CAN ANYONE PLEASE HELP WITH MATH?The rectangle has an area of 4(x+3) square units.
A- If the dimensions of the rectangle are doubled, what is the area of the new rectangle in terms of x? Show your work.
B- Will the ratio of the area of the original rectangle to the area of the larger rectangle be the same for any positive value of x? Explain.
Answers
If it has an area of 4(x+3) we can think that one side has a length of 4, and the other has a length of (x+3).
So, if the dimensions were doubled, 4 x 2 = 8. And 2(x+3) = 2x+6.
The new area would be:
8(2x+6) = 16x+48.
B)
The ratio will be the same. For example lets plug in some points:
x=0
4(0+3) = 4(3) = 12
And
16(0)+48 = 0+48 = 48
So the ratio is 48/12 = 4
Lets plug in another point.
x=2
4(2+3)= 4(5) = 20
And
x=2
16(2)+48 = 32 + 48 = 80
80/20 = 4
So the ratio is the same :)
if we double the dimensions of the rectangle, the area will be fourfold:
B- yes, it will always be the same because:
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pick three number that is multiple of 4 and add them up will be 24
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Answers
Answer:
4.002 4.022 4.221
Step-by-step explanation:
dont be mad if i did it wrong cuz that's how i was taught and anyways the smaller one is always bigger according to my teachers
X+3y=73
X+y=27
Answers
1. Change x + y= 27 into y=mx+ b form
2. Subtract x on both sides
Y= -x + 27
3. Substitute the y in x + 3y= 73 for -x + 27
X + 3(-x + 27) = 73
X + -3x + 81= 73
-2x + 81= 73
4. Now subtract 81 on both sides
-2x=-8
5. X= 4
6. Now solve for y
7. Now substitute the x in x + y= 27 for 4
8. 4 + y= 27
9. Subtract 4 on both sides
10. Y= 23
11. Your answer is: x= -4 and y= 23 or (-4,23)
x+y=27
Multiply the second equation by -3.
x+3y=73
-3x-3y=-81
Now add.
-2x=-8
x=4
Plug in 4.
4+y=27
Subtract 4 from both sides.
y=23
Answers
Answer: Nine
Step-by-step explanation:
7+9+11+13 = 40
They are all consecutive odd numbers, and add up to 40. 7 +13 is twenty, and 9+11 is also twenty, making forty. The second number in this sequence is 9