditions:

(P1 x V1)/T1 = (P2 x V2)/T2

Substituting the given values,

(0.5 x V1)/325 = (1.2 x 48)/320K

Solving for V1

V1 = (1.2atm x 48L x 325K)/ (320Kx 0.5 atm)

 V1   = 117L

 Hence, the initial volume of the gas is 117L.

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Use the Equation of Clapeyron:

(P_1.V_1)/(T_1)=(P_2.V_2)/(T_2)\n \n (0.5V_1)/(235)=(1.2*48)/(320)\n \n 320*0.5V_1=235*1.2*48\n \n V_1=(235*1.2*48)/(320*0.5)=84.5 liters

Need Help with my Chemistry please!!Which of the following is not an outcome of acid rain?
-altercation crust on marble statues
-plant death due to nutrients becoming toxic
-suffocation of fish
-corrosion of metal surfaces

Which of the following materials is damaged by acid rain?
-quartz
-marble
-aluminum
-glass

The ozone layer absorbs most of the incoming ____ radiation.
-infrared
-X-ray
-ultraviolet
-radio

Thank you very much~!!

Answers

Which of the following materials is damaged by acid rain? marble

The ozone layer absorbs most of the incoming ____ 
ultraviolet

An equilibrium mixture of PCl5(g), PCl3(g), and Cl2(g) has partial pressures of 217.0 Torr, 13.2 Torr, and 13.2 Torr, respectively. A quantity of Cl2(g) is injected into the mixture, and the total pressure jumps to 263.0 Torr (at the moment of mixing). The system then re-equilibrates. The appropriate chemical equation is:PCl3(g) + Cl2(g) ---> PCl5(g)

Calculate the new partial pressures after equilibrium is reestablished. [in torr]

PPCl3

PPCl2

PPCl5

Answers

equilibrium is a situation in which economic forces such as supply and demand are balanced and in the absence of external influences the values of economic variables will not change

The equilibrium constant depends on the following:-

  • Pressure
  • Volume

The formula used in the question is as follows:-

k_p = (P_1)/(P_1*P_2), After putting the value, the equilibrium constant is as follows:-

k_p = (217)/(13.2*13.2)

After solving it, the equilibrium constant is 1.245.

The pressure in different systems is as follows:-

Hence, the total pressure is:- P_1 + P_2+ P_3

263 = 13.2 + P_2 + 217

After solving it, the P2 is 32.8torr.

The equilibrium constant in the second case is:-

k_p = (P_1^')/(P_1^' * P_2^')

After putting the value,

1.245= (217+x)/((13.2-x )* (32.8-x))

After solving, the value of x is 6.402torr

Hence, the partial pressure PCL_3,\ CL2, \ PLC_5\ is 6.798, 26.398, and 223.402 respectively.

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Answer:

The new partial pressures after equilibrium is reestablished for PCl_3:

P_1'=6.798 Torr

The new partial pressures after equilibrium is reestablished Cl_2:

P_2'=26.398 Torr

The new partial pressures after equilibrium is reestablished for PCl_5:

P_3'=223.402 Torr

Explanation:

PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)

At equilibrium before adding chlorine gas:

Partial pressure of the PCl_3=P_1=13.2 Torr

Partial pressure of the Cl_2=P_2=13.2 Torr

Partial pressure of the PCl_5=P_3=217.0 Torr

The expression of an equilibrium constant is given by :

K_p=(P_1)/(P_1* P_2)

=(217.0 Torr)/(13.2 Torr* 13.2 Torr)=1.245

At equilibrium after adding chlorine gas:

Partial pressure of the PCl_3=P_1'=13.2 Torr

Partial pressure of the Cl_2=P_2'=?

