The amount that remains after one quantity is subtracted from another

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100 points please hurryFind the expression for -
HELP ASAP!!! BRAINLIEST!
A Middle Eastern restaurant recorded the number of times 2 dinner appetizers, hummus and baba ghanoush, were ordered every day for 1 month. The restaurant calculated the mean number of times each appetizer was ordered and the MAD (mean absolute deviation) for each appetizer. | Appetizer | Orders sold | Mean | MAD --------------------------- Hummus 24.3 | 3.1 Baba ghanoush 11.5 | 2.9 Which statement best describes the overlap in the distribution of the two data sets? A. The overlap is high because both means are greater than either MAD. B. The overlap is high because the sum of the means is large compared to the MAD. C. The overlap is low because the difference in the MADs is small. D. The overlap is low because the difference in the means is large compared to either MAD.
Which are all the solutions of 5sinθ-4=2sinθ-4, where 0≤θ≤2π
If 28% of a sum is $100.80, what is the sum?

I need help on 1-8 ..

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Answer:

To begin this problem we call "the sum of the number" x. Now we have the equation 2(x)+5=20. This is the answer because it said to translate the equation. I think 2x+5+20 would be the correct translation.

What is two x one half

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2*1/2=1 because half or 2 is 1

$2* (1)/(2) = \frac {2}{2}=1$

Simplify 4 + (−3) − 2 × (−6)

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Keywords:

Simplify, expression, order of operation, PEMDAS

For this case we must simplify the given expression, we must take into account the order of operation (sequence in which operations must be performed) known as PEMDAS:

P: Parentesis

E: Exponents

M: Multiplication

D: Division:

A: Addition

S: Subtraction

In the given expression, we see that we have multiplication and addition, according to the PEMDAS rule, we must first do the multiplication:

So:

$4 + (-3) - 2 * (-6) =$

We multiply, taking into account that: $- * - = +$

$4 + (- 3) + 12 =$

We add similar terms:

$12+4-3=$

$16-3 =$

Different signs are subtracted and the sign of the major is placed:

$4 + (-3) - 2 * (-6) = 13$

Answer:

By simplifying $4 + (-3) - 2 * (-6)$ we get 13 as a result.

2.-6=-12
4+(-3)-(-12)
13
Good Luck

P(A)=0.4 and P(B)=0.6. What is the probability of observing event B three times in a row? Question 10 options:

0.240

0.360

0.064

0.216

Answers

Answer:

0.216

Step-by-step explanation:

Probability is the ratio of the number of possible outcome to the number of total outcome.

The probability that an event will happen added to the probability that the event will not happen gives 1. In other words, the outcome of a probability cannot exceed 1.

The probability that an event a will happen or that another independent event b will happen is the sum of the probability that a will happen to the probability that b will happen.

The probability that the event B will occur 3 times in a row may be interpreted as BBB and in probability, "and" is interpreted as multiplication while "or" is addition.

Pr(BBB)

= 0.6 * 0.6 * 0.6

= 0.216

Prove that: (a2 - b2)3 + (b2-c2)3+ (c2-a2)3 = 3 (a+b) (b+c) (c+a) (a-b) (b-c) (c-a).

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$L=(a^2-b^2)^3+(b^2-c^2)^3+(c^2-a^2)^3=(*)\n\n(a^2-b^2)^3=a^6-3a^4b^2+3a^2b^4-b^6\n\n(b^2-c^2)^3=b^6-3b^4c^2+3b^3c^4-c^6\n\n(c^2-a^2)^3=c^6-3c^4a^2+3c^2a^4-a^6\n\n(*)=a^6-3a^4b^2+3a^2b^4-b^6+b^6-3b^4c^2+3b^2c^4-c^6+c^6-\dots\n\dots-3c^4a^2+3c^2a^4-a^6\n\n=-3a^4b^2+3a^2b^4-3b^4c^2+3b^2c^4-3c^4a^2+3c^2a^4\n\n=3(-a^4b^2+a^2b^4-b^4c^2+b^2c^4-a^2c^4+a^4c^2)$

