Using the value of atmospheric pressure at sea level, 1 × 105 Pa, estimate the total mass of the earth's atmosphere above a 5-m2 area.

Answers

Answer 1
Answer:

Answer:

5×10^4 kg

Explanation:

pressure= force/Area

area= 5m^2

pressure = 1×10^5 Pa

1×10^5=mg/5 (weight will be the force)

5×10^5=m×10 (gravitational field strength of the earth)

5×10^5×10^-1 =m

mass=5×10^4 kg!

hope this helps!


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Explain why solar energy is considered an inexhaustible source of energy

Answers


-- The amount of energy radiated by the sun is not affected at all by how much
of it we use or don't use.

-- The sun is not expected to quit shining on us, or to change its rate of energy
output, at any time within the next several many human lifetimes.

Solar energy is going to keep arriving here, continuously, at the same rate,
free of charge, for a long long time, whether we feel like using it or not.  It's
the closest thing to manna from heaven that has been seen around here for
thousands of years.


'When we see something that exists in real life, there are many different ways to display imagery and importance using art. What the artist _____________ depends on what he/she wants to communicate.'

Answers

Answer:

Emphasizes

Explanation:

The expression of an art is intelligible to those that understand it, as such to make an impression an artist has to emphasize the point they want to communicate

An art is an expression of the personal experiences of the artist or a reaction to events or to reveal the realities as seen by the artist such as global warming and the environment, so as to get the attention of people with the goal to change them, such that a good art changes the most people, hence the need for emphasis.

Answer:

A - emphasizes

A water wave has a frequency of 2 HZ and a wavelength of 5 meters what is its speed

Answers

Speed, v = fλ.

Where f is the frequency in Hertz, wavelength is in meters.

Speed, v = 2*5 = 10

Speed = 10 m/s. 

Help Please ! A fisherman casts his lure at an angle of 33 degrees above the horizontal. The lure reaches a maximum height of 2.3 m. Assuming no frictional forces, what was the initial velocity the fisherman gave the lure when he cast it? 12.34 m/s


28.45 m/s


34.91 m/s


21.29 m/s

Answers

The initial velocity is 12.34 m/s

Explanation:

The vertical component of the initial velocity determines the maximum height.

The formula to apply is : v²=u²+2as , where

v=y-component, final velocity = 0 m/s

u= y-component of the initial velocity = ?

s= distance traveled = 2.3 m

a=acceleration due to gravity = -9.81 m/s²

Using the values in the equation

v²=u²+2as

0²=u²+2×2.3×-9.81

0=u²-45.126

45.126=u²

√45.126= u

6.7175 m/s

The vertical component of velocity is given by;

velocity*sin(angle with horizontal)

velocity=6.7175 / sin 33°

=12.338 m/s

=12.34 m/s

Learn More

Finding Initial velocity :brainly.com/question/1858995

Keywords : angle, maximum height, initial velocity, friction

#LearnwithBrainly

Data is information from which conclusions can be drawn.. . True. False

Answers

That statement is True. 

Data will show you the element that you need to draw conclusion of your study/experiment.
For example, if after you gather the the data from 100 heart patient and 70 percent of them are obese, you can draw a conclusion that obesity is linked with heart disease

hope this helps
you can draw conclusions from data, so it would be true

Two objects, Object A and Object B, need to be identified. Object A's index of refraction is determined to be 1.77, and Object B's index of refraction is determined to be 1.333. Knowing this information, which of the following must be true? A. Light can pass through Object A faster than it can pass through Object B.B. The optical density of Object A is lower than the optical density of Object B.
C. Light can pass through Object B faster than it can pass through Object A.
D. The optical density of Object B is higher than the optical density of Object A.

Answers

The correct answer is

C. Light can pass through Object B faster than it can pass through Object A.

In fact, the index of refraction of a material is defined as:

n=(c)/(v)

where c is the speed of light in vacuum and v is the speed of light in the material. Rearranging the equation, we can write the speed of light in the material as:

v=(c)/(n)

So we that, the smaller the refractive index n, the greater the speed of light in the material, v. In this problem, object B has lower refractive index than object A, so light travels faster in object B.

In the question "Two objects, Object A and Object B, need to be identified. Object A's index of refraction is determined to be 1.77, and Object B's index of refraction is determined to be 1.333. Knowing this information, which of the following must be true? A. Light can pass through Object A faster than it can pass through Object B." The correct answer is "Light can pass through Object B faster than it can pass through object A." (option C) The refractive index is a ratio of the speed of light in a medium relative to its speed in a vacuum. The refractive index of any other medium is defined relative to the refractive index of a vacuum, which is assigned a value of 1. Thus, a refractive index of 1.33 for water means that light travels 1.33 times faster in a vacuum than in water.