Help please I need this done like right now

Answers

Answer 1

Answer:

Answer:

$\left(\begin{array}{c}-24\n20\end{array}\right)$

Step-by-step explanation:

Given vectors:

$\textbf{a}=\left(\begin{array}{c}-9\n7\end{array}\right)\n\n\n \textbf{b}=\left(\begin{array}{c}12\n-20\end{array}\right)\n\n\n\textbf{c}=\left(\begin{array}{c}0\n-16\end{array}\right)$

$\textsf{To calculate}\;\;3\textbf{a}-(1)/(4)(\textbf{c}-\textbf{b}),\;\;\textsf{substitute the given vectors into the expression:}$

$3\left(\begin{array}{c}-9\n7\end{array}\right)-(1)/(4)\left(\begin{array}{ccc}0&-&12\n-16&-&(-20)\end{array}\right)$

When subtracting vectors, we subtract the elements in the same position from one vector from the elements in the same position of the other vector. Therefore, subtracting vector b from vector c gives:

$3\left(\begin{array}{c}-9\n7\end{array}\right)-(1)/(4)\left(\begin{array}{c}-12\n4\end{array}\right)$

When multiplying a vector by a constant, we multiply each component of the vector by that constant. Therefore, multiplying vector a by 3 gives:

$\left(\begin{array}{c}3\cdot(-9)\n3\cdot 7\end{array}\right)-(1)/(4)\left(\begin{array}{c}-12\n4\end{array}\right)$

$\left(\begin{array}{c}-27\n21\end{array}\right)-(1)/(4)\left(\begin{array}{c}-12\n4\end{array}\right)$

Multiply (c - b) by 1/4:

$\left(\begin{array}{c}-27\n21\end{array}\right)-\left(\begin{array}{c}-12\cdot (1)/(4)\n4\cdot (1)/(4)\end{array}\right)$

$\left(\begin{array}{c}-27\n21\end{array}\right)-\left(\begin{array}{c}-3\n1\end{array}\right)$

Finally, subtract the vectors:

$\left(\begin{array}{ccc}-27&-&(-3)\n21&-&1\end{array}\right)$

$\left(\begin{array}{c}-24\n20\end{array}\right)$

$\textsf{So,}\;\;3\textbf{a}-(1)/(4)(\textbf{c}-\textbf{b})\;\;\textsf{is equal to}\;\;\left(\begin{array}{c}-24\n20\end{array}\right).$

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So the distance of a aircraft flies a proportional relationship whith its number of hours inflight. The table shows the number of miles flown for a number of hours in flight. Find the constant of proportionality. How long will the jet take to travel 5,880.

Answers

The constant of proportionality is k = 490 and the equation is y = 490x where x is the number of hours and y is the total number of miles

The time required is 12 hours

What is Proportion?

The proportion formula is used to depict if two ratios or fractions are equal. The proportion formula can be given as a: b::c : d = a/b = c/d where a and d are the extreme terms and b and c are the mean terms.

The proportional equation is given as y ∝ x

And , y = kx where k is the proportionality constant

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Given data ,

Let the equation be represented as A

Now , the value of A is

Let the distance of the aircraft be = x

Let the total time taken by the aircraft be = y

Let the constant of proportionality be k

when x = 1 ,

y = 490

So , the equation will be y = kx

Substituting the values in the equation , we get

y = 490x

when x = 2

y = 490 ( 2 )

y = 980

Now , the time taken by aircraft to travel 5,880 miles is

Substitute the value of y as 5880 in the equation , we get

5880 = 490x

Divide by 490 on both sides of the equation , we get

x = 5880 / 490

x = 12

Therefore , the time taken is 12 hours

Hence , the constant of proportionality is 490

To learn more about proportion click :

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Answer:

The constant of proportionality is 490

The jet will take 12 hours to travel 5,880 miles

Step-by-step explanation: The miles multiply by 490 each time.

490 x 12 is 5,880

If i have 900 gallons of gas. how much tank does do we need to fill up 20?

Answers

Answer:

18000

Step-by-step explanation:

Answer:

the answer is 18000

Step-by-step explanation:

900 gallons multiply 20

so our answer is =18000

Finish the sequence
1,1,2,3,5,8,_,_,_

Answers

This is a Fibonacci sequence
1; 1
1 + 1 = 2
1 + 2 = 3
2 + 3 = 5
3 + 5 = 8
next terms:
5 + 8= 13
8 +13 = 21
13 + 21 = 34

The Fibonacci sequence has to be thought of in these terms:

F₀, F₁, F₂, F₃, F₄, F₅, F₆, F₇, etc, etc

----------------------

Now:

F₀=0

F₁=1

The formula you use to get the other numbers is:

$F_(n) = F_(n-1) + F_(n-2)$

--------------

So:

$F_(2) = F_(2-1) + F_(2-2) = F_(1) + F_(0) =1+0=1$

And:

$F_(3)= F_(3-1) + F_(3-2) = F_(2) + F_(1) =1+1=2$

------------

If you continue using the formula, you should get a sequence that starts off like this:

0, 1, 1, 2, 3, 5, 8, 13, 21, 34, etc, etc

4.- UN RELOJERON COBRO $391.40 POR COMPONER 3 RELOJES; ¿CUANTO COBRARA POR ARREGLAR 5 RELOJES?

Answers

El relojeron les cobrará 652.33 por los 5 reloj ya que cada reloj vale 130.46

Can somebody help me answer this question whoever gets it right will get branlist !

Answers

Answer: x=17

Step by Step:

Suppose you throw a dart at a circular target of radius 10 inches. Assuming that you hit the target and that the coordinates of the outcomes are chosen at random, find the probability that the dart falls (a) within 2 inches of the center. (b) within 2 inches of the rim. (c) within the first quadrant of the target. (d) within the first quadrant and within 2 inches of the rim.

Answers

Answer:

a) The probability is 0.04

b) The probability is 0.36

c) The pprobability is 0,25

d) The probability is 0.09

Step-by-step explanation:

Lets calculate areas:

the target has a radius of 10 inces, hence the target area has a area on 10²*π = 100π square inches.

a) A circle of 2 inches of radius has an area of 2²π = 4π square inches, hence the probability of hitting that area is 4π/100π = 1/25 = 0.04

b) If the dart s within 2 inches of the rim, then it is not at distance 8 inches from the center (that is the complementary event). The probability for the dart to be at 8 inches of the center is 8²π/100π = 64/100 = 16/25 = 0.64, thus, the probability that the dart is at distance 2 or less from the rim is 1-0.64 = 0.36.

c) The first quadrant has an area exactly 4 times smaller than the area of the target (each quadrant has equal area), thus the probability for the dart to fall there is 1/4 = 0.25

d) If the dart is within 2 inches from the rim (which has probability 0.36 as we previously computed), then it will be equally likely for the dart to be in either of the 4 quadrants (the area that is within 2 inches from the rim forms a ring and it has equal area restricted on each quadrant). Therefore, the probability for the dice to be in the first qudrant and within 2 inches from the rim is 0.36*1/4 = 0.09.

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