Which layer of the Epidermis contains flat dead cells filled with keratin and surrounded by lipids? (a) Stratum Spinosum (b) Stratum Squamosum (c) Stratum Lipidosum (d) Stratum Corneum

Answers

Answer 1
Answer:

D. Stratum Corneum

The layer of the epidermis that contains flat, dead cells filled with keratin and surrounded by lipids is (d) Stratum Corneum. This layer is the outermost layer of the epidermis and serves as a protective barrier for the skin, preventing the loss of water and protecting against external pathogens and environmental factors. The accumulation of keratin and lipids in the stratum corneum gives it its characteristic properties.


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A sample of gas isolated from unrefined petroleum contains 90.0% CH4, 8.9% C2H6, and 1.1% C3H8 at a total pressure of 307.2 kPa. What is the partial pressure of each component of this gas?

Answers

The partial pressure of each component of the gas are:

1. The partial pressure of CH₄ is 276.48 KPa

2. The partial pressure of C₂H₆ is 27.34 KPa

3. The partial pressure of C₃H₈ is 3.38 KPa

We'll begin by calculating the mole fraction of each gas.

For CH₄:

Percentage of CH₄ = 90%

Total = 100%

Mole fraction CH₄ =?

Mole fraction = mole / total

Mole fraction CH₄ = 90 / 100

Mole fraction CH₄ = 0.9

For C₂H₆:

Percentage of C₂H₆ = 8.9%

Total = 100%

Mole fraction C₂H₆ =?

Mole fraction = mole / total

Mole fraction C₂H₆ = 8.9 / 100

Mole fraction C₂H₆ = 0.089

For C₃H₈:

Percentage of C₃H₈ = 1.1%

Total = 100%

Mole fraction C₃H₈ =?

Mole fraction = mole / total

Mole fraction C₃H₈ = 1.1 / 100

Mole fraction C₃H₈ = 0.011

Finally, we shall determine the partial pressure of each gas. This can be obtained as follow:

1. Determination of the partial pressure of CH₄

Mole fraction CH₄ = 0.9

Total pressure = 307.2 KPa

Partial pressure of CH₄ =?

Partial pressure = mole fraction × Total pressure

Partial pressure of CH₄ = 0.9 × 307.2

Partial pressure of CH₄ = 276.48 KPa

2. Determination of the partial pressure of C₂H₆

Mole fraction C₂H₆ = 0.089

Total pressure = 307.2 KPa

Partial pressure of C₂H₆ =?

Partial pressure = mole fraction × Total pressure

Partial pressure of C₂H₆ = 0.089 × 307.2

Partial pressure of C₂H₆ = 27.34 KPa

3. Determination of the partial pressure of C₃H₈

Mole fraction C₃H₈ = 0.011

Total pressure = 307.2 KPa

Partial pressure of C₃H₈ =?

Partial pressure = mole fraction × Total pressure

Partial pressure of C₃H₈ = 0.011 × 307.2

Partial pressure of C₃H₈ = 3.38 KPa

Learn more: brainly.com/question/15754440

Answer:

276.48 atm → CH₄

27.3 atm → C₂H₆

3.38 atm → C₃H₈

Explanation:

Percentages of each gas, are the mole fraction

0.9 CH₄

0.089 C₂H₆

0.011 C₃H₈

Mole fraction = Partial pressure each gas/ Total pressure

0.9 = Partial pressure CH₄ / 307.2 kPa

307.2 kPa . 0.9 = 276.48 atm

0.089 = Partial pressure C₂H₆ / 307.2 kPa

307.2 kPa . 0.089 = 27.3 atm

0.011 = Partial pressure C₃H₈ / 307.2 kPa

307.2 kPa . 0.011 = 3.38 atm

How many atoms of carbon are in 24 grams of carbon?a) 1.2 x 10²⁴ atoms
b) 1.7 x 10²⁶ atoms
c) 1.2 x 10²⁵ atoms
d) 3.0 x 10²⁴ atoms
e) 3.0 x 10²³ atoms

Can anyone explain this one?