Partial pressure of the PCl_5=P_3'=217.0 Torr

Total pressure of the system = P = 263.0 Torr

P=P_1'+P_2'+P_3'

263.0Torr=13.2 Torr+P_2'+217.0 Torr

P_2'=32.8 Torr

PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)

At initail

(13.2) Torr     (32.8) Torr                        (13.2) Torr

At equilbriumm

(13.2-x) Torr     (32.8-x) Torr                        (217.0+x) Torr

K_p=(P_3')/(P_1'* P_2')

1.245=((217.0+x))/((13.2-x)(32.8-x))

Solving for x;

x = 6.402 Torr

The new partial pressures after equilibrium is reestablished for PCl_3:

P_1'=(13.2-x) Torr=(13.2-6.402) Torr=6.798 Torr

The new partial pressures after equilibrium is reestablished Cl_2:

P_2'=(32.8-x) Torr=(32.8-6.402) Torr=26.398 Torr

The new partial pressures after equilibrium is reestablished for PCl_5:

P_3'=(217.0+x) Torr=(217+6.402) Torr=223.402 Torr

The multiple covalent bond in a molecule of 1-butene is a(1) double covalent bond that has 6 shared electrons
(2) double covalent bond that has 4 shared electrons
(3) triple covalent bond that has 6 shared electrons
(4) triple covalent bond that has 4 shared electrons

Answers

Answer: Option (2) is the correct answer.

Explanation:

An alkene is a molecule that contains a hydrocarbon chain with atleast one double bond.

For example, H_(2)C=CH-CH_(2)-CH_(3) is a 1-butene molecule and it contains one double bond that consists of four shared electrons.

On the other hand, a molecule of hydrocabon that contains a triple bond is known as an alkyne. Whereas a hydrocarbon that contains only single bonds is known as an alkane.

Thus, we can conclude that the multiple covalent bond in a molecule of 1-butene is a double covalent bond that has 4 shared electrons.

(2) double covalent bond that has 4 shared electrons 

Which one of the following equations is not balanced?6H2O + 6CO2 ---> C6H12O6 + 6O2
C7H16 + 11O2 ---> 7CO2 + 8H2O
PCl2 + 4H2O --->H3PO4 + 5HCL
Fe3O4 + 4H2 ---> 3Fe + 4H2O

Answers

The key inthe balancing of chemical reaction is to make sure that you got the exactchemical formula of the substance that is reacting and the yielded product.After getting the formula, identify first the hardest element/atom to bebalanced such as Na, Zn, Cl, C, O, etc. Then proceed to the easier ones such asO, H. Make sure to note the atoms present in the molecule of the substance. Amongthe three equations, PCl2 + 4H2O --->H3PO4 + 5HCL is not balanced. Thehardest element here is the Cl. Observe that there are 5Cls in the product sideso you must add 5 to the PCl2. However, there are only 2Cl atoms and it needs3 to balance the equation. Also, there is no P in the product side. This equationis invalid.
The third one is incorrectly balance because the are only two chlorine on the reactant side and five on the product side. The correct balanced equation is 2PCL2 + 8H2O -> 2H3PO4 + 5H2 + 4Cl. The reason HCl is broken into two parts is because it is a strong acid and would immediately dissolve if put together.

How does an object's mechanical energy change as its speed (velocity) increases?

Answers

Answer:

The mechanical energy of the system increases, provided there is no loss of energy due to friction. The energy would transform to kinetic energy when the speed is increasing. The mechanical energy of the system remains constant provided there is no loss of energy due to friction.

Explanation:

Final answer:

An object's mechanical energy generally increases as its velocity increases. This is because mechanical energy is the sum of an object's kinetic and potential energy, and kinetic energy is directly proportional to the square of its velocity.

Explanation:

In physics, mechanical energy is the energy that an object has due to its motion (kinetic energy) and position (potential energy). When an object's speed or velocity changes, specifically increases, so does its kinetic energy, as kinetic energy is directly proportional to the square of the object's velocity. Essentially, if an object's velocity doubles, its kinetic energy would quadruple. However, this does not take into account variables like air resistance, friction, or changes in potential energy. In an ideal, frictionless scenario, an increase in an object's velocity directly results in an increase in its mechanical energy.

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