$R=3(a+b)(a-b)(b+c)(b-c)(c+a)(c-a)\n\n=3(a^2-b^2)(b^2-c^2)(c^2-a^2)\n\n=3(a^2b^2-a^2c^2-b^4+b^2c^2)(c^2-a^2)\n\n=3(a^2b^2c^2-a^4b^2-a^2c^4+a^4c^2-b^4c^2+a^2b^4+b^2c^4-a^2b^2c^2)\n\n=3(-a^4b^2+a^2b^4-b^4c^2+b^2c^4-a^2c^4+a^4c^2)\n\nL=R$

$(a^2 - b^2)^3 + (b^2 - c^2)3 + (c^2 - a^2)^3 = 3(a + b)(b +c)(c + a)(a - b)(b - c)(c - a)$
$(a^2 - b^2)^3 + (b^2 - c^2)3 + (c^2 - a^2)^3 = 3(a + b)(a - b)(b + c)(b - c)(c + a)(c - a)$
$(a^2 - b^2)^3 + (b^2 - c^2)3 + (c^2 - a^2)^3 = 3(a^2 - b^2)(b^2 - c^2)(c^2 - a^2)$

$(a^2 - b^2)^3 = (a^2 - b2)(a^2 - b^2)(a^2-b^2) = a^6 - 3a^4b^2 + 3a^2b^4 - b^6$
$(b^2 - c^2)^3 = (b^2 - c^2)(b^2 - c^2)(b^2 - c^2) = b^6 - 3^4c^2 + 3b^2c^4 - c^6)$
$(c^2 - a^2)^3 = (c^2 - a^2)(c^2 - a^2)(c^2 - a^2) = c^6 - 3a^2c^4 + 3a^4c^2 - a^6$

$a^6 - 3a^4b^2 + 3a^2b^4 - b^6 + b^6 - 3b^4c^2 + 3b^2c^4 - c^6 + c^6 - 3a^2c^4 + 3a^4c^2 - a^6$
$-3a^4b^2 + 3a^2b^4 - 3b^4c^2 + 3b^2c^4 - 3a^2c^4 + 3a^4c^2$
$3(-a^4b^2 + a^2b^4 - b^4c^2 + b2^c^4 - a^2c^4 + a^4c^2)$

$3(a^2 - b^2)(b^2 - c^2)(c^2 - a^2) = 3(-a^4b^2 + a^2b^4 - b^4c^2 + b^2c^4 - a^2c^4 + a^4c^2)$

$3(-a^4b^2 + a^2b^4 - b^4c^2 + b^2c^4 - a^2c^4 + a^4c^2) = 3(-a^4b^2 + a^2b^4 - b^4c^2 + b^2c^4 - a^2c^4 + a^4c^2$

I really need help on all of them, I will give out brainliest to one answer and ten points to both

Answers

Answer:

1. 1/2, 2. 2, 3. 1/-3, 4. -2

Step-by-step explanation:

1) I know that the equation for slope is y2-y1/x2-x1. For number one I first found two points of the graph which is (0,3) and (2,4) (not sure if I see it correctly, its kind of blurry). I decided that (0,3) would be my y1 and x1 and (2,4) will be my y2 and x2. I later plugged the number in the equation and got 4-3/2-0 which the answer turns out to be 1/2.

2) For the rest of the questions it is kinda the same business as question 1. For question two I chose two points out of the table which wrer (-1, -12) and (1,-8) and plugged them into the equation and got -8-(-12)/1-(-1) which the answer turns out to be 2.

3) similar to question 2. The two points(2,-6) and (-4,-3) are given to you. so I plugged them in again and got -3-(-6)/-4-2 which the answer turns out to be 3/-6 into 1/-3.

4) Same with question 1 find two points of the graph. I chose (0,3) and (1,1) (again might not be accurate it's kind of blurry) I plugged them into the equation again and got 1-3/1-0 which equals -2.

Just always remember y2-y1/x2-x1=m is the equation for slope.

(m is the variable for slope)

Hoped this helped you : )

Other Questions

Can you guys help me out with number 13

Henry bought pound of roasted almonds for $5. He wants to know the price per pound. What is the price per pound?

A foreman for an injection-molding firm admits that on 55% of his shifts, he forgets to shut off the injection machine on his line. This causes the machine to overheat, increasing the probability that a defective molding will be produced during the early morning run from 3% to 15%. The plant manager randomly selects a molding from the early morning run and discovers it is defective. What is the probability that the foreman forgot to shut off the machine the previous night?

How do you solve 2/3=m/42