which of the following is not an example of a graph of a single variable? a. a pie chart b. a bar graph c. a time-series graph

Answers

Answer 1

Answer: I think the answer would be a bad graph

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Solve for f is h=2f/m+1

Answers

h=2f/m+1
subtract one from both sides
h-1=2f/m
multiply m to both sides
m*h-1=2f
divide 2 both sides
mh-1/2=F
(the whole left side of the equation is divided by 2 i just cant do it on the computer)

Which answer is the solution set in simplest form?4x-1/3=7/1
a 4/3
b 7/3
c 3/2
d 11/2

Answers

In this question there is 1 equation with 1 unknown variable. So it is absolutely possible to find the value of the unknown variable "x".
(4x - 1)/3 = 7/1
4x -1 = 7 * 3
4x - 1 = 21
4x = 21 + 1
4x = 22
x = 22/4
= 11/2
So the value of the unknown variable x is 11/2. So the correct option is option "d". Hope i have answered your question correctly and helped you to understand the method by which these problems should be done.

Draw or write to explain why 1 hundred 4 tens and 14 tens name the same amount

Answers

Solving the expressions, we find 140 = 140, thus, they are the same amount.

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One hundred is 1 multiplied by 100, thus $1 * 100 = 100$
4 tens is 4 multiplied by 10, thus $4 * 10 = 40$
1 hundred 4 tens is $100 + 40 = 140$

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14 tens is 14 multiplied by 10, thus $14 * 10 = 140$
Applying the multiplications, that is, solving the expressions, we get the same amount, this is why the measures are the same amount.

A similar problem is given at brainly.com/question/20742606

1 hundred can also be 10 tens so when you add 10 tens and 4 tens you 14 tens and that is the same thing as 14 tens

A bin contains red balls and purple balls. A ball is selected at random and then placed back in the bin. The results are recorded after 10 trials, 50 trials, and 200 trials. The results are recorded in the table.Outcome| Number of trials
| 10__50___200
Red | 5___36___152
Purple | 5___14___48

Based on the table, how many times can you expect that a purple ball will be selected in 400 tries?

Answers

In total, we have 5+14+48=67 purple balls in 10+50+200=260 trials, so based on our data, purple balls appear with probability 67/260=0.258, so we expect .258*400=103 purple balls to appear in the larger sample.

Hey there

A bin contains red balls and purple balls. A ball is selected at random and then placed back in the bin. The results are recorded after 10 trials, 50trials, and 200 trials. We know that 5+14+48=67 purple balls in 260 trials. , Purple balls appear with probability 67/260 . Now we multiply and get 258*400=103

PLSSSSSSSSSSSSSSSSSS IM TIMED What is the product of StartFraction 7 Over 9 EndFraction and One-fourth?StartFraction 7 Over 36 EndFraction
StartFraction 8 Over 36 EndFraction
StartFraction 7 Over 13 EndFraction
StartFraction 8 Over 13 EndFraction