Answers

(3 grams of carbon) x (1 mole of carbon/12 grams ) =3/12 = 1/4 of a mole of carbon. Then... ( 1/4 of a mole) x (6.02 x 10^23 atoms/mole) = approximately 1.5 x 10^23 atoms.

A fossilized animal that was killed by a volcanic eruption has 6.25 percent of its original amount of carbon-14 remaining; this radioisotope has a half-life of 5730 years. How long ago did the volcano erupt?a) 34,380 years agob) 22,920 years agoc) 17,190 years agod) 9,168 years ago

Answers

With the assumption that the animal is 100kg the remaining mass is 6.25. (assumption of mass will not matter since the decrease in mass is in percentage.) 

To answer this we use the formula A=Aoe^-(ln2/t1/2)t
where 
A- final amount (6.25kg)
Ao - initial amount (100kg)
t1/2 - half life (5730)
t - time it takes to change A to Ao

plugging in the values 
t= 22920 years ago. 

Which hand is negatively charged? Ο Α. OB. Oc. OD. ​

Answers

Answer:

it would be OA that is negatively charged

Which balanced equation represents an endothermic reaction?(1) C(s) + O2(g) → CO2(g)
(2) CH4(g) + 2O2(g) → CO2(g) + 2H2O(l)
(3) N2(g) + 3H2(g) → 2NH3(g)
(4) N2(g) + O2(g) → 2NO(g)

Answers

Answer:

4)  N2(g) + O2(g) → 2NO(g)

Explanation:

In a chemical equation, the location of the word "heat" can be used to quickly determine whether the reaction is endothermic or exothermic. If heat is released as a product of the reaction, the reaction is exothermic. If heat is listed on the side of the reactants, the reaction is endothermic.

However in the options given, heat was not mentioned. this means we would have to undergo elimination process.

Option 2 represents combustion of methane, heat is a natural by product of any combustion reaction. hence, the correct answer cannot be 2.

Option 1 - The C=O bonds in CO2 have a high bond energy (the energy you would need to break them) which is more than either of the C-C or O=O bonds in the elements and their sum. Thus to create C and O2 from CO2 you would have to put in energy to break the two C=O bonds. You would get some back from the C-C and O=O bonds but less. Thus you need to add a lot of energy to convert CO2 into its elements. (You can decompose it at high temperatures.)

The reverse process gives off heat. So again, the correct answer cannot be 1.

Option 3 - The heat of formation of H2 ( g ) and N2( gas) under the standard condition is zero ( 0), and heat of formation of NH3 ( g ) is -46.11 kj / mol, so for the formation of 2 moles of NH3( g ) it would be - 92.22 kj,

The -ve symbol is indicative of the above reaction is exothermic in nature. So again, the correct answer cannot be 3.

Our only option left is 4 - The standard enthalpy of formation of nitric oxide (NO) in the gas phase is about +90 kJ/mol, which is endothermic. The primary reason for this is that the nitrogen-nitrogen triple bond is very strong (941 kJ/mol). The energy cost to break that bond as well as the oxygen-oxygen double bond (495 kJ/mol) is not compensated by the forming of the nitrogen-oxygen double bond (607 kJ/mol). Endothermic reactions are the result of breaking strong bonds and forming weaker ones.

N2 (g) + O2 (g) ---» 2NO (g) represents an exothermic reaction.

HELP!!!! I HAVE 2 MINUTES!!!A substance placed into an open plastic container at room temperature exerts a force against the bottom of the container but not the sides of the container. What is the most likely phase of this substance?
A. gas
B. solid
C. liquid
D. plasma

Answers

Answer:

a solid

Explanation:

because because gas would excerpt forced throughout the whole container and plasma would be too hot for the plastic container and liquid would flow throughout the container touching the sides and solid is the only one that would probably only touch the bottom of the plastic container exerting force